Penghitungan Stationing PERENCANAAN JALAN

commit to user

3.3 Penghitungan Stationing

Data – data tikungan : d A – 1 : 357,946 m d 1 – 2 : 653,911 m d 2 – 3 : 755,066 m d 3 – 4 : 512,372 m d 4 – 5 : 449,055 m d 5 – 6 : 505,594 m d 6 – 7 : 449,472 m d 7 – B : 815,552 m 1. Tikungan PI 1 S-S Ts 1 = 98,491 m Ls 1 = 88,400 m 2. Tikungan PI 2 S-C-S Tt 2 = 86,458 m Ls 2 = 43,428 m Lc 2 = 64,495 m 3. Tikungan PI 3 S-C-S Tt 3 = 98,103 m Ls 3 = 40,992 m Lc 3 = 88,843 m 4. Tikungan PI 4 S-C-S Tt 4 = 95,817 m Ls 4 = 40,992 m commit to user Lc 4 = 85,889 m 5. Tikungan PI 5 S-C-S Tt 5 = 132,477 m Ls 5 = 45,99 m Lc 5 = 93,115 m 6. Tikungan PI 6 S-C-S Tt 6 = 175,700 m Ls 6 = 43,428 m Lc 6 = 130,377 m 7. Tikungan PI 7 S-C-S Tt 7 = 120,543 m Ls 7 = 50,274 m Lc 7 = 56,781 m STA A = 0 + 000 STA PI 1 = Sta A + d A – 1 = 0 + 000 + 357,946 = 0 + 357,946 m STA TS 1 = Sta PI 1 – Ts 1 =0 + 357,946 – 98,491 = 0 + 259,455 m STA ST 1 = Sta TS 1 + 2 x Ls 1 = 0 + 259,455 + 2×88,400 = 0 + 436,255 m commit to user STA PI 2 = Sta ST 1 + d 1-2 – Ts 1 = 0 + 436,255 + 653,911 – 98,491 = 0 + 991,675 m STA TS 2 = Sta PI 2 – Tt 2 =0 + 991,675 – 86,458 = 0 + 905,217 m STA SC 2 = Sta TS 2 + Ls 2 = 0 + 905,217 + 43,428 = 0 + 948,645 m STA CS 2 = Sta SC 2 + Lc 2 = 0 + 948,645 + 64,495 = 1 + 013,140 m STA ST 2 = Sta CS 2 + Ls 2 = 1 + 013,140 + 43,428 = 1 + 056,568 m STA PI 3 = Sta ST 2 + d 2-3 – Tt 2 = 1 + 056,568 + 755,066 – 86,458 = 1 + 725,176 m STA TS 3 = Sta PI 3 – Tt 3 =1 + 725,176 – 98,103 = 1 + 627,073 m STA SC 3 = Sta TS 3 + Ls 3 = 1 + 627,073 + 40,992 = 1 + 668,065 m commit to user STA CS 3 = Sta SC 3 + Lc 3 = 1 + 668,065 + 88,483 = 1 + 756,548 m STA ST 3 = Sta CS 3 + Ls 3 = 1 + 756,548 + 40,992 = 1 + 797,540 m STA PI 4 = Sta ST 3 + d 3-4 – Tt 3 = 1 + 797,540 + 512,372 – 98,103 = 2 + 211,809 m STA TS 4 = Sta PI 4 – Tt 4 =2 + 211,809 – 95,817 = 2 + 115,992 m STA SC 4 = Sta TS 4 + Ls 4 = 2 + 115,992 + 40,992 = 2 + 156,984 m STA CS 4 = Sta SC 4 + Lc 4 = 2 + 156,984 + 85,889 = 2 + 242,873 m STA ST 4 = Sta CS 4 + Ls 4 = 2 + 242,873 + 40,992 = 2 + 283,865 m STA PI 5 = Sta ST 4 + d 4-5 – Tt 4 = 2 + 283,865 + 449,055 – 95,817 = 2 + 637,103 m commit to user STA TS 5 = Sta PI 5 – Tt 5 =2 + 637,103 – 132,477 = 2 + 504,626 m STA SC 5 = Sta TS 5 + Ls 5 = 2 + 504,626 + 45,99 = 2 + 550,616 m STA CS 5 = Sta SC 5 + Lc 5 = 2 + 550,616 + 93,115 = 2 + 643,731 m STA ST 5 = Sta CS 5 + Ls 5 = 2 + 643,731 + 45,99 = 2 + 689,721 m STA PI 6 = Sta ST 5 + d 5-6 – Tt 5 = 2 + 689,721 + 505,594 – 132,477 = 3 + 062,838 m STA TS 6 = Sta PI 6 – Tt 6 =3 + 062,838 – 175,700 = 2 + 887,138 m STA SC 6 = Sta TS 6 + Ls 6 = 2 + 887,138 + 43,428 = 2 + 930,566 m STA CS 6 = Sta SC 6 + Lc 6 = 2 + 930,566 + 130,377 = 3 + 060,943 m commit to user STA ST 6 = Sta CS 6 + Ls 6 = 3 + 060,943 + 43,428 = 3 + 104,371 m STA PI 7 = Sta ST 6 + d 6-7 – Tt 6 = 3 + 104,371 + 449,472 – 175,700 = 3 + 378,143 m STA TS 7 = Sta PI 7 – Tt 7 =3 + 378,143 – 120,543 = 3 + 257,600 m STA SC 7 = Sta TS 7 + Ls 7 = 3 + 257,600 + 50,274 = 3 + 307,874 m STA CS 7 = Sta SC 7 + Lc 7 = 3 + 307,874 + 56,781 = 3 + 364,655 m STA ST 7 = Sta CS 7 + Ls 7 = 3 + 364,655 + 50,274 = 3 + 414,929 m STA B = Sta ST 7 + d 7-B – Tt 7 = 3 + 414,929 + 815,552 – 120,543 = 4 + 109,938 m commit to user

3.3 Kontrol Overlaping