Soal Matematika SMA Ulangan Harian Limit

  Ulangan Harian Limit

  Lim

  3 x

  Lim

  2 x tgx 

  2 

  1. x = …… 4. = ……

   3 x  x 

  x

  1  cos x

  2 x  10 x 

  75 Lim   4 x

  2 Lim x 

  5 

  x

  5 2. = …… 5. = ……

   x

  x

  3 Lim

  2 t 

  1 Lim 3 x  2  9 x  2 x 

  5 

  2 x 

   t t

  3. t 1  

  2 = …… 6.

  Lim

    

  Lim ( x

  3 ) ( x

3 ) sin (

  2 2 x )

   7. = …… 9.

  

  2

  x

  2

  

  x

  3

  3  x

   x

  2 x  6  x 1 

  Lim Lim

  4   

     3 x 2 2 x

  2 

  x

  6

  

  8. = …… 10. x

  2

  x 

  2  x 

  4 x 6  

  ( soal Ebtanas tahun 2005 / 2006 SMA IPA ) .

Jawab

  _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________

  Ulangan Harian Limit

  2 x x 2 

  6 Lim

  Lim

  sin 1  2 x x

  4 

  1. x = …… 4. = ……

  

  2 

  x

  1  sin 2 x

  4

  2 x  x 

  12

  2 Lim x

  Lim

  x 

  3 

  2. x -3 = …… 5.

  2 = …… 

  x

  1  1  x

  3 Lim

  2

  2 t 

  8 Lim x  4 x  5  x  6 x 

  3 

  2 x 

   t t

  3. t 2  

  6 = …… 6.  x

  1 Lim

  7.  = ……

  1 x 

  t

  1

  2 4  x

  Lim

  2 

  8. x 2 = ……( soal Ebtanas tahun 1997 / 1998 SMA IPA )

  3  x 

  5 .

  Lim

  1  cos( x  2 ) 

  9. x -2

  2 = …… ( soal Ebtanas tahun 1997 / 1998 SMA IPA ) x  4 x 

  4

  2

  3 

  Lim

  2

  2 x  4 x  2 x 

  8 

  10. x 2 = …… ( soal Ebtanas tahun 1998 / 1999 SMA IPA ) .

  .

Jawab

  _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________

  lUlangan Harian Limith l

  Lim

  2

  2 x  x  x  x

  

  4. x = ……

  

  Lim

  2

  2 x  x  5  x  2 x 

  3 

  5. x = ……

  

  Lim

  5 x  1  3 x 

  7 

  3. x  =  ( soal Ebtanas tahun 1996 / 1997 SMA IPA ) .

  Lim

  2 4  x

  

  4. x 2 = ……( soal Ebtanas tahun 1997 / 1998 SMA IPA )

  2 3  x 

  5 .

  1  cos( x  2 )

  Lim

  2 

  5. x -2 x 

  4 x  4 = …… ( soal Ebtanas tahun 1997 / 1998 SMA IPA )

  Lim

  2

  3  

  6. x 2 = …… ( soal Ebtanas tahun 1998 / 1999 SMA IPA )

  2

  2 x  4 x  2 x 

  8 .

  . Jawab _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________

  = …… .

  2  

  2

  1

  ( 2 x cos

  4 x 12 x 3 )

  2

  

  Lim x

  

  2 1 x 2  

  4

   ₂ ^{1 } 6 x

  Lim x

   

  6

  . = …… .

  1 4 x x

  2 x

  2

  

  Lim x

  

  2   

  2

  2

  

8 x

2 x 3 4 x

  2

  

  . Lim x

  . 4. = …… .

  2    

  .

  

  2 1 x 2  

  4

   ₂ ^{1 } 6 x

  Lim x

   

  2  

  6

  1 4 x x

  2 x

  2

  Lim x

  = …… .

  

  2   

  2

  2

  

8 x

2 x 3 4 x

  2

  

  Lim x

  . 4. = …… .

  . = …… .

  

  .

  2 1  cos ( x  2 )

  Lim

  2  3 x  12 x 

  4

  x

  2 6. = …… .