T
e
=
=
– –
= = 1,36 Nm
Beban 325 W
P
cu
= P
in
– P
ts
– P
i
Watt = 250 – 26,76 – 1,45
= 221,79 Watt P
tr
= 3. I
2 2
. R
2
Watt = 3. 1,47
2
. 3,456 = 22,4 Watt
T
e
=
=
– –
= = 1,71 Nm
b. R
2
= 5,456 Ω
Beban 125 W
P
cu
= P
in
– P
ts
– P
i
Watt = 150 – 26,76 – 1,45
= 121,79 Watt P
tr
= 3. I
2 2
. R
2
Watt = 3. 0,5
2
. 5,456
= 4,1 Watt T
e
=
=
– –
= = 0,89 Nm
Beban 200 W
P
cu
= P
in
– P
ts
– P
i
Watt = 200 – 26,76 – 1,45
= 171,79 Watt P
tr
= 3. I
2 2
. R
2
Watt = 3. 1,11
2
. 5,456 = 20,16 Watt
T
e
=
=
– –
= = 1,17 Nm
Beban 325 W
P
cu
= P
in
– P
ts
– P
i
Watt = 250 – 26,76 – 1,45
= 221,79 Watt P
tr
= 3. I
2 2
. R
2
Watt = 3. 1,5
2
. 5,456 = 36,82 Watt
T
e
=
=
– –
= = 1,47 Nm
b. R
2
= 7,456 Ω
Beban 125 W
P
cu
= P
in
– P
ts
– P
i
Watt = 130 – 26,76 – 1,45
=101,79 Watt P
tr
= 3. I
2 2
. R
2
Watt = 3. 0,71
2
. 7,456 = 11,27 Watt
T
e
=
=
– –
= = 0,78 Nm
Beban 200 W
P
cu
= P
in
– P
ts
– P
i
Watt = 150 – 26,76 – 1,45
= 121,79 Watt P
tr
= 3. I
2 2
. R
2
Watt = 3. 1,01
2
. 7,456 = 22,81 Watt
T
e
=
=
– –
= = 0,926 Nm
Beban 325 W
P
cu
= P
in
– P
ts
– P
i
Watt = 200 – 26,76 – 1,45
= 171,79 Watt P
tr
= 3. I
2 2
. R
2
Watt = 3. 1,27
2
. 7,456 = 36,07 Watt
T
e
=
=
– –
= = 1,29 Nm
- Efisiensi
Dari percobaan kita memperoleh data – daya yang diperlukan untuk memperhitungkan efisiensi motor induksi tiga phasa yaitu.
Tabel 4.6 Data Hasil Pengujian Motor Induksi Dengan Besar Tahanan Rotor yang
Berbeda
R
1
= 1,86 Ω
Tahanan Rotor
Ω Beban
Generator Dc Watt
I
2
A I
s
P
in
KW 3,456
125 0,6
2,19 0,18
200 1,05
2,21 0,2
325 1,47
2,25 0,25
5,456
125 0,5
1,97 0,15
300 1,11
1,84 0,2
325 1,5
1,97 0,25
7,456
125 0,71
1,81 0,13
300 1,01
1,83 0,15
325 1,27
1,84 0,2
a. R
2
= 3,456 Ω
Beban 125 W
loss
P
= P
ts+
P
i
+ P
tr
- Rugi – rugi tembaga stator P
ts
P
ts
= 3. I
1 2
. R
1
Watt = 3. 2,19
2
. 1,86 = 26,76 Watt
- Rugi – rugi inti stator P
i
P
i
= 1,45 Watt - Rugi – rugi tembaga rotor P
tr
P
tr
= 3. I
2 2
. R
2
Watt = 3. 0,6
2
. 3,456 = 3,74 Watt
η
= x100 =
x 100
= x 100
= 82,25
Beban 200 W
loss
P
= P
ts+
P
i
+ P
tr
- Rugi – rugi tembaga stator P
ts
P
ts
= 3. I
1 2
. R
1
Watt = 3. 2,21
2
. 1,86 = 27,25 Watt
- Rugi – rugi inti stator P
i
P
i
= 1,45 Watt -
Rugi – rugi tembaga rotor P
tr
P
tr
= 3. I
2 2
. R
2
Watt = 3. 1,05
2
. 3,456 = 11,4 Watt
η
= x100 =
x 100
= x 100
= 79,95
Beban 325 W
loss
P
= P
ts+
P
i
+ P
tr
- Rugi – rugi tembaga stator P