The Data of Controlled Class

According to the table above, the table frequency distribution which is presented as follow: Table 4.8 F r e q u e n c y D i stribution of Pre-test Result of Controlled Class The table above is a tool of presentation consisting of columns and rows and there numbers which describe the division and percentage of frequency distribution. It also can be described by diagram as follow: Score Frequency Percent Valid Percent Cumulative Percent Valid 50 1 3,3 3,3 3,3 55 3 10,0 10,0 13,3 60 7 23,3 23,3 36,7 65 7 23,3 23,3 60,0 70 6 20,0 20,0 80,0 75 4 13,3 13,3 93,3 80 2 6,7 6,7 100,0 Total 30 100,0 100,0 Diagram 4.3 The result achieved from the post-test in controlled class of this research are presented in table below: Table 4.9 Data Description of Post-test of Controlled Class Statistics Class Score N Valid 30 30 Missing Mean 2,00 71,00 Median 2,00 70,00 Mode 2 65 Std. Deviation ,000 7,120 Variance ,000 50,690 Minimum 2 60 Maximum 2 85 Sum 60 2130 Percentiles 25 2,00 65,00 50 2,00 70,00 75 2,00 75,00 The table 4.9 shows that the mean of the 30 students is 71. The median score from the table is 70. The mode score is 65. The set of the score constitute a population determine as variance score is 50.690. Standard deviation is a quantity calculated to indicate the extent of deviation for a group as a whole and it is 7.1206. Then the sum gained from the total score is 2130. The table of frequency distribution which reached based on the table above is presented as follow: Table 4.10 Frequency Distribution of Post-test Result of Controlled Class T h e table above is a tool of presentation consisting of columns and rows and there numbers which describe the division and percentage of frequency distribution. It can be described by diagram as follow: Score Frequency Percent Valid Percent Cumulative Percent Valid 60 3 10,0 10,0 10,0 65 8 26,7 26,7 36,7 70 7 23,3 23,3 60,0 75 6 20,0 20,0 80,0 80 4 13,3 13,3 93,3 85 2 6,7 6,7 100,0 Total 30 100,0 100,0 Diagram 4.4 B. Data Analysis 1. Normality test a Pre-test Normality test The normality test in this research use Saphiro Wilk because the participant 50. The data was analysed by using SPSS v.22 for windows with the criteria 0.05. The result of normality test of the data are presented as follow: Table 4.11 Normality Pre-test between Experimental and Controlled Class Tests of Normality Class Kolmogorov-Smirnov a Shapiro-Wilk Statistic df Sig. Statistic df Sig. Score experimental class ,145 30 ,108 ,953 30 ,207 controlled class ,138 30 ,150 ,958 30 ,270 a. Lilliefors Significance Correction From the table 4.11 above, it can be seen that the significance of the normality pre-test score in experimental class is 0.207. It can be calculated that the data are normally distributed because 0.207 0.05. Then, the significance of pre-test score in controlled class is 0.270. Therefore, the data are normally distributed because 0.270 0.05. So the writer can conclude that the result in both of experimental and controlled class are normally distributed. b Post-test Normality test The normality in this test used Saphiro Wilk. The data was analysed by using SPSS v.22 for windows. Then the result of normality test of the data are presented as follow: Table 4.12 Normality Post-test result Between Experimental and Controlled Class From the table 4.12 above, shows that the significance of the normality post-test score in experimental class is 0.175. It means that the data are normally distributed because 0.207 0.05. Moreover, the significance of post-test score in controlled class is 0.057. By meaning the data are normally distributed because 0.057 0.05. Then the writer conclude that the result in both of experimental and controlled class are normally distributed. Tests of Normality Class Kolmogorov-Smirnov a Shapiro-Wilk Statistic df Sig. Statistic df Sig. Score experimental class ,132 30 ,195 ,951 30 ,175 controlled class ,167 30 ,032 ,933 30 ,057 a. Lilliefors Significance Correction

2. Homogeneity test

a Pre-test Homogeneity test Based on calculation of the normality test, the write reached to the point that all data in pre-test and post-test both of experimental class and controlled class had been normally distributed. The next step is the calculation to find the pre-test and post-test homogeneity of the data by using SPSS v.22 for windows. The result of pre-test homogeneity test of the data is presented as follow: Table 4.13 Homogeneity Pre-test between Experimental and Controlled Class The table 4.13 above shows that the significance of pre-test homogeneity result between experimental and controlled class is 0.072. Thus, it can be concluded that the data of pre-test is homogeneous because 0.072 0.05. b Post-test Homogeneity test The data of post-test homogeneity test was analysed by using SPSS v.22 for windows and the result is as follow: Table 4.14 Homogeneity Post-test between Experimental and Controlled Class Test of Homogeneity of Variances Score Levene Statistic df1 df2 Sig. 3,354 1 58 ,072 Test of Homogeneity of Variances Score Levene Statistic df1 df2 Sig. 1,207 1 58 ,276 According to the table above shows that the significance of post- test between experimental and controlled class is 0.276. Therefore, is can be concluded that the data of post-test is homogeneous because 0.276 0.05. So, it shows both of groups are homogenous.

3. Hypothesis test

The next calculation was testing the hypothesis. The data was analysed by using t-test formula. This technique is useful to prove statistically whether there is a significant influence between using realia and pictures in experimental and controlled class. The experimental class was X variable and the controlled class was Y variable. Before analysing the data, the following table is statistical calculation of the gained score from both of experimental class using realia and pictures and controlled class without using realia and pictures. Table 4.15 The Statistical Calculation of the Gained score of both Experimental and Controlled Class No X Y X2 Y2 1 20 10 400 100 2 15 5 225 25 3 15 -5 225 25 4 15 -5 225 25 5 10 5 100 25 6 10 5 100 25 7 5 10 25 100 8 5 25 9 10 5 10 25 10 -5 5 25 25 11 15 5 225 25 12 20 5 400 25 13 14 5 10 25 100 15 5 5 25 25 16 5 5 25 25 17 10 5 100 25 18 10 10 100 100 19 20 400 20 15 225 21 10 15 100 225 22 5 5 25 25 23 5 10 25 100 24 10 5 100 25 25 5 5 25 25 26 15 10 225 100 27 10 5 100 25 28 10 10 100 100 29 5 5 25 25 30 25 -5 625 25 � 300 150 4210 1400 From the table above, the writer calculated the data based on the step of t-test formula. The calculation can be seen as follow; 1. Determining Mean of Variable X 2. Determining Mean of Variable Y 3. Determining Standard of Deviation Score of Variable X √ √ = 11.84 4. Determining Standard of Deviation Score of Variable Y √ √ = 6.83 5. Determining Standard Error of Mean of Variable X √ √ √ 6. Determining Standard Error of Mean of Variable Y √ √ √

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