commit to user
Perencanaan St rukt ur Gedung Sekolah 2 L ant ai
xxxvi
xxxvi Dipakai tulangan
∅ 10 – 130 mm
5.6. Penulangan tumpuan arah y
Mu = 882,21 kgm = 8,8221.10
6
Nmm Mn =
φ Mu
=
6 6
10 .
0276 ,
11 8
, 10
. 8221
, 8
= Nmm
Rn =
=
2
.dy b
Mn 526
, 1
85 .
1000 10
. 0276
, 11
2 6
= Nmm
2
m = 412
, 9
30 .
85 ,
240 .
85 ,
= =
c f
fy
ρ
perlu
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− fy
Rn .
m 2
1 1
. m
1
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− 240
526 ,
1 .
412 ,
9 .
2 1
1 .
412 ,
9 1
= 0,006561 ρ
ρ
max
ρ ρ
min
, di pakai ρ
perlu
= 0,006561 As
perlu
= ρ
perlu
. b . d = 0,006561 . 1000 . 85
= 557,685 mm
2
Digunakan tulangan ∅ 10
As = ¼ . π . 10
2
= 78,5
mm
2
S =
perlu
As b
As. =
685 ,
557 1000
. 5
, 78
= 140,76 ~ 130 mm
n = s
b
commit to user
Perencanaan St rukt ur Gedung Sekolah 2 L ant ai
xxxvii
xxxvii =
100 1000
= 10
As yang timbul = 10. ¼ . π . 10
2
= 785
mm
2
As
perlu
…ok Dipakai tulangan
∅ 10 – 130 mm
5.7. Penulangan lapangan arah x
Mu = 453,02 kgm = 4,5302.10
6
Nmm Mn =
φ Mu
=
6 6
10 .
663 ,
5 8
, 10
. 5302
, 4
= Nmm
Rn =
=
2
.dx b
Mn =
2 6
95 .
1000 10
. 663
, 5
0,627 Nmm
2
m = 412
, 9
30 .
85 ,
240 .
85 ,
= =
c f
fy
ρ
perlu
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− fy
Rn .
m 2
1 1
. m
1
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− 240
627 ,
. 412
, 9
. 2
1 1
. 412
, 9
1 =
0,002646 ρ ρ
max
ρ ρ
min
, di pakai ρ
perlu
= 0,002646 As =
ρ
perlu
. b . dx = 0,002646. 1000 . 95
= 251,328
mm
2
Digunakan tulangan ∅ 10
As = ¼ .
π . 10
2
= 78,5
mm
2
S =
perlu
As b
As. =
328 ,
251 1000
. 5
, 78
commit to user
Perencanaan St rukt ur Gedung Sekolah 2 L ant ai
xxxviii
xxxviii = 312,34 ~ 300 mm
Jarak maksimum = 2 x h = 2 x 120
= 240
mm n =
s b
= 240
1000 =
4,2 ∼ 5
As yang timbul = 5. ¼ . π . 10
2
= 392,5
mm
2
As…ok Dipakai tulangan
∅ 10 – 240 mm
5.8. Penulangan lapangan arah y
Mu = 333,81 kgm = 3,3381.10
6
Nmm
Mn = φ
Mu =
6 6
10 .
1726 ,
4 8
, 10
. 3381
, 3
= Nmm
Rn =
=
2
.dy b
Mn =
2 6
85 .
1000 10
. 1726
, 4
0,5775 Nmm
2
m = 412
, 9
30 .
85 ,
240 .
85 ,
= =
c f
fy
i
ρ
perlu
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− fy
Rn m
m .
. 2
1 1
. 1
= . 412
, 9
1 ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− 240
5775 ,
. 412
, 9
. 2
1 1
= 0,00243 ρ
ρ
max
ρ ρ
min
, di pakai ρ
min
= 0,0025
As = ρ
min
b . d = 0,0025 . 1000 . 85
commit to user
Perencanaan St rukt ur Gedung Sekolah 2 L ant ai
xxxix
xxxix = 212,5 mm
2
Digunakan tulangan ∅ 10
As = ¼ . π . 10
2
= 78,5
mm
2
S =
perlu
As b
As. =
5 ,
212 1000
. 5
, 78
= 369,412 ~ 350 mm Jarak maksimum = 2 x h
= 2 x 120 =
240 mm
n = s
b
= 240
1000 =
4,2 ∼ 5
As yang timbul = 5. ¼ . π . 10
2
= 392,5 mm
2
As…ok Dipakai tulangan
∅ 10 – 240 mm
5.9. Rekapitulasi Tulangan
