Sistem Biaya Taksiran PERTEMUAN XIII Dr Rilla Gantino, SE., AK., MM MM-FEB
Sistem Biaya Taksiran
PERTEMUAN XIII
Dr Rilla Gantino, SE., AK., MM
MM-FEB
KEMAMPUAN AKHIR YANG DIHARAPKAN
Mahasiswa dapat menghitung dan menginterpretasikan sistem biaya taksiran, Penentuan biaya taksiran, Perlakuan akuntansi terhadap biaya taksiran.
15-1 Lecture slides to accompany
Engineering Economy
7 th edition Leland Blank
Chapter 15
Chapter 15 CostCost
Estimation
Estimation
and Indirect
and Indirect
Costs
Costs
© 2012 by McGraw-Hill All Rights Reserved
Cost Estimation
Direct and Indirect Cost Estimates
Direct cost Indirect cost examples examples
- Physical assets
- Utilities
- Maintenance and
operating costs • IT systems and (M&O) networks
- Materials
- Purchasing
- Direct human labor
- Management
(costs and benefts)
- Taxes
- Scrapped and
- Legal functions
reworked product
- Warranty and
- Direct supervision
of personnel guarantees © 2012 by McGraw-Hill All Rights Reserved 15-3
What Direct Cost Estimation
Includes
Direct costs are more commonly estimated than revenue in an
engineering environment. Preliminary decisions required are:
What cost components should be estimated?
What approach to estimation is best to apply? How accurate should the estimates be?
What technique(s) will be applied to estimate costs? frst costs
Sample direct cost components:
and its elements (P); annual costs (AOC or M&O); salvage/market value (S) bottom-up; design-to-cost (top
Approaches:
down) feasibility stage through detailed design
Accuracy:
estimates require more exacting estimates © 2012 by McGraw-Hill All Rights Reserved
15-4
Diferent Approaches to Cost
Estimation
© 2012 by McGraw-Hill All Rights Reserved 15-5
Accuracy of Cost Estimates
General guidelines for
accuracy
Conceptual/Feasibility stage order- –
of-magnitude estimates are in range of
±20% of actual costs Detailed design stage Detailed - estimates are in range of ±5% of actual costsCharacteristic curve of accuracy vs. time to make estimates © 2012 by McGraw-Hill All Rights Reserved
15-6
Unit Method
preliminary design stage estimates
- Commonly used technique for
• Total cost estimate C is per unit cost (u) times number of units
T
(N)
C = u × N
T- Example uses: T<
- Cost to operate a car at 60¢/mile for 500 miles: C = 0.60 × 500 = $300 2 2 Cost to build a 250 m house at $2250/m : C T = 2250 × 250 = $562,50
- Cost factors must be updated periodically to remain
timely When several components are involved, estimate cost of each component and add to
determine total cost estimate C
T© 2012 by McGraw-Hill All Rights Reserved 15-7
Cost Indexes
Defnition: Cost Index is ratio of cost today
to cost in the past over time ; therefore,- Indicates change in cost they account for the impact of infation
- Index is dimensionless
- CPI (Consumer Price Index) is a good example
© 2012 by McGraw-Hill All Rights Reserved
15-8
Example: Cost Index Method Problem: Estimate the total cost of labor today in US dollars for a maritime construction project using data from a similar project in Europe completed in 1998
Labor index, 1998: 789.6 Cost in 1998: €3.9 million
Labor index, current: 1165.8 Currently, 1 € = 1.5
US$ Solution: Let t = today and 0 = 1998 baseC = 3.9 million × (1165.8/789.6) = €5.76
t million = €5.76 × 1.5 = $8.64 million © 2012 by McGraw-Hill All Rights Reserved
15-9
Why Estimate Costs?
Managers make decisions and need to compare costs and benefits among alternative actions.
Cost estimates can be an important element In helping managers make decisions. Basic Cost Behavior Patterns LO 5-1 Understand the reasons for estimating fixed and variable costs.
Costs Fixed costs
Variable costs
Total fixed costs do not change proportionately as activity changes.
Per unit fixed costs change inversely as activity changes.
Total variable costs change proportionately as activity changes.
Per unit variable cost remain constant as activity changes. LO 5-1
5-1 LO
Methods Used to Estimate Cost Behavior
Charlene, owner of Charlene’s Computer Care
(3C), wants to estimate the cost of a
new computer repair center.
1. Engineering estimates
2. Account analysis
3. Statistical methods
5-2 LO
Engineering Estimates Estimate costs using engineering estimates.
Cost estimates are based on measuring and then pricing the work involved in a task.
Identify the activities involved:
- – Labor – Rent – Insurance Estimate the time and cost for each activity.
5-2 LO
Engineering Estimates
Details each step required to perform an operation Permits comparison of other centers with similar operations Costs for totally new activities can be estimated without prior activity data.
Can be quite expensive to use Based on optimal conditions
Account Analysis LO 5-3 Estimate costs using account analysis.
Review each account comprising the total cost being analyzed.
Identify each cost as either fixed or variable.
Fixed Variable LO 5-3
Account Analysis
Costs for 360 repair-hours Office rent Utilities Administration Supplies Training Other Total Per repair hour
$ 3,375 310 3,386 2,276 666 613 $10,626
$1,375 100 186 2,176 316 257 $4,410 $12.25
$2,000 210 3,200 100 350 356 $6,216
Account Total Variable cost Fixed cost LO 5-3
Account Analysis
Fixed costs + (Variable cost/unit × No. of units) = Total cost Cost at 360 repair-hours:
$6,216 + ($12.25 × 360) = $10,626 Cost at 480 repair-hours:
$6,216 + ($12.25 × 480) = $12,096 LO 5-3
Account Analysis
Managers and accountants are familiar with company operations and the way costs react to changes in activity levels.
Managers and accountants may be biased.
Decisions often have major economic consequences for managers and accountants. LO 5-3 Statistical Cost Estimation LO 5-4 Estimate costs using statistical analysis.
Analyze costs within a relevant range, which is the limits within which a cost estimate may be valid.
Relevant range for a projection is usually between the upper and lower limits (bounds) of past activity levels for which data is available. LO 5-4
Overhead Cost Estimation for 3C
11
These data will be used to estimate costs using a statistical analysis. LO 5-4
Month Overhead costs Repair- hours
248 248 480 284 200 380 568 344 448 544 340 412 384 404 212
15 $ 9,891 $ 9,244 $13,200 $10,555 $ 9,054 $10,662 $12,883 $10,345 $11,217 $13,269 $10,830 $12,607 $10,871 $12,816 $ 8,464
14
13
12
1
2
9
8
7
6
5
4
3
10
Scattergraph
Does it look like a relationship exists between repair-hours and overhead costs? LO 5-4 Scattergraph
We use “eyeball judgment” to determine the intercept and slope of the line. LO 5-4
5-4 LO
Hi-Low Cost Estimation
This is a method to estimate cost based on two cost observations, the highest and lowest activity level.
Overhead Repair-
Month costs hours
High $12,883 568 Low $ 9,054 200 Change $ 3,829 368 Total cost at lowest activity
Variable cost per unit (V) =
LO 5-4Hi-Low Cost Estimation
Fixed cost (F) =
- – (Variable cost × Lowest activity level)
5-4 LO
Hi-Low Cost Estimation
Variable cost ($12,883 – $9,054) $3,829 $10.40 =
= = per RH (V) 568 RH – 200 RH 368 RH per RH Fixed costs (F) = ($12,883 – ($10.40 × 568 RH) = $6,976 Fixed costs (F) = ($9,054 – ($10.40 × 200 RH) = $6,974
Rounding difference Hi-Low Cost Estimation
How do we estimate manufacturing overhead with 480 repair-hours?
TC = F + VX TC = $6,976 + ($10.40 × 480) = $11,968 LO 5-4
5-4 LO
Regression Analysis
Regression is a statistical procedure to determine the relation between variables.
It helps managers determine how well the estimated regression equation describes the relations between costs and activities.
Regression Analysis
Hi-low method: Uses two data points
Regression: Uses all of the data points LO 5-4
Regression Analysis
Y = a + bX Y = Intercept + (Slope × X)
For 3C: OH = Fixed costs + (V × Repair-hours) LO 5-4
5-5 LO
Interpreting Regression Interpret the results of regression output.
Independent variable:
- – The X term, or predictor
- – The activity that predicts (causes) the change in costs Activities:
- – Repair-hours Dependent variable:
- – The Y term
- – The dependent variable
- – The cost to be estimated Costs:
- – Overhead costs
The computer output of 3C’s scattergraph gives the following formula: Total overhead = $6,472 + ($12.52 per RH × No. of RH) Estimate 3C’s overhead with 480 repair hours.
TC = F + VX
TC = $6,472 + ($12.52 × 480) = $12,482
LO 5-5Interpreting Regression
Correlation coefficient (R): This measures the linear relationship between variables. The closer R is to 1.0 the closer the points are to the regression line. The closer R is to zero, the poorer the fit of the regression line.
Coefficient of determination (R 2 ): This is the square of the correlation coefficient.
It is the proportion of the variation in the dependent variable (Y) explained by the independent variable(s) (X). LO 5-5
5-5 LO
Interpreting Regression
T-statistic: This is the value of the estimated coefficient, b, divided by its estimated standard error (Se ). Generally, if it is b over 2, then it is considered significant. If significant, the cost is NOT totally fixed.
From the data used in the 3C regression, the t-statistic is:
t = b ÷ Se b
= 12.5230 ÷ 1.5843
= 7.9044
Interpreting Regression
An 0.91 correlation coefficient means that a linear relationship does exists between repair hours and overhead costs.
An 0.828 coefficient of determination means that 82.8% of the changes in overhead costs can be explained by changes in repair-hours.
Both have t-statistics that are greater than 2, so the cost is not totally fixed. LO 5-5
5-5 LO
Multiple Regression
Multiple regression: When more than one predictor (x) is in the model
Is repair-hours the only activity that drives overhead costs at 3C? Predictors:
X : Repair-hours 1 X : Parts cost 2 Equation: TC = VC(X ) + VC(X ) + FC 1 2
5-5 LO
Multiple Regression Output
The adjusted R-squared is the correlation coefficient squared and adjusted for the number of independent variables used to make the estimate.
The statistics supplied with the output (rounded off) are:
- – Correlation coefficient (R) = 0.953 2<
- – R = 0.908 2<
- – Adjusted R = 0.892
Multiple Regression Output
TC = F + V 1 X 1 + V 2 X 2 TC = $6,416 + ($8.61 × 480) + (77% × $3,500)
TC = $13,244
LO 5-55-6 LO
Practical Implementation Problems Identify potential problems with regression data.
Effect of:
- – Nonlinear relations
- – Outliers – Spurious relations
- – Using data that do not fit the assumptions of regression analysis
5-6 LO
Practical Implementation Problems The Effect of Nonlinear Relations $800 Assumed actual cost function $700 $600 t $500 s o
Regression C $400 estimate $300
Relevant $200 Capacity range $100 $0 0 5 10 15 20 25 30 35 40 Volume
5-6 LO
Practical Implementation Problems
Problem:
- Attempting to fit a linear model to nonlinear data
- Likely to occur near full-capacity Solution: • Define a more limited relevant range.
(Example: from 25-75% capacity) • Design a nonlinear model.
5-6 LO
Practical Implementation Problems
The Effect of Outliers on the Computed Regression
Computed regression line “Outlier” True regression line
5-6 LO
Practical Implementation Problems
Problem: Outliers move the regression line.
Solution: Prepare a scattergraph, analyze the graph, and eliminate highly unusual observations before running the regression.
The Effect of Spurious Relations
Problem: Using too many variables in the regression (i.e., using direct labor to explain materials costs).
Although the association is very high, actually both are driven by output.
Solution: Carefully analyze each variable and determine the relationship among all elements before using in the regression. LO 5-6
Practical Implementation Problems
5-6 LO
Practical Implementation Problems
The Effect of Using Data That Do Not
Fit the Assumptions of Regression
Problem: If the assumptions in the regression are not satisfied, then the regression is not reliable.
Solution: There is no clear solution. Limit time to help assure costs behavior remains constant, yet this causes the model to be weaker due to less data.
Learning Phenomenon
Learning phenomenon is the systematic relationship between the amount of experience in performing a task and the time required to perform it. LO 5-6
5-7 LO
How an Estimation Method is Chosen Evaluate the advantages and disadvantages
LO 5-7 of alternative cost estimation methods.
- Reliance on historical data is relatively inexpensive.
- Computational tools allow for more data to be used than for non-statistical methods.
- Reliance on historical data may be the only readily available, cost-effective basis for estimating costs.
- Analysts must be alert to cost-activity changes.
5-7 LO
Data Problems
- Missing data
- Outliers • Allocated and discretionary costs
- Inflation • Mismatched time periods
5-7 LO
Efect of Diferent Methods on Cost Estimates Estimated manufacturing overhead with 480 repair-hours. Total Estimated Estimated estimated fixed variable
Method costs costs costs
Account analysis $12,096 $6,216 $12.25/repair-hour High-low $11,968 $6,976 $10.40/repair-hour Simple regression $12,482 $6,472 $12.52/repair-hour Multiple regression $13,244 $6,416 $8.61/repair-hour
- 77% of parts cost
(Appendix A) Use Microsoft Excel to perform a regression analysis.
Many software programs exist to aid in performing regression analysis.
Data is entered and the user then selects the data and type of regression analysis to be generated.
The analyst must be well schooled in regression in order to determine the meaning of the output.
In order to use Microsoft Excel, the Analysis Tool Pak must be installed. LO 5-8 Appendix B: Learning Curves
This is the systematic relationship between the amount of experience in performing a task and the time required to perform it.
First unit Second unit Fourth unit Eighth unit
100.0 hours 80.0 hours 64.0 hours 51.2 hours
(assumed) 80% × 100 hours 80% × 80 hours 80% × 64 hours
Unit Time to produce Calculation of time
(Appendix B) Understand the mathematical relationship describing the learning phenomenon. LO 5-9
- Impact: It causes the unit price to decrease as production increases.
- This implies a nonlinear model.