FUNGSI PEUBAH KOMPLEKS 2

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{ z n } = { z1 , z 2 , z 3 ,

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{ zn }

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z ∈C

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lim z n = z
n →∞

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zn − z < ε

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n ≥ n0

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(−1) n
z n = −2 + 2 , n = 1, 2,
n

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lim − 2 − 2 = −2 , n = ganjil
(−1) n
n →∞
n
lim z n = lim − 2 + 2 =
n →∞
n →∞

1
n
lim − 2 + 2 = −2 , n = genap
n →∞
n

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lim z n = −2
n →∞

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z
1 + , n = 1, 2,

n
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