Identifikasi Sistem pakar Mey pptx

Identifikasi Sistem
Meylin (1506800325)
Fitriyanti Izzinilah (

P7-20
Consider the typical control system for the double-effect evaporator shown in Fig. P7-5.
Evaporators are characterized by slow dynamics. The composition of the product out of
the last effect is controlled by manipulating the steam to the first effect. The design feed
rate and composition are 50,000 lb/h and 5.0 weight%, respectively. Figure P7-6 shows
the open-loop step response of the product composition for a change of 0.75% by weight
in the composition of the solution entering the first effect. Figure P7-7 shows the
response of the product composition to a change of 2.5% in controller output. The
composition sensor/transmitter has a range of 10 to 35 weight %.
a)

Draw a complete block diagram with the transfer function of each block. What
should be the fail-safe position of the control valve? What is the correct controller
action?

b)

Tune a proportional-integral controller for quarter decay ratio response.

c)

Tune a PI controller for 5% overshoot, using the controller

Gambar Sistem

Figure 7.6  perubahan
komposisi produk terhadap
perubahan 0.75% berat
komposisi feed
Figure 7.7  perubahan
komposisi produk terhadap
perubahan 2.5% controller
output

Perubahan Komposisi Produk Terhadap
Perubahan 2,5% Controller Output
Menggunakan garis bantu

maka didapatkan perhitungan
sebagai berikut
  METODE I PROSES REACTION
CURVE
Δ = 24,7 – 21,5 = 3,2
S = = 0,0068
δ = 2,5
ϴ = 110
Maka,
Kp = Δ/ δ = 1,28
τ = Δ/S = 470.589

 

 

Berdasarkan perubahan output
controller


 



516



t63%

410 s

t28%


230 s

Maka,


 

Perbandingan Hasil
dengan Matlab

2. Berdasarkan perubahan output
controller
 taktual=[0 50 75 100 150
200 300 400 450 500 550
600 650 700 750 800];
%perubahan output cont
 amplaktual=[21.5 21.5 21.57
21.65 21.75 22 22.7 23.4
23.7 23.9 24.15 24.25 24.4
24.5 24.55 24.6];
 g2_metode1=tf(1.28,
[470.589 1]);
 g2_metode1.inputdelay=110
;
 g2_metode2=tf(1.28, [270



t1=0:0.5:800;



grafik3=21.5+2.5*step(g2_metode1,t1);



grafik4=21.5+2.5*step(g2_metode2,t1);



plot(taktual,amplaktual,'k');



hold on



plot(t1,grafik3,'k-.');



plot(t1,grafik4,'g-.');



ylabel('Komposisi produk (% berat)')



xlabel('Waktu (s)')



legend('aktual,controller','metode

1','metode 2')