L .A. Sholomov Mathematical Social Sciences 39 2000 81 –107
95
side can be supplemented to TL. Since the consideration was led up to reindexing and inverting of axes, we have g g , in the general case.
ˆ r
l
The assertion a is a simple corollary of f. According to f, a LO r can be extended
ˆ to some GL
l. As a connected relation r cannot be increased without loss of asymmetry, ˆ
r coincides with l. Conversely, any GL meets the conditions b, c, f of Section 5, and therefore arbitrary GL is a LO.
n
The results of this section show that the structure of ordinal relations over R is fairly
simple. Namely, all LO’s are reduced to lexicographies up to directions of coordinate
n
axes; WO’s are reduced to lexicographies on subspaces of R ; proper SO’s and proper
IO’s are missing; each PO is an intersection of lexicographies; TR’s are equivalent to
n
PO’s strict or not on subspaces of R ; each AR is a subset of some lexicography.
7. Connection between aggregation operators and ordinal relations
All classes of relations in 3 except for 7 consist of asymmetric relations only. We will suppose up to Section 11 devoted to 7 individual relations to be asymmetric. The
21
condition of asymmetry r r 5 5 is equivalent to the inclusion r r , i.e. to the
i i
i i
inequality xr y xr y.
i i
Let Fr , . . . , r 5 Fr , . . . , r , r , . . . , r be an operator of F. Associate with F
1 n
1 n
1 n
ˆ ˆ
the function g [ P as below. To find the value g for some u , . . . , u , consider
F 3,2
F 1
n
any x, y [ A and any profile of asymmetric relations r , . . . , r such that
1 n
ˆ yr x
if u 5 2 1,
i i
¯ ¯
ˆ xr y
∧ yr x
if u 5 0, ,
19
i i
i
6
ˆ xr y
if u 5 1,
i i
and put 1
if x, y [ Fr , . . . , r ,
1 n
ˆ ˆ
g u , . . . , u 5 20
H
F 1
n
if x, y [
⁄ Fr , . . . , r .
1 n
It is easy to see that the definition is correct i.e. independent of chosen x, y and r , . . . ,
1
r provided 19. The function g was used in Aleskerov and Vladimirov 1986.
n F
It is not difficult to understand that the map F →
P is injective F ± F 9
⇒ g ± g .
3,2 F
F 9
Let us prove that it is also surjective and hence bijective. Consider any g [ P ,
3,2
9 9
gu , . . . , u 5 w p , . . . , p , p , . . . , p .
21
1 n
1 n
1 n
Let F be the operator 8 with the function w from 21. Let us verify that g 5 g. The
F
ˆ ˆ
equalities 20 and 21, with regard to the correlations pu 5 xr y and p9u 5 xr y,
i i
i i
equivalent to 19, give ˆ
ˆ g u , . . . , u 5 1
⇔ x, y [ Fr , . . . , r
⇔ wxr y, . . . , xr y, xr y, . . . , xr y 5 1
F 1
n 1
n 1
n 1
n
ˆ ˆ
ˆ ˆ
ˆ ˆ
⇔ w pu , . . . , pu , p9u , . . . , p9u 5 1
⇔ gu , . . . , u 5 1.
1 n
1 n
1 n
The correspondence between F and g in the explicit form is
F
96 L
.A. Sholomov Mathematical Social Sciences 39 2000 81 –107
9 9
F 5 Fr , . . . , r , r , . . . , r
⇔ g 5
w p , . . . , p , p , . . . , p . 22
1 n
1 n
F 1
n 1
n
Different presentations 21 of the same function g led to different ones of the same
F
operator F. Therefore, equivalent transformations in the class F are similar to them in P
.
3,2
Associate with each operator F the ordinal relation r
by g 5 g
the corre-
F r
F
F
spondence is one-to-one. The following statement Sholomov, 1990b; Sholomov, 1994
n
helps to find the explicit form of operators 0 →
5 for different 5. A particular case
n
of the approach for operators 0 →
0 was used in Fishburn 1975 and in Morkjalunas, 1985.
Theorem. If 5 is an universally axiomatizable class then an operator F [ F has the
n
type 0 →
5 iff r [ 5.
F
A proof of the fact uses the following lemma where by A we mean a finite set.
Lemma. If F is an operator in the form 8 then
n
a ;x . . . ;x [
R Ar . . . r [ 0Ax . . . x [ A
1 s
1 n
1 s
x rx ⇔
x r x , 1 i, j s, r 5 Fr , . . . , r ,
i j
i F
j 1
n n
b ;A;r . . . ;r [ 0A;x . . . ;x [ Ax . . . x [
R
1 n
1 s
1 s
x rx ⇔
x r x , 1 i, j s, r 5 Fr , . . . ,r .
i j
i F
j 1
n i
i
Proof of Lemma. a Let x 5 x , . . . , x , 1 i s. Associate x with an element x
i 1
n i
i
e.g. an integer and put A 5 hx , . . . , x j. Introduce the relations r 1 t n on A by
1 s
t i
j
ˆ setting x r x
⇔ x
. x , 1 i, j s. Consider any i, j, and denote
Dx , x by u , . . . ,
i t j t
t i
j 1
ˆ ˆ
ˆ ˆ
ˆ
9
u . Introducing p 5 pu and p 5 p9u , we have
n t
t t
t i
j
ˆ x r x
⇔ x
. x ⇔
p 5 1,
i t j t
t t
i j
¯ ˆ
9
x r x ⇔
x r x ⇔
x x
⇔ p 5 1.
i t j
j t i t
t t
With regard to 8 and 22, this gives ˆ
ˆ ˆ
ˆ
9 9
x rx ⇔
wx r x , . . . , x r x , x r x , . . . , x r x 5 1 ⇔
wp , . . . , p , p , . . . , p 5 1
i j
i 1 j i n j
i 1 j
i n j
1 n
1 n
ˆ ˆ
⇔ g u , . . . , u 5 1
⇔ g
Dx , x 5 1
⇔
x r x .
F 1
n F
i j
i F
j
b Since r [ 0A 1 t n, the finite set A can be subdivided into levels such that
t i
xr y holds iff x’s level is higher than y’s level Fishburn, 1970. Denote by x the
t t
i i
9
number of the x s level in r , and put x 5 x , . . . , x , 1 i s. We have
i t
i 1
n i
j
x r x ⇔
x . x
, i.e. x and x connect with x and x by the same way as in a. It
i t j t
t i
j i
j
makes it possible to finish the proof similarly to a, and to obtain x rx ⇔
x r x , 1 i,
i j
i F
j
j s.
L .A. Sholomov Mathematical Social Sciences 39 2000 81 –107
97
n
Proof of Theorem. Let F be an operator 0
→ 5 for an universally axiomatizable
class 5. Consider some axiom 4 used in definition of 5. Let x , . . . , x be any points
1 s
n
in R . Let us take both relations r , . . . , r [ 0 and elements x ,.., x [ A guaranteed
1 n
1 s
by a of the Lemma. The relation r 5 Fr , . . . , r of 5 satisfies the formula Px , . . . ,
1 n
1
x in 4. According to a, x r x
⇔
x rx and, therefore, Px , . . . , x is true for r .
s i
F j
i j
1 s
F
Since points x , . . . , x are arbitrary, r meets the axiom 4. As this reasoning can be
1 s
F
applied to any axiom used in the definition of 5, it gives r [ 5.
F
Conversely, let us show that r [ 5 implies r 5 Fr , . . . , r [ 5 for any r , . . . ,
F 1
n 1
n
r [ 0. Consider an axiom 4 and any x ,.., x [ A. Let x , . . . , x be points of R
n 1
s 1
s
guaranteed by b of the Lemma. Because r meets the formula Px , . . . , x , the
F 1
s
relation r satisfied Px , . . . , x . To complete the proof, it is sufficient to remark about
1 s
arbitrariness of both considered axiom and elements x ,.., x .
1 s
n
As the result, the synthesis problem for operators 0 →
5 is reduced to the description problem for ordinal relations of 5 studied in Section 6.
n
8. Explicit form of operators 0