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As ada As perlu………….. OK ☺
Jadi dipakai tulangan 4 D 22 7.5.2. Hitungan Tulangan Geser Kolom
Vu = 589,35 kg = 5,894× 10
3
N Pu = 36182,68 kg = 361826,8 N
Vc = d
b c
f Ag
Pu .
. 6
. 14
1 ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ +
=
4
10 775
, 49
442 500
6 25
500 500
14 361826,8
1 ×
= ×
× ⎟
⎠ ⎞
⎜ ⎝
⎛ ×
× +
N Ø Vc = 0,6 × Vc = 29,865 × 10
4
N 0,5 Ø Vc = 14,9325× 10
4
N Vu 0,5 Ø Vc = tanpa diperlukan tulangan geser.
Dipakai sengkang praktis untuk penghubung tulangan memanjang :
∅10 – 200
mm.
7.6 PENULANGAN SLOOF
7.6.1. Perhitungan Tulangan Lentur Sloof Melintang
Gambar bidang momen sloof As 3A-B :
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Gambar bidang geser sloof As 3A-B :
Data perencanaan : b
= 250 mm d = h – p –Ø
s
- ½Ø
t
h = 400 mm
= 400 – 40 – 8 – ½.16 f’c = 25 MPa
= 344 mm fy
= 320 MPa
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ρb = ⎥⎦
⎤ ⎢⎣
⎡ + fy
fy c
f 600
600 .
. 85
, β
= 03136
, 320
600 600
320 85
, .
25 .
85 ,
= ⎥⎦
⎤ ⎢⎣
⎡ +
ρ
max
= 0,75 ρb = 0,02352
ρ
min
= 003889
, 360
4 ,
1 4
, 1
= =
fy m =
9412 ,
16 25
85 ,
320 .
85 ,
= ×
= c
f fy
a. Daerah Tumpuan : Dari Perhitungan SAP 2000 diperoleh momen terbesar pada batang As 3
bentang A-B. Mu = 1208,68 kgm = 1,2087 × 10
7
Nmm
Mn =
φ Mu
= 8
, 10
1,2087
7
×
= 1,5109× 10
7
Nmm Rn =
2 7
2
344 250
10 1,5109
. ×
× =
d b
Mn =
0,517 m =
9412 ,
16 25
85 ,
320 .
85 ,
= ×
= c
f fy
ρ = ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− fy
2.m.Rn 1
1 m
1
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ ×
× −
− 320
517 ,
9412 ,
16 2
1 1
9412 ,
16 1
= 0,001436
ρ ρ
min
ρ ρ
max
→ dipakai tulangan tunggal Digunakan
ρ
min
= 0,003889 As
perlu
= ρ. b. d
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= 0,003889× 250 × 344 = 334,454 mm
2
n =
2
12 4
1 perlu
As ×
×
π
n = =
097 ,
113 334,454
2,957 ~ 4 tulangan As’ = 4 × 113,097 = 452,388 334,454 mm
2
As’ As………………….OK ☺
Jadi, digunakan tulangan 4 D 12
b. Daerah Lapangan: Dari Perhitungan SAP 2000 diperoleh momen terbesar pada batang As 3
bentang A - B.
Mu = 1069,85 kgm = 1,0699 × 10
7
Nmm Mn =
8 ,
10 1,0699
7
× = 1,3374 × 10
7
Nmm Rn =
452 ,
344 250
10 1,3374
.
2 7
2
= ×
× =
d b
Mn
m = 9412
, 16
25 85
, 320
85 ,
= ×
= c
f fy
ρ = ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− fy
2.m.Rn 1
1 m
1
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ ×
× −
− 320
452 ,
9412 ,
16 2
1 1
9412 ,
16 1
= 0,001269
ρ ρ
min
ρ ρ
max
Digunakan ρ
min
= 0,003889 As
perlu
= ρ. b. d
= 0,003889× 250 × 344 = 334,454 mm
2
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n =
2
12 4
1 perlu
As ×
×
π
n = =
097 ,
113 334,454
2,957 ~ 4 tulangan As’ = 4 × 113,097 = 452,388 334,454 mm
2
As’ As………………….OK ☺
Jadi, digunakan tulangan 4 D 12
c. Perhitungan Tulangan Geser