A numerical approach using the De Vylder–Goovaerts method

D.A. Stanford et al. Insurance: Mathematics and Economics 26 2000 251–267 261 The proof is completed by collecting like terms and expressing the coefficients c N j l as in 3.14 for n = N . Thus, P n, n ≥ 2 can be explicitly determined from 3.16 with coefficients c n j l starting from c 1 10 = µλ 2 + µ and c 1 11 = µλ 1 + µ. Numerical examples for this case are presented in Section 5. By inspection of Eqs. 3.13 and 3.14, we see that the recursion involves no negative numbers. Furthermore, the multiplications involve terms between 0 and 1, except for two combinatorial terms in the middle line. Thus, while the form of 3.14 may be complicated, it can nonetheless be programmed to provide accurate results. Theorem 3.5 shows that the recursion for the coefficients, while tractable, is somewhat cumbersome. The situation is even more cumbersome for α = 2. As an alternative to this exact method when the recursions are either too cum- bersome or intractable, an approximate method by De Vylder and Goovaerts can be adopted. This is presented next.

4. A numerical approach using the De Vylder–Goovaerts method

The methodology that we have employed to determine the ruin probability up to this point and in our previous paper consists of the following steps. First, a recursion involving the Laplace transforms of the incomplete densities p n x is determined in terms of the density function for the increment gx. Next, an algebraic form for L n s is obtained, and finally a recursion for the coefficients is developed. This procedure is tractable for the Poisson-arrival case, but can become an arduous task for certain arrival processes as we have seen in Section 3.2. At the same time, it is possible to retain the advantages of working with the increment distribution and a recursion based at claim instants without having to determine explicit expressions for L n s. Adopting the algorithm in De Vylder and Goovaerts 1988, formulae 4 and 5 we define ψ n u = P n i=1 P i to be the probability of ruin at or before the nth claim, given the initial surplus u. The probability of ruin on the first claim, as shown in Section 2, is obtained as ψ 1 u = F −u. The probability that ruin occurs at or before the nth claim is obtained recursively as the sum of the probability that ruin occurs on the first claim, plus the complementary probability that a surplus u + x 0 resulted from the first increment x, and the ruin occurs on or before the remaining n − 1 claims are paid. This yields ψ n u = F −u + Z ∞ x=−u gxψ n−1 u + x dx. 4.1 To obtain numerical results from the above formula 4.1 it was suggested by a referee to Lee et al.1994 to discretise the density function of the increment and then to shorten the range of summationintegration by discarding small probabilities. The discretisation used will be based on formula 15 of De Vylder and Goovaerts 1988 rewritten as follows. Let f k , −∞ k ∞, be the probability mass function for the discretised increment distribution. Then f k = Z k+1 x=k F x dx − Z k x=k−1 F x dx. 4.2 One can obtain increasingly accurate discretisations by appropriate rescaling of the increment distribution. The formulae for the cumulative distribution function F −u are given below for the cases considered in Section 3. Case 1. Mixture of exponentials revenue, Erlang-N claims F x =            P M i=1 q i P N −1 n=0 λ i λ i + θ θ λ i + θ n e xθ P N −n−1 l=0 −xθ l l , x 0, P M i=1 q i 1 − θ λ i + θ N e − λ i x , x ≥ 0. 4.3 262 D.A. Stanford et al. Insurance: Mathematics and Economics 26 2000 251–267 Case 2. Erlang-M revenue, mixture of exponentials claims F x =          P N j =1 p j λ λ + θ j M e θ j x , x 0, P N j =1 p j 1 − P M−1 m=0 θ j λ + θ j λ λ + θ j m e − λx P M−m−1 l=0 λx l l , x ≥ 0. 4.4 Below we present the increment distribution for the following additional case: Case 3. Mixture of exponentials revenue, mixture of exponentials claims F x =        P M i=1 q i P N j =1 p j λ i λ i + θ j e θ j x , x 0, P M i=1 q i P N j =1 p j 1 − θ j λ i + θ j e − λ i x , x ≥ 0. 4.5 The determination of the f k ’s for each case is straightforward. Below the final results for Case 3 are given: F −u = M X i=1 q i N X j =1 p j λ i λ i + θ j e − θ j u , 4.6 and the discretised increment distribution f k , −∞ k ∞, is given by f k = M X i=1 q i N X j =1 p j f ij k , 4.7 where f ij k =          λ i λ i + θ j e − θ j k−1 1 − e − θ j 2 θ j , k 0, θ j λ i + θ j e − λ i k−1 1 − e − λ i 2 λ i , k 0, 4.8 and where f ij 0 = 1 − θ j λ i + θ j 1 − e − λ i λ i − λ i λ i + θ j 1 − e − θ j θ j . 4.9 In the next section some numerical examples involving the exact method discussed in Section 3 are presented, as well as one example of the numerical approach discussed above.

5. Numerical results

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