vol4_pp19-31. 171KB Jun 04 2011 12:06:14 AM

The Electronic Journal of Linear Algebra.
A publication of the International Linear Algebra Society.
Volume 4, pp. 19-31, August 1998.
ISSN 1081-3810. http://math.technion.ac.il/iic/ela

ELA

ON THE CHARACTERISTIC POLYNOMIAL OF MATRICES WITH
PRESCRIBED COLUMNS AND THE STABILIZATION
AND
OBSERVABILITY OF LINEAR SYSTEMS
SUSANA FURTADOy AND FERNANDO C. SILVAz

Abstract. Let A 2 F nn , B 2 F nt , where F is an arbitrary eld. In this paper, the possible
characteristic polynomials of [ A B ], when some of its columns are prescribed and the other columns
vary, are described. The characteristic polynomial of [ A B ] is de ned as the largest determinantal
divisor (or the product of the invariant factors) of [ xIn , A , B ]. This result generalizes a
previous theorem by H. Wimmer which studies the same problem when t = 0. As a consequence,
it is extended to arbitrary elds a result, already proved for in nite elds, that describes all the
possible characteristic polynomials of a square matrix when an arbitrary submatrix is xed and the
other entries vary. Finally, applications to the stabilization and observability of linear systems by

state feedback are studied.
AMS subject classi cations. 15A18, 93B60
Key words. Matrix completion, eigenvalue, linear system.

1. Introduction. Throughout this paper, F denotes a eld. If f(x) is a polynomial, d(f) denotes its degree.
Several results are known that study the existence of matrices (matrix completions) with a xed submatrix and satisfying certain conditions. For example, the
following theorem, due to Wimmer, describes the possible characteristic polynomials
of a matrix when a certain number of rows are xed and the others vary.
Theorem 1.1. [20] Let A1 1 2 F  ; A1 2 2 F  and m = p + q. Let f 2 F[x]
be a monic polynomial of degree m. Let 1 j    j be the invariant factors of


xI , A1 1 ,A1 2 :
Then, there exist A2 1 2 F  and A2 2 2 F  such that


A1 1 A1 2
A2 1 A2 2
has characteristic polynomial f if and only if
(1)

1    j f:
Later, Zaballa [22] characterized the possible invariant polynomials of a matrix
when a certain number of rows are xed and the others vary. As a square matrix is
p

;

p

p

;

q

p

p

;


q

p

;

;

q

;

q

;

;

;


;

p

 This work was partially supported by the Praxis Program (praxis/2/2.1/mat/73/94) and was
done within the activities of the Centro de A lgebra da Universidade de Lisboa. Received by the
editors on 26 October 1997. Final manuscript accepted on 7 August 1998. Handling editor: Daniel
Hershkowitz.
y Faculdade de Economia, Universidade do Porto, Rua Dr. Roberto Frias, 4200 Porto, Portugal
(sbf@fep.up.pt).
z Departamento de Matematica, Faculdade de Ci^encias, Universidade de Lisboa, Rua Ernesto de
Vasconcelos, 1700 Lisboa, Portugal (fcsilva@fc.ul.pt).
19

ELA
20

Susana Furtado and Fernando C. Silva


similar to its transpose, these results also describe the possible characteristic polynomials and the possible invariant polynomials of a matrix when a certain number
of columns are xed and the others vary. For other results of this type, see, e.g.,
[1, 9, 10, 11, 12, 15, 17, 19, 22, 25].
Recall that the characteristic polynomial of a matrix A 2 F mm is the product
factors of xIm , A. Now call characteristic polynomial of a matrix
of the invariant

A B , where A 2 F mm , B 2 F mn , to the product of the invariant factors of




xIm , A ,B :
Note
that the
condition (1) says that the characteristic polynomial of


A1;1 A1;2 divides f.
paper [7], we have described all possible characteristic polynomials

 In a previous

of A B when some of its rows are xed and the others vary. The main
purpose

of this paper is to describe all the possible characteristic polynomials of A B
when some of its columns are xed and the others vary. Note that, in order to solve
this problem, we may assume that the columns xed in A are the rst ones and that
the columns xed in B are also the rst ones. In fact, if P 2 F mm and Q 2 F nn
are permutation matrices, then




A B
and
P ,1AP P ,1BQ
have the same characteristic polynomial.



Analogously, call characteristic polynomial of a matrix At C t t ; where A 2
F mm , C 2 F sm , to the product of the invariant factors of


Two matrices
(2)



A B
C D


xIm , At ,C t t :


and




A0 B 0
C 0 D0



A; A0 2 F mm ; B; B 0 2 F mn; C; C 0 2 F sm and D; D0 2 F sn, are said to be
m-similar if there exist matrices P 2 F mm , Q 2 F ss, R 2 F nn, S 2 F ms ,
T 2 F nm such that P, Q and R are nonsingular and






A0 B 0 = P ,1 S
A B
P 0 :
(3)
C 0 D0
0 Q

C D
T R
It is easy to see that the matrices (2) are m-similar if and only if the pencils



0 ,B 0 
xI
,
A
,
B
xI
,
A
m
m
and
(4)
,C

,D
,C 0
,D 0
are strictly equivalent. Therefore the m-similarity classes are completely described
by the Kronecker invariants for strict equivalence. Moreover, a canonical form for msimilarity results easily from the Kronecker canonical form for strict equivalence. An

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Characteristic Polynomial of Matrices with Prescribed Columns

21

explicit canonical form for m-similarity was presented in [3, Lemma 2]. For details
about strict equivalence, see, e.g., [8]. Note that the proof of the existence of the
Kronecker canonical form presented in [8] fails in nite elds. However the Kronecker
canonical form is valid in arbitrary elds; see [6].
When s = 0, m-similarity appeared in [2] with the name of feedback equivalence.
(Also see [22].) Note that, in this case, the pencils (4), which do not have the second
row of blocks, have neither row minimal indices nor in nite elementary divisors. When
s = n = 0, m-similarity is the usual relation of similarity.


2. The Characteristic Polynomial of Matrices with Prescribed
Columns. The following result was obtained by Zaballa when t = 0 [22] and when
q = 0 [23]. The general case was established in [4].
Theorem 2.1. Let A1;1 2 F pp and A2;1 2 F qp . Let 1 j    j p be the
invariant factors and k1      kq be the row minimal indices of


xIp , A1;1 :
(5)
,A2;1
Let m = p + q; B1 2 F mm and B2 2 F mt . Let
1 j    j
m be the invariant factors
and s1      s > s+1 =    = st (= 0) be the column minimal indices of


(6)
xIm , B1 ,B2 :
Then, there exist A1;2 2 F pq , A1;3 2 F pt, A2;2 2 F qq and A2;3 2 F qt such that


(7)


A1;1 A1;2 A1;3
A2;1 A2;2 A2;3





B1 B2 are feedback equivalent if and only if
(i2:1)
i j i j
i+q+ ;
i 2 f1; : : :; pg;
(ii2:1 ) m  d( q ) and

and

(k1 + 1; : : :; kq + 1)  (m , d( q,1 ); d( q,1 ) , d( q,2 ); : : :; d( 1) , d( 0 ));
where  j = 1j    pj+j

and

i 2 f1; : : :; p + j g; j 2 f0; : : :; qg;
(iii2:1 ) m  d( ) and

ij = l:c:m:f i,j ;
ig;

(s1 ; : : :; s )  (m , d(,1); d(,1) , d(,2 ); : : :; d(1) , d(0));
where j = 1j    mj ,+j

and

ij = l:c:m:f i,q ;
i+,j g;

i 2 f1; : : :; m ,  + j g; j 2 f0; : : :; g:
[We make convention that
i = 0 whenever i > m, and i = 1 whenever i  0:]
The following lemma is not hard to prove; see [17, Lemma 8] for details.
Lemma 2.2. Let t1 ; : : :; tm ; t01; : : :; t0m ; t00 be integers such that t1      tm ; t01 
    t0m ; t1 +    + tm  t00  t01 +    + t0m . Then there exist integers t001 ; : : :; t00m such
that t001      t00m ; ti  t00i  t0i ; i 2 f1; : : :; mg; t001 +    + t00m = t00.

ELA
22

Susana Furtado and Fernando C. Silva

Let A1;1 2 F pp and A2;1 2 F qp . Let 1 j    j p be
the invariant factors of (5). Let m = p + q and let t be a positive integer. Let
f 2 F [x] be a monic polynomial. Then, there exist A1;2 2 F pq , A1;3 2 F pt,
A2;2 2 F qq and A2;3 2 F qt such that (7) has characteristic polynomial f if and
only if d(l:c:m:f 1    p; f g)  m and
Corollary 2.3.

1    p, j f;

(8)

where  = minfm , d(f); tg.
Proof. Necessity. Suppose that there exists a matrix of the form (7) with char-

acteristic polynomial f. Let
1 j    j
m be the invariant factors of




xIp , A1;1
,A1;2 ,A1;3
(9)
,A2;1 xIq , A2;2 ,A2;3 :
According to Theorem 2.1, m  d( q ). Clearly l:c:m:f 1    p ; f g j  q and, therefore,
d(l:c:m:f 1    p ; f g)  m. It also follows from Theorem 2.1, that 1    p, j
1+q+   
m ; where 0 is the number of nonzero column minimal indices of (9).
Note that   0 . Therefore 1    p, j f:
Suciency. Suppose that d(l:c:m:f 1    p ; f g)  m and 1    p, j f, where
 = minfm , d(f); tg. Suppose that
0

0

i = 1li;1    li; ;
f = 1l1    l ;

i 2 f1; : : :; pg;

were 1; : : :;  are monic, pairwise distinct, irreducible polynomials and li;j and lj
are nonnegative integers. For each j 2 f1; : : :;  g, let
lj0 = maxfl1;j +    + lp;j ; lj g;
0 = li;j ;
(10)
li;j
i 2 f1; : : :; p , 1g;
0l = lp;j + l0 , (l1;j +    + lp;j ):
p;j
j
We have
0 :
l1;j +    + lp,;j  lj  lj0 = l10 ;j +    + lp;j

0 = 0 whenever i  0. According
The rst inequality follows from (8). Take li;j = li;j
00
00
to Lemma 2.2, there exist integers l1;j ; : : :; lm;j such that

(11)

00 ;
l100;j      lm;j
00
li,q,;j  li;j  li0,q;j ;
00 :
lj = l100;j +    + lm;j

i 2 f1; : : :; mg;

Let
i = 1li;1    li; ;
00

00

i 2 f1; : : :; mg:

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Characteristic Polynomial of Matrices with Prescribed Columns

23

From (10) and (11), it follows that
i,q, j
i ; i 2 f1; : : :; mg;
(12)
i j i,q j i ; i 2 f1; : : :; m , 1g;
where i = 0 whenever i > p. If q > 0, then the condition (i2:1 ) is already proved.
Now suppose that q = 0. Then d( 1    p) = p. From d(l:c:m:f 1    p; f g)  m it
0 = lp;j , j 2 f1; : : :;  g.
follows that f j 1    p. Therefore lj0 = l1;j +    + lp;j and lp;j
From (11) it follows that
p j p. In any case, the condition (i2:1) is proved.
Let j 2 f1; : : :;  g. Note that
00 g  l0 ;
maxfli,q;j ; li;j
i 2 f1; : : :; mg:
i,q;j
Therefore
m
X
i=1

Also note that
 q =  =

00 g 
maxfli,q;j ; li;j

m
Y
i=1

m
X
i=1

li0,q;j = lj0 :

Pm

00

i=1 maxfli,q;j ;li;j g j ;

l:c:m:f i,q ;
ig = j

0

where g:c:d:fj ; j g = 1, and l:c:m:f 1    p ; f g = jlj j0 ; where g:c:d:fj ; j0 g = 1.
Therefore  q =  j l:c:m:f 1    p ; f g and d( q ) = d( )  m.
From (12), it follows that  j = 1    p ; j 2 f0; : : :; q , 1g. As
1   
m = f
and d(f)  m , , we have
1 =    =
 = 1. Therefore, from (12), it follows that
0 =
+1   
m =
1   
m = f. Suppose that m , d(f) = g + h, where g and h
are integers and 0  h < . Let
si = g + 1; i 2 f1; : : :; hg;
si = g; i 2 fh + 1; : : :; g:
Note that d(
1   
m ) + s1 +    + s = m. Looking at the normal form for feedback
equivalence, it is easy to nd B1 2 F mm and B2 2 F mt such that (6) has invariant
factors
1 j    j
m and column minimal indices s1      s > s+1 =    = st (= 0).
From the previous remarks, it is not hard to deduce that the conditions (i2:1 ){
(iii2:1 ) are satis ed. According to Theorem 2.1, there exist A1;2 2 F pq , A1;3 2 F pt,
A2;2 2 F qq and A2;3 2 F qt such that (7) and B1 B2 are feedback equivalent.
Therefore (7) has characteristic polynomial
1   
m = f.
The following lemma is easy to prove.
Lemma 2.4. Let A1;1 ; A01;1 2 F pp , A1;3; A01;3 2 F pt, A2;1 ; A02;1 2 F qp ,
A2;3; A02;3 2 F qt . Let m = p + q, and let f 2 F[x] be a monic polynomial. Suppose
that



A1;1 A1;3
A2;1 A2;3



and



A01;1 A01;3
A02;1 A02;3



ELA
24

Susana Furtado and Fernando C. Silva

are p-similar. Then, there exist A1;2 2 F pq , A1;4 2 F pu, A2;2 2 F qq , A2;4 2 F qu
such that




A1;1 A1;2 A1;3 A1;4
A2;1 A2;2 A2;3 A2;4
has characteristic polynomial f if and only if there exist A01;2 2 F pq , A01;4 2 F pu ,
A02;2 2 F qq , A02;4 2 F qu such that
 0

A1;1 A01;2 A01;3 A01;4
A02;1 A02;2 A02;3 A02;4
has characteristic polynomial f .
Theorem 2.5. Let A1;1 2 F pp ; A1;3 2 F pt; A2;1 2 F qp and A2;3 2 F qt . Let
1 j    j p+ be the invariant factors,  the number of in nite elementary divisors,
l the sum of the degrees of the in nite elementary divisors, w the sum of the column
minimal indices of



(13)



xIp , A1;1 ,A1;3 :
,A2;1 ,A2;3

Let m = p+q; and let f 2 F [x] be a monic polynomial. Then, there exist A1;2 2 F pq ,
A2;2 2 F qq , A1;4 2 F pu and A2;4 2 F qu such that




A1;1 A1;2 A1;3 A1;4
(14)
A2;1 A2;2 A2;3 A2;4
has characteristic polynomial f if and only if one of the following conditions is satis ed.
(I2:5) maxf; ug > 0; d(l:c:m:f 1    p+ ; f g)  m , w , l and

1    p+, j f;
where  = minfm , w , l , d(f);  + ug.
(II2:5)  = u = 0; d(f) = m , w and
1    p j f:
Proof. Note that 1 =    = w+l = 1. With permutations of the rows and
columns of the normal form for p-similarity of


A
A
1
;1
1
;3
(15)
A2;1 A2;3
one can get a p-similar matrix of the form
3
2
0
D1;1 0
6 0
E1;1 E1;3 77 ;
6
(16)
4 D2;1
0
0 5
0 E2;1 E2;3

ELA
Characteristic Polynomial of Matrices with Prescribed Columns

25

where D1;1 2 F (p,w,l+)(p,w,l+) , D2;1 2 F (q,)(p,w,l+) , E1;1 2
F (w+l,)(w+l,) , the matrix


xIp,w,l+ , D1;1
,D2;1
has invariant factors w+l+1 ; : : :; p+ , and the matrix




xIw+l, , E1;1 ,E1;3
(17)
,E2;1
,E2;3
has w + l invariant factors equal to 1. Bearing in mind Lemma 2.4, one may assume,
without loss of generality, that (15) has the form (16).
Necessity. Suppose that there exists a matrix of the form (14) with characteristic
polynomial f. Bearing in mind that (17)has w + l invariant
factors equal to 1, and

that, therefore, its Smith normal form is Iw+l 0 , it is not hard to deduce that




xIp , A1;1
,A1;2 ,A1;3 ,A1;4
,A2;1 xIq , A2;2 ,A2;3 ,A2;4
is equivalent to a matrix of the form
2
3
xIp,w,l+ , D1;1
,D1;2
,D1;3 0 0
4
,D2;1
xIq, , D2;2 ,D2;3 0 0 5 ;
(19)
0
0
0
Iw+l 0
(18)

where D1;3 2 F (p,w,l+)(+u) . Consequently,
(20)



D1;1 D1;2 D1;3
D2;1 D2;2 D2;3



has characteristic polynomial f.
Suppose that maxf; ug > 0. According to Corollary 2.3, d(l:c:m:f 1    p+ ; f g
= d(l:c:m:f l+w+1    p+ ; f g  m , w , l and
1    p+, = l+w+1    p+, j f;
where  = minfm , l , w , d(f);  + ug.
Now suppose that  = u = 0. Then l = 0 and, as (20) is a square matrix, its
characteristic polynomial, f, has degree m , w. According to Theorem 1.1,
1    p = w+1    p j f:
Suciency. The arguments are similar to the ones used to prove necessity.
Suppose that maxf; ug > 0. According to Corollary 2.3, there exist D1;2 2
F (p,w,l+)(q,) , D1;3 2 F (p,w,l+)(+u) , D2;2 2 F (q,)(q,) , and D2;3 2
F (q,)(+u), such that (20) has characteristic polynomial f. It is not hard to see
that the matrices (18) and (19) are equivalent for certain blocks A1;2 ; A2;2; A1;4 and

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26

Susana Furtado and Fernando C. Silva

A2;4. For these blocks (14) has characteristic polynomial f. The case  = u = 0 is
analogous.
The next theorem was established in [5] for in nite elds. Now it can be deduced,
for arbitrary elds, as a simple consequence of Theorems 1.1 and 2.5. This theorem
describes the possible characteristic polynomials of a matrix with a prescribed arbitrary submatrix. Note that, with permutations of rows and columns that correspond
to similarity transformations, the general problem can be reduced to the case where
the prescribed submatrix lies in the position considered in the next statement; see [5],
for details.
Theorem 2.6. Let A1;1 2 F pp ; A1;3 2 F pt; A2;1 2 F qp and A2;3 2 F qt . Let
1 j    j p+ be the invariant factors,  the number of in nite elementary divisors,
l the sum of the degrees of the in nite elementary divisors, w the sum of the column
minimal indices of (13). Let u be a nonnegative integer and m = p + q + t + u; and
let f 2 F[x] be a monic polynomial of degree m.
If  = u = 0, then there exist A1;2 2 F pq ; A2;2 2 F qq ; A1;4 2 F pu; A2;4 2
q u
F ; A3;1 2 F tp; A3;2 2 F tq ; A3;3 2 F tt; A3;4 2 F tu; A4;1 2 F up; A4;2 2
F uq ; A4;3 2 F ut; A4;4 2 F uu; such that
2
3
A1;1 A1;2 A1;3 A1;4
66 A2;1 A2;2 A2;3 A2;4 7
(21)
4 A3;1 A3;2 A3;3 A3;4 7
5
A4;1 A4;2 A4;3 A4;4
has characteristic polynomial f if and only if there exists a polynomial g of degree
p + q , w such that
1    p j g j f:
If maxf; ug > 0, then such a matrix completion exists if and only if
1    p,u j f:
Proof. Necessity. Let g be the characteristic polynomial of (14). According to
Theorem 1.1, g j f.
If  = u = 0, then according to Theorem 2.5, g has degree p+q ,w and 1    p j g.
Now suppose that maxf; ug > 0. According to Theorem 2.5,
d(l:c:m:f 1    p+ ; gg)  p + q , w , l and 1    p+, j g, where  = minfp + q ,
w , l , d(g);  + ug. Therefore 1    p,u j g j f.
Suciency. Suppose that  = u = 0. According to Theorem 2.5, there exists a
matrix of the form (14) with characteristic polynomial g. According to Theorem 1.1,
there exists a matrix of the form (21) with characteristic polynomial f.
From now on suppose that maxf; ug > 0. Let g = 1    p,u and  = minfp +
q , w , l , d(g);  + ug.
Firstly suppose that  = p + q , w , l , d(g) <  + u. From the normal form for
p-similarity [3, Lemma 2] of (15) [or the normal form for strict equivalence of (13)],
it follows that
p = d( 1    p+ ) + k + w + l , ;

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Characteristic Polynomial of Matrices with Prescribed Columns

27

where k is the sum of the row minimalindices of (13), and that q  . If d( p+, ) > 0,
then d( p,u+1    p+ ) >  = p +q , w , l , d(g) and d( 1    p+ ) > p+q , w , l 
p , w , k , l + , which is impossible. Therefore, 1 = 1    p+, = 1    p,u = g.
For any of the two possible values of , according to Theorem 2.5, there exists a
matrix of the form (14) with characteristic polynomial g. According to Theorem 1.1,
there exists a matrix of the form (21) with characteristic polynomial f.
Lemma 2.7. Let A; A0 2 F mm ; B; B 0 2 F mt; C; C 0 2 F sm and D; D0 2 F st.
Let f 2 F[x] be a monic polynomial. Suppose that


 0

A B
A B0
and
C D
C 0 D0
are m-similar. Then, there exists X 2 F tm such that


A
+
BX
(22)
C + DX
has characteristic polynomial f if and only if there exists X 0 2 F tm such that
 0

A + B0X 0
(23)
C 0 + D0 X 0
has characteristic polynomial f .
Proof. Suppose that (3) is satis ed. Suppose that there exists X 2 F tm such
that (22) has characteristic polynomial f. Let X 0 = R,1 (XP , T). Then
 0
 


A + B 0 X 0 = P ,1 S
A + BX P;
C 0 + D0 X 0
0 Q
C + DX
which shows that (22) and (23) are feedback equivalent and, therefore, have the same
characteristic polynomial.
Theorem 2.8. Let A 2 F mm ; B 2 F mt ; C 2 F sm and D 2 F st. Let
1 j    j m+ be the invariant factors,  the number of in nite elementary divisors,
l the sum of the degrees of the in nite elementary divisors, k the sum of the row
minimal indices of

(24)





xIm , A ,B :
,C
,D

Let f 2 F[x] be a monic polynomial. Then, there exists X 2 F tm such that

(25)



A + BX
C + DX



has characteristic polynomial f if and only if one of the following conditions is satis ed.
(I2:8)  > 0; d(l:c:m:f 1    m+ ; f g)  m , k , l +  and

1    m+, j f;
where  = minfm , k , l +  , d(f); g.

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28

Susana Furtado and Fernando C. Silva

(II2:8)  = 0; d(f) = m , k and
1    m j f:

Proof. By performing permutations of rows and columns in the normal form for
m-similarity [3, Lemma 2] of


(26)

A B
C D



one get an m-similar matrix of the form
2
A1;1 A1;2

 0
0
6 0
B
0
A
6
(27)
C 0 D0 = 4 C3;1 C3;2
0
0

0 0
Iq 0
0 0
0 Iu

where A1;1 2 F pp , A1;2 2 F pq , m = p + q, and


3

0
0 77 ;
0 5
0



A1;1 A1;2
C3;1 C3;2
has a normal form for p-similarity. Note that u is the number of in nite elementary
divisors of (24) of degree equal to 1. Let (1 =) l1 =    = lu < lu+1      l be
the degrees of the in nite elementary divisors of (24). It is not hard to deduce that
q+u+1 ; : : :; m+ are the invariant factors and lu+1 , 1; : : :; l , 1 are the degrees of
the in nite elementary divisors of




xIp , A1;1 ,A1;2 :
,C3;1 ,C3;2

Moreover, 1 = : : : = q+u = 1. Bearing in mind Lemma 2.7, one may assume,
without loss of generality, that (26) has already the form (27).
Necessity. Suppose that there exists X 2 F tm such that (25) has characteristic
polynomial f. Note that (25) has the form
2

(28)

6
6
4

A1;1
A2;1
C3;1
C4;1

A1;2
A2;2
C3 ;2
C4;2

3

7
7;
5

where A2;1 2 F qp , A2;2 2 F qq , C4;1 2 F up , C4;2 2 F uq . According to Theorem
2.5, one of the conditions (I2:8), (II2:8) is satis ed.
Suciency. Suppose that one of the conditions (I2:8), (II2:8) is satis ed. According to Theorem 2.5, there exist A2;1 2 F qp , A2;2 2 F qq , C4;1 2 F up , C4;2 2 F uq
such that (28) has characteristic polynomial f. Note that (28) has the form (25) for
some X 2 F tm .

ELA
Characteristic Polynomial of Matrices with Prescribed Columns

29

3. Stabilization and Observability of Linear Systems by Linear Feedback. Let F be the eld of complex numbers, C , or the eld of real numbers, R.
Consider a linear system S


x(t)
_ = Ax(t) + Bu(t);
v(t) = Cx(t) + Du(t);

where A 2 F mm , B 2 F mn , C 2 Fsm , D 2 Fsn, x(t) is the state, u(t) is the
input and v(t) is the output.
Several results are known that relate matrix completion problems to linear systems; see, e.g., [16, 18, 20, 24].
Recall that S is stable if and only if all the solutions of x(t)
_ = Ax(t) converge to
0 as t ! +1 if and only if the real parts of the eigenvalues of A are negative; and
that S is stabilizable if and only if there exists a state feedback u(t) = Xx(t) such
that x(t)
_ = (A + BX)x(t) becomes stable if and only if the roots of the characteristic
polynomial of A B have their real parts negative. In this context, arises the
problem of describing the possible eigenvalues of A + BX, when X varies, whose
solution is known for a long time, and it is a particular case of Theorem 2.8.
Also recall
that S is completely observable if and only if the characteristic poly
nomial of At C t t is equal to 1 if and only if rank O(A; C) = m; where

O(A; C) = C t (CA)t    (CAm,1 )t t
is the observability matrix of S ; and that Stis detectable if and only if the roots of




the characteristic polynomial of At C t have their real parts negative. For the
meaning of these concepts in systems theory and other details, see, e.g., [13].
Now suppose that the entries of A and C are polynomials in variables x1; : : :; xh
and let A be the set of all h-uples (a1 ; : : :; ah ) 2 Fh such that
rank O(A(a1 ; : : :; ah); C(a1; : : :; ah )) < m:
Then A is an algebraic set. Therefore, if ; =
6 A 6= F h , then, in any neighbourhood of
h
any element of A, there are elements of F that do not belong to A.
The following results are simple consequences of Theorem 2.8. We use the notation of Theorem 2.8.
Corollary 3.1. There exists a state feedback u(t) = Xx(t) such that

x(t)
_ = (A + BX)x(t);
(29)
v(t) = (C + DX)x(t)
becomes completely observable if and only if one of the following conditions is satis ed.
(I3:1) The system is already completely observable with u(t)  0.
(II3:1)  > 0 and 1    m = 1.
Proof. Note that, from the normal form for m-similarity [3, Lemma 2] of (26) [or

the normal form for strict equivalence of (24)], it follows that
(30)
m = d( 1    m+ ) + k + w + l , ;

ELA
30

Susana Furtado and Fernando C. Silva

where w is the sum of the column minimal indices of (28).
Necessity. The characteristic polynomial of (25) is f = 1. According to Theorem
2.8, 1    m = 1.
Now suppose that  = 0. Then l = 0 and m = d( 1    m ) + k + w. According
to Theorem 2.8, m = k and, therefore, w = 0. It follows that B = 0 and D = 0.
Consequently the characteristic polynomial of At C t t is 1    m = 1, that is,
the system is already completely observable with u(t)  0.
Suciency. As the case (I3:1) is trivial, suppose that (II3:1) is satis ed. Take
f = 1 2 F [x]. Let  = minfm , k , l + ; g. Suppose that  = m , k , l + . If
k+l = m+, 6= 1, then d( 1    m+ ) >  = m +  , k , l, which is impossible.
Then (I2:8) is satis ed. If  = , then (I2:8) is also satis ed. According to Theorem
2.8, there exists X 2 F tm such that (25) has characteristic polynomial f, that is,
(29) is completely observable.
Corollary 3.2.
There exists a state feedback u(t) = Xx(t) such that (29)
becomes detectable if and only if the roots of 1    m have their real parts negative.
Proof. Necessity. Let f be the characteristic polynomial of (25). The roots of f
have their real parts negative. According to Theorem 2.8, the roots of 1    m have
their real parts negative.
Suciency. Note that (30) is satis ed.
If  = 0, then d( 1    m )  m , k. Let f = 1    m g be a monic polynomial
of degree m , k such that the real parts of the roots of g are negative. According to
Theorem 2.8, there exists X 2 F sm such that (25) has characteristic polynomial f.
Therefore (29) is detectable.
Now suppose that  > 0. From (30) it follows that d( 1    m )  m , k , l + .
Let  = minfm , k , l +  , d( 1    m ); g.
Suppose that  = m , k , l +  , d( 1    m ) < . If d( m+, ) > 0, then
d( m+1    m+ ) >  = m , k , l +  , d( 1    m ), which is impossible. Therefore,
1 = 1    m+, = 1    m .
For any value of , according to Theorem 2.8, there exists X 2 F nm such that
(25) has characteristic polynomial 1    m and (29) is detectable.
Corollary 3.3.
There exists a state feedback u(t) = Xx(t) such that (29)
becomes simultaneously stable and completely
observable if and only if the roots of the

characteristic polynomial of A B have their real parts negative and one of the
conditions (I3:1), (II3:1) is satis ed.
Proof. The necessity follows immediately from the previous remarks
and results.


Suciency. As the roots of the characteristic polynomial of A B have

their real parts negative, there exists X0 2 F nm such that A + BX0 is stable.
By continuity, there exists a neighbourhood V of X0 such that A + BX is stable
for every X 2 V . Now let A be the set of all the matrices X 2 Fnm such that
rank(O(A + BX; C + DX)) < m. As one of the conditions (I3:1), (II3:1) is satis ed,
A 6= F nm .
If X0 62 A, the proof is complete with X = X0 . If X0 2 A, there exists a matrix
X 2 V n A and the proof is also complete.

ELA
Characteristic Polynomial of Matrices with Prescribed Columns

31

Acknowledgement. We would like to thank one of the referees for detecting an
error in Corollary 2 3 and for his comments.
:

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[3] I. Cabral. Matrices with prescribed submatrices and number of invariant polynomials, Linear
Algebra Appl., 219:207{224, 1995.
[4] I. Cabral and F. C. Silva. Uni ed theorems on completions of matrix pencils, Linear Algebra
Appl., 159:43{54, 1991.
[5] I. Cabral and F. C. Silva. Similarity invariants of completions of submatrices, Linear Algebra
Appl., 169:151{161, 1992.
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