some of them still made few grammatical mistakes. The analysis of students’ transcript on the spoken test can be seen in the appendix 10.
B. Hypothesis Testing
This section includes the presentation of the normality of the data distribution and t-test calculation.
1. Normality of Data Distribution
As we know that the data should be normally distributed, the researcher checked the normality of the data distribution by using SPSS 15 Program. The
following is the result of the computation of the pretest and posttest of normality for IAK as the experimental group and IAP as the control group.
Table 15. Tests of Normality for IAK experimental group
Kolmogorov-Smirnova Shapiro-Wilk
Statistic df
Sig. Statistic
df Sig.
PRETESTIAK ,138
30 ,153
,931 30
,053 POSTTESTIAK
,103 30
,200 ,966
30 ,432
This is a lower bound of the true significance. a Lilliefors Significance Correction
Table 16. Tests of Normality for IAP control group
Kolmogorov-Smirnova Shapiro-Wilk
Statistic df
Sig. Statistic
df Sig.
PRETEST1AP ,142
30 ,126
,954 30
,212 POSTTEST1AP
,105 30
,200 ,978
30 ,765
This is a lower bound of the true significance. a Lilliefors Significance Correction
As we can see from the calculation above, the value of significance is higher than 0.05 a. Jogiyanto 2004:171 says that data is considered normally
distributed when the value of the significance is higher than 0.05 a. The value PLAGIAT MERUPAKAN TINDAKAN TIDAK TERPUJI
of significance for the pretest of IAK is 0.153 and the value of significance for the posttest of IAK is 0.200. It means that the data in pretest and posttest are
considered distributed normally because the values of significance are higher than 0.05 a. It is also obvious for the value of significance for the pretest and posttest
of IAP. The value of significance for the pretest of IAP is 0.126 and the value of significance for the posttest of IAP is 0.200. Both of the values of significance are
higher than 0.05 a. So, the data are considered distributed normally.
2. t-test Calculation
The researcher used t-test for independent samples to find the significance of the difference between the mean scores of the two samples as well as to
answer the problem formulation and to test the hypothesis. The data of the mean scores of IAK as the experimental group and IAP as the control group was
presented on the appendix as well as the complete calculation of the independent sample t-test.
The calculation of the standard error of the difference between the two mean gained scores was 2.36 see appendix and the value of the t-test was 2.512
see the appendix. Furthermore, to determine the significance of the result, it needed to calculate the degrees of freedom and consulted the t-table. In this
research, the number of degrees of freedom for independent t-test equaled n
1
+n
2
- 2, that meant 30+30-2= 58. The degree of freedom was 58 in 0.05 level. In this
case: 2.512 1.671
t
obs
t
table
In the hypothesis, when t
obs
1.671, Ho is rejected. So, based on the manual calculation, the null hypothesis is rejected and the research hypothesis is
accepted. Therefore, the answer of the problem formulation was concluded from the calculation that Dictogloss technique has positive effect to enhance the
mastery of simple past tense for the first grade students of SMK Bopkri I Yogyakarta
.
C. Other Findings
