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Electronic Journal of Linear Algebra ISSN 1081-3810
A publication of the International Linear Algebra Society
Volume 18, pp. 613-627, October 2009

ELA

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REPRESENTATIONS FOR THE DRAZIN INVERSE OF BOUNDED
OPERATORS ON BANACH SPACE∗
´
´ † AND YIMIN WEI‡
DRAGANA S. CVETKOVIC-ILI
C

Abstract. In this paper a representation is given for the Drazin inverse of a 2 × 2 operator
matrix, extending to Banach spaces results of Hartwig, Li and Wei [SIAM J. Matrix Anal. Appl.,
27 (2006) pp. 757–771]. Also, formulae are derived for the Drazin inverse of an operator matrix M
under some new conditions.

Key words. Operator matrix, Drazin inverse, D-invertibility, GD-invertibility.


AMS subject classifications. 47A52, 47A62, 15A24.

1. Introduction. Throughout this paper X and Y are Banach spaces over the
same field. We denote the set of all bounded linear operators from X into Y by B(X , Y)
and by B(X ) when X = Y. For A ∈ B(X , Y), let R(A), N (A), σ(A) and r(A) be the
range, the null space, the spectrum and the spectral radius of A, respectively. By IX
we denote the identity operator on X .
In 1958, Drazin [16] introduced a pseudoinverse in associative rings and semigroups that now carries his name. When A is an algebra and a ∈ A, then b ∈ A is
the Drazin inverse of a if
(1.1)

ab = ba, b = bab and a(1 − ba) ∈ Anil ,

where Anil is the set of all nilpotent elements of algebra A.
Caradus [5], King [23] and Lay [25] investigated the Drazin inverse in the setting
of bounded linear operators on complex Banach spaces. Caradus [5] proved that a
bounded linear operator T on a complex Banach space has the Drazin inverse if and
∗ Received by the editors September 6, 2009. Accepted for publication October 13, 2009. Handling
Editor: Bit-Shun Tam.

† Department of Mathematics, Faculty of Sciences and Mathematics, University of Niˇ
s, P.O. Box
224, Viˇsegradska 33, 18000 Niˇs, Serbia ([email protected]). Supported by Grant No. 144003 of
the Ministry of Science, Technology and Development, Republic of Serbia.
‡ Institute of Mathematics, School of Mathematical Science, Fudan University, Shanghai, 200433,
P. R. of China and Key Laboratory of Nonlinear Science (Fudan University), Education of Ministry
([email protected]). Supported by the National Natural Science Foundation of China under
grant 10871051, Shanghai Municipal Education Commission (Dawn Project) and Shanghai Municipal
Science and Technology Committee under grant 09DZ2272900 and KLMM0901.

613

Electronic Journal of Linear Algebra ISSN 1081-3810
A publication of the International Linear Algebra Society
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614

D. Cvetkovi´
c-Ili´
c and Y. Wei

only if 0 is a pole of the resolvent (λI − T )−1 of T . The order of the pole is equal to
the Drazin index of T which we shall denote by ind(A) or iA . In this case we say that
A is D-invertible. If ind(A) = k, then Drazin inverse of A denoted by AD satisfies
(1.2)

Ak+1 AD = Ak , AD AAD = AD , AAD = AD A,

and k is the smallest integer such that (1.2) is satisfied. If ind(A) ≤ 1, then AD
is known as the group inverse of A, denoted by A♯ . A is invertible if and only if
ind(A) = 0 and in this case AD = A−1 .
Harte [20] and Koliha [24] observed that in Banach algebra it is more natural to
replace the nilpotent element in (1.1) by a quasinilpotent element. In the case when
a(1 − ba) in (1.1) is allowed to be quasinilpotent, we call b the generalized Drazin
inverse (g-Drazin inverse) of a and say that a is GD-invertible. g-Drazin inverse was

introduced in the paper of Koliha [24] and it has many applications in a number of
areas. Harte [20] associated with each quasipolar operator T an operator T × , which is
an equivalent to the generalized Drazin inverse. Nashed and Zhao [29] investigated the
Drazin inverse for closed linear operators and applied it to singular evolution equations
and partial differential operators. Drazin [17] investigated extremal definitions of
generalized inverses that give a generalization of the original Drazin inverse.
Finding an explicit representation for the Drazin inverse of a general 2 × 2 block
matrix, posed by Campbell in [4], appears to be difficult. This problem was investigated in many papers (see [21], [27], [14], [22], [33], [26], [8], [12]). In this paper we
give a representation for the Drazin inverse of a 2 × 2 bounded operator matrix. We
show that the results given by Hartwig, Li and Wei [22] are preserved when passing
from matrices to bounded linear operators on a Banach space. Also, we derive formulae for the Drazin inverse of an operator matrix M under some new conditions.

If 0 ∈
/ accσ(A), then the function z → f (z) can be defined as f (z) = 0 in a
neighborhood of 0 and f (z) = 1/z in a neighborhood of σ(A)\{0}. Function z → f (z)
is regular in a neighborhood of σ(A) and the generalized Drazin inverse of A is defined
using the functional calculus as Ad = f (A). An operator A ∈ B(X) is GD-invertible,
if 0 ∈
/ accσ(A) and in this case the spectral idempotent P of A corresponding to {0} is
given by P = I − AAd (see the well-known Koliha’s paper [24]). If A is GD-invertible,

then the resolvent function z → (zI − A)−1 is defined in a punctured neighborhood
of {0} and the generalized Drazin inverse of A is the operator Ad such that
Ad AAd = Ad , AAd = Ad A and A(I − AAd ) is quasinilpotent.
It is well-known that if A ∈ B(X ) is GD-invertible, then using the following

Electronic Journal of Linear Algebra ISSN 1081-3810
A publication of the International Linear Algebra Society
Volume 18, pp. 613-627, October 2009

ELA

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Drazin Inverse of Bounded Operators on Banach Space

615

decomposition
X = N (P ) ⊕ R(P ),
we have that

A=



A1
0

0
A2




 
N (P )
N (P )
,

:
R(P )

R(P )

where A1 : N (P ) → N (P ) is invertible and A2 : R(P ) → R(P ) is quasinilpotent
operator.
In this case, the generalized Drazin inverse of A has the following matrix decomposition:
 −1



 
A1
N (P )
N (P )
0
.

:
Ad =
R(P )
R(P )

0
0
For other important properties of Drazin inverses see ([1], [2], [3], [5], [7], [8], [9],
[10], [13], [15], [19], [21], [26], [27], [30], [31], [32], [33], [34]).
2. Main results. Firstly, we will state a very useful result concerning the
additive properties of Drazin inverses which is the main result proved in [6] with
aπ = 1 − aad .
Theorem 2.1. Let a, b be GD-invertible elements of algebra A such that
aπ b = b, abπ = a, bπ abaπ = 0.
Then a + b is GD-invertible and

d

(a + b) =
+




d


b +




n=0



n=0




d n+2

(b )

n


a(a + b)

n=0

bπ (a + b)n b(ad )n+2 −






aπ + b π ad
(bd )n+2 a(a + b)n bad

n=0
∞ 




bd a(a + b)n b(ad )n+2 −

(bd )k+2 a(a + b)n+k+1 b(ad )n+2 .

n=0 k=0

Next we extend [22, Lemma 2.4] to the linear operator.
Lemma 2.2. Let M ∈ B(X ), G ∈ B(X , Y) and H ∈ B(Y, X ) be operators such
that HG = IX . If M is GD-invertible operator, then the operator GM H is GDinvertible and
(2.1)

(GM H)d = GM d H.

Electronic Journal of Linear Algebra ISSN 1081-3810
A publication of the International Linear Algebra Society
Volume 18, pp. 613-627, October 2009

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616

D. Cvetkovi´
c-Ili´
c and Y. Wei

Proof. It is evident that
(GM d H)(GM H)(GM d H) = GM d M M d H = GM d H
and
(GM d H)(GM H) = GM d M H = GM M d H = (GM H)(GM d H).


To prove that GM H I − (GM H)(GM d H) is a quasinilpotent, note that


GM H I − (GM H)(GM d H) = GM (I − M M d )H.

Since M (I − M M d ) is quasinilpotent, we have




r GM H(I − (GM H)(GM d H)) = r GM (I − M M d )H
1


n 

n
= lim  GM (I − M M d )H 
n→∞
1


n 
n

= lim G M (I − M M d) H 
n→∞

n  n1
1
1


≤ lim G n ·  M (I − M M d )  · H n = 0.
n→∞

Hence, (2.1) is valid.

From now on, we will assume that X and Y are Banach spaces and Z = X ⊕ Y.
For A ∈ B(X ), B ∈ B(Y, X ), C ∈ B(X , Y) and D ∈ B(Y), consider the operator


A B
∈ B(Z).
M=
C D
Theorem 2.3. If A and D are GD-invertible operators such that
BC = 0 and DC = 0,
then M is GD-invertible and
d

M =



Ad
C(Ad )2

X
Y + Dd



,

where
(2.2) X = X(A, B, D) =




(Ad )n+2 BDn Dπ +

n=0

and Y = CXDd + CAd X.




n=0

Aπ An B(Dd )n+2 − Ad BDd

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617

Drazin Inverse of Bounded Operators on Banach Space

Proof. We rewrite M = P + Q, where P =
[14, Theorem 5.1], P d is GD-invertible and
 d
A
d
P =
0



X
Dd



A
0

B
D



and Q =



0
C

0
0



. By

,

where X = X(A, B, D) is defined by (2.2). Also, Q is GD-invertible and Qd = 0.
Now, we have that the condition P π Q = Q is equivalent to
−(AX + BDd )C = 0,

(2.3)

Dπ C = C
whereas the condition P QP π = 0 is equivalent to
BCAπ = 0, DCAπ = 0,
−BC(AX + BDd ) = 0,

(2.4)

d

−DC(AX + BD ) = 0.
Since, BC = 0 and DC = 0, from (2.3) and (2.4) we get that P π Q = Q and
P QP π = 0, so by Theorem 2.1, we have that M is GD-invertible and
Md = Pd +




M n Q(P d )n+2

n=0
d

=



A
0

=



Ad
0

=



Ad
C(Ad )2

X
Dd



X
Dd



∞ 

A
+
C
n=0



+

B
D

n

0
C(Ad )2

X
Y + Dd

2





C(Ad )n+2

0
n+2


C(Ad )i−1 X(Dd )n+2−i

i=1

0

C(Ad )i−1 X(Dd )2−i

i=1



0








,

for Y = CXDd + CAd X.
Remark 1. Theorem 2.3 is a strengthening of [14, Theorem 5.3], since it shows
that one of the conditions of Theorem 2.3 (BD = 0) is actually redundant.
Theorem 2.4. If A and D are GD-invertible operators such that
(2.5)

C(I − AAd )B = 0,

A(I − AAd )B = 0

Electronic Journal of Linear Algebra ISSN 1081-3810
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618

D. Cvetkovi´
c-Ili´
c and Y. Wei

and S = D − CAd B is nonsingular, then M is GD-invertible and

"

d

(2.6) M =

I+

(I − AAd )B
0

0
0

# !

R R I+


X

"

R

i+1

i=0

0
C(I − AAd )Ai

0
0

#!
,

where
(2.7)

R=



Ad + Ad BS −1 CAd
−S −1 CAd

−Ad BS −1
S −1



.

Proof. In [18] it is proved that σ(A) ∪ σ(M ) = σ(A) ∪ σ(D), so we conclude that
0∈
/ accσ(M ), i.e., M is GD-invertible.
Using that X = N (P ) ⊕ R(P ), for P = I − AAd , we have


A1

M=
0
C1
where B =



B1
B2



:Y →



0
A2
C2

 



B1
N (P )
N (P )
B2  :  R(P )  →  R(P )  ,
D
Y
Y

N (P )
R(P )



and C =



C1

C2



:



N (P )
R(P )



→Y.

Now, we have

A1 0 B1
M1 = I2  0 A2 B2  I1
C1 C2 D


 


A1 B1 0
N (P )
N (P )
,
→ Y
=  C1 D C2  :  Y
R(P )
R(P )
0 B2 A2


where


I
I2 =  0
0

I
I1 =  0
0

0
0
I
0
0
I

 


0
N (P )
I  :  R(P )  → 
0
Y


 
N (P )
0
→
I : Y
R(P )
0


N (P )
,
Y
R(P )

N (P )
R(P )  .
Y

Since I1 = I2−1 , using Lemma 2.2, we have that M d = I1 M1d I2 , so we proceed
towards finding the Drazin inverse of M1 .

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619

Drazin Inverse of Bounded Operators on Banach Space

In order to get an explicit formula for M1d , we partition M1 as a 2×2 block-matrix,
i.e.,
M1 =



A3
C3

B3
D3



where
A3 =



A1
C1

B1
D



, B3 =



0
C2



, C3 =



0

B2



, D3 = A2 .

From (2.5), we get C2 B2 = 0 and A2 B2 = 0, so B3 C3 = 0 and D3 C3 = 0. Also, by
σ(A3 )∪σ(A1 ) = σ(A1 )∪σ(D), it follows that A3 is GD-invertible. Applying Theorem
2.3 we get that




d i+2
i
d
(A
)
B
D
A
3 3
3
3


i=0

M1d = 




C3 (Ad3 )i+3 B3 D3i
C3 (Ad3 )2
i=0

=



I
C3 Ad3



Ad3



I




i=0

(Ad3 )i+1 B3 D3i



.

For the operator matrix A3 we have that its upper left block, the operator A1 is
nonsingular and its Schur complement
d
S(A3 ) = D − C1 A−1
1 B1 = D − CA B

is nonsingular, which implies that the operator A3 is nonsingular and
 −1

−1
−1
A1 + A−1
C1 A−1
A−1
−1
1 B1 S
1
1 B1 S
A3 =
.
S −1 C1 A−1
S −1
1
Now,
M d = I1 M1d I2


where




0



d d



(Ad3 )i+1 B3 D3i 0
= I3 + I C3 A3 A3 I4 +
i=0
0
I
I3 =  0
0


I4 =



I
0






0
N (P )
N
(P
)
→  R(P )  ,
0 :
Y
I
Y





N (P )
0 0
N (P )


:
.

R(P )
0 I
Y
Y

I

0




Electronic Journal of Linear Algebra ISSN 1081-3810
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620

D. Cvetkovi´
c-Ili´
c and Y. Wei

It is obvious that I4 I3 = IN (P )⊕Y . Let us denote by R = I3 Ad3 I4 ,



0
N (P )
I5 =  I  : R(P ) →  R(P )  ,
0
Y


N (P )


I6 = 0 I 0 :  R(P )  → R(P ).
Y


Obviously, R is given by (2.7). Now,







d
d i+1
i
M = IZ + I5 C3 A3 I4 R IZ + I3
(A3 ) B3 D3 I6 .
d

i=0

By computation, we get that
I5 C3 Ad3 I4 =



0
0

(I − AAd )B
0



R,

I3 (Ad3 )i+1 B3 D3i I6 = I3 (Ad3 )i I4 (I3 Ad3 B3 I6 )(I5 D3i I6 )


0
0
(I − AAd )Ai
i
=RR
C(I − AAd ) 0
0


0
0
,
= Ri+1
C(I − AAd )Ai 0

0
0



so, (2.6) is valid.
Remark 2. Theorem 2.3 generalizes [22, Theorem 3.1] to the bounded linear
operator.
Taking conjugate operator of M in Theorem 2.4, we derived the following corollary:
Corollary 2.5. If A and D are GD-invertible operators such that
C(I − AAd )B = 0,

C(I − AAd )A = 0

and S = D − CAd B is nonsingular, then M is GD-invertible and


 


∞ i
0
0
A (I − AAd )B
d
i+1
i=0
M = I+
R I +R
R
C(I − AAd )
0
0

0
0



,

where R is defined by (2.7).
If an additional condition C(I − AAd )A = 0 is satisfied in Theorem 2.4, we get a
simpler formula for M d :

Electronic Journal of Linear Algebra ISSN 1081-3810
A publication of the International Linear Algebra Society
Volume 18, pp. 613-627, October 2009

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621

Drazin Inverse of Bounded Operators on Banach Space

Corollary 2.6. If A and D are GD-invertible operators such that
C(I − AAd )B = 0,

A(I − AAd )B = 0,

C(I − AAd )A = 0

and S = D − CAd B is nonsingular, then M is GD-invertible and



  

0 (I − AAd )B
0
0
Md = I +
,
R R I +R
C(I − AAd ) 0
0
0
where R is defined by (2.7).
In the paper of Miao [28] a representation of the Drazin inverse of block-matrices
M is given under the conditions:
C(I − AAD ) = 0,

(I − AAD )B = 0 and S = D − CAD B = 0.

Hartwig et al. [22] generalized this result in Theorem 4.1 and gave a representation
of the Drazin inverse of block-matrix M under the conditions:
C(I − AAD )B = 0,

A(I − AAD )B = 0 and S = D − CAD B = 0.

In the following theorem we generalized Theorem 4.1 from [22] to the linear bounded
operator.
Theorem 2.7. If A and D are GD-invertible operators such that
C(I − AAd )B = 0,

A(I − AAd )B = 0, S = D − CAd B = 0

and the operator AW is GD-invertible, then M is GD-invertible and

"

d

(2.8) M =

I+

0
0

# !

(I − AAd )B
0

R1

R1

I+


X

"

0
C(I − AAd )Ai

R1i+1

i=0

0
0

#!
,

where
(2.9)

R1 =



I
CAd



Ad,w



I

Ad B



,

and Ad,w = [(AW )d ]2 A is the weighted Drazin inverse [11] of A with weight operator
W = AAd + Ad BCAd .
Proof. Using the notations and method from the proof of Theorem 2.4, we have
that




d i+2
i
d
(A
)
B
D
A
3 3
3
3


i=0

M1d = 




C3 (Ad3 )i+3 B3 D3i
C3 (Ad3 )2
i=0

=



I
C3 Ad3



Ad3



I




i=0

(Ad3 )i+1 B3 D3i



.

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622

D. Cvetkovi´
c-Ili´
c and Y. Wei

Now, prove that the generalized Drazin inverse of A3 is given by




I
,
F =
((A1 H)2 )d A1 I A−1
1 B1
C1 A−1
1

−1
where H = I + A−1
1 B1 C1 A1 . Remark that from the fact that AW is GD-invertible,
it follows that A1 H is GD-invertible. By computation we check that

A3 F = F A3 and F A3 F = F.
To prove that the operator A3 (I − F A3 ) is a quasinilpotent, we will use the fact that
for bounded operators A and B on Banach spaces, r(AB) = r(BA). First note that








I
I
−1
−1
A3 =
A
and
H
=
.
I
A
B
I
A
B
1
1
1
1
1
C1 A−1
C1 A−1
1
1
Since

A3 (I − F A3 ) =



I
C1 A−1
1

it follows that



 
I − (A1 H)(A1 H)d A1 I

A−1
1 B1



,






r A3 (I − F A3 ) = r I − (A1 H)(A1 H)d A1 H = 0,

so A3 (I − F A3 ) is a quasinilpotent. Hence, Ad3 = F .

Now, for R1 = I3 Ad3 I4 , we get that (2.8) holds. By computation we obtain






H 0
I
d,w
d
d
= AAd +
A
that R1 = I3 A3 I4 =
I A B , where W =
0 0
CAd
Ad BCAd .
We obtain the following corollary by taking conjugate operator:
Corollary 2.8. If A and D are GD-invertible operators such that
C(I − AAd )B = 0,

C(I − AAd )A = 0, S = D − CAd B = 0

and the operator AW is GD-invertible, then M is GD-invertible and






∞ 
i
d

0
0
0
A
(I

AA
)B
i+1
d
R1
M = I+
R1 I + R1
,
C(I − AAd ) 0
0
0
i=0

where R1 is given by (2.9) in Theorem 2.7.
If the condition C(I − AAd )A = 0 is added to Theorem 2.7, we have a simpler
formula for M d .

Electronic Journal of Linear Algebra ISSN 1081-3810
A publication of the International Linear Algebra Society
Volume 18, pp. 613-627, October 2009

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623

Drazin Inverse of Bounded Operators on Banach Space

Corollary 2.9. If A and D are GD-invertible operators such that
C(I − AAd )B = 0,

C(I − AAd )B = 0, A(I − AAd )B = 0, S = D − CAd B = 0

and the operator AW is GD-invertible, then M is GD-invertible and
 





0 (I − AAd )B
0
0
R1 R1 I + R1
Md = I +
,
C(I − AAd ) 0
0
0
where R1 is given by (2.9) in Theorem 2.7.
The next theorem presents new conditions under which we give a representation
of M d in terms of the block-operators of M .
Theorem 2.10. If A and D are GD-invertible operators and
AAd B = 0

(2.10)

and

C(I − AAd ) = 0,

then M is GD-invertible and






0
0
0
i
π
R
M d = Rd I +
+
R
C(Ad )i+2
CAd 0

0
0

i=0



+



Ad
0

0
0



where
R=



(I − AAd )A B
0
D





and Rd = 

0




(I − AAd )Ai B(Dd )i+2

i=0

0

D

d



.

Proof. As in the proof of the Theorem 2.4, we conclude that M is GD-invertible.
Using that X = N (P ) ⊕ R(P ), for P = I − AAd , we have
A1
M = 0
C1


where B =



B1
B2



:Y →



0
A2
C2

 



B1
N (P )
N (P )
B2  :  R(P )  →  R(P )  ,
D
Y
Y

N (P )
R(P )



and C =



C1

C2



:



N (P )
R(P )

Now,
M1 = J2 M J1

A2 B2
=  C2 D
0 B1

 



0
R(P )
R(P )
→ Y
,
C1  :  Y
A1
N (P )
N (P )



→Y.

Electronic Journal of Linear Algebra ISSN 1081-3810
A publication of the International Linear Algebra Society
Volume 18, pp. 613-627, October 2009

ELA

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624

D. Cvetkovi´
c-Ili´
c and Y. Wei

 




0 I 0
N (P )
R(P )
0
 and J1 =  I
where J2 =  0 0 I  :  R(P )  →  Y
I 0 0
Y
N (P )
0




R(P )
N (P )
 Y
 →  R(P ) .
N (P )
Y


0
0
I


I
0  :
0

Using Lemma 2.2, we deduce that M d = J1 M1d J2 . In order to compute M d it
suffices to find the Drazin inverse of M1 . To derive an explicit formula for M1d , we
partition M1 as a 2 × 2 block-matrix, i.e.,


A3 B3
M1 =
C3 D3
where
A3 =



A2
C2

B2
D



, B3 =



Since

0
C1



, C3 =



0

B1



, D3 = A1 .

B3 C3 = 0 ⇔ C1 B1 = 0 ⇔ CAAd B = 0
and
D3 C3 = 0 ⇔ A1 B1 = 0 ⇔ AAd B = 0.
by (2.10) we have B3 C3 = 0 , D3 C3 = 0 and B1 = 0.
Similarly as in the proof of the Theorem 2.4, we conclude that A3 is GD-invertible
operator. Now, by Theorem 2.3,




−1
−1 i+2
d
π i
d
− A3 B3 A1
A A B3 (A1 )
A

M1d =  3 i=0 3 3
0
(A1 )−1




 






I
0
0
I
−1 i+2
i
π
B
(A
)
0
A
Ad3 I −B3 A−1
=
+
.
A
+
3 3
1
3
1
0
0 A−1
0
i=0
1
By the second condition of (2.10), we obtain that C2 = 0, as for the operator A3 we
have that
B2 C2 = 0

and DC2 = 0.

Applying Theorem 2.3 to A3 , we get




i
d i+2
A
B
(D
)
0
2 2
.
Ad3 = 
i=0
0
Dd

Electronic Journal of Linear Algebra ISSN 1081-3810
A publication of the International Linear Algebra Society
Volume 18, pp. 613-627, October 2009

ELA

http://math.technion.ac.il/iic/ela

625

Drazin Inverse of Bounded Operators on Banach Space

Now,
M d = J1 M1d J2
=

J3 Ad3




π
J4 + B3 A−1
1 J5 + J3 A3

∞


i+2
Ai3 B3 (A−1
J5
1 )

i=0






π
i+2
= R I + J3 B3 A−1
Ai3 B3 (A−1
J5 +
1 J5 + R J3
1 )
d

i=0

0
where R = J3 A3 J4 , J3 =  I
0



0
0
0 , J4 =
0
I



I
0

0
I





+



Ad
0

0
0




0 0 .

and J5 =



1

Ad
0

0
0




,

It is evident that J4 J3 = I. By computation, we get that


0
0
J3 B3 A−1
,
J
=
5
1
CAd 0


0
0
−1 i+2
i
i
J3 A3 B3 (A1 ) J5 = R
.
C(Ad )i+2 0
Also, from the definition of R, we have that

(I − AAd )A
R=
0

B
D



and by [14, Theorem 5.1]


Rd = 

0




(I − AAd )Ai B(Dd )i+2

i=0

0

D

d



.

3. Concluding remarks. The whole paper would appear to be valid in general
Banach algebras, not just algebras of operators. Whenever P = P 2 ∈ G, for a Banach
algebra G, there is an induced block structure


A M
G=
N B
in which A and B are Banach algebras and M and N are bimodules over A and B.

Electronic Journal of Linear Algebra ISSN 1081-3810
A publication of the International Linear Algebra Society
Volume 18, pp. 613-627, October 2009

ELA

http://math.technion.ac.il/iic/ela

626

D. Cvetkovi´
c-Ili´
c and Y. Wei
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