Paper-12-22-2010. 117KB Jun 04 2011 12:03:09 AM

Acta Universitatis Apulensis
ISSN: 1582-5329

No. 22/2010
pp. 123-131

SOME RESULTS ON THE COMPLEX OSCILLATION THEORY OF
SOME DIFFERENTIAL POLYNOMIALS

Benharrat Bela¨ıdi and Abdallah El Farissi
Abstract. In this paper, we investigate the complex oscillation of the differ′′

ential polynomial gf = d2 f + d1 f + d0 f, where dj (j = 0,1,2) are meromorphic
functions with finite iterated p−order not all equal to zero generated by solutions of
′′
the differential equation f + A (z) f = 0, where A (z) is a transcendental meromorphic function with finite iterated p−order ρp (A) = ρ > 0.
2000 Mathematics Subject Classification: 34M10, 30D35.
1. Introduction and main results
Throughout this paper, we assume that the reader is familiar with the fundamental results and the standard notations of the Nevanlinna’s value distribution
theory (see [5, 7, 10]). In addition, we will use λ (f ) and λ (1/f ) to denote respectively the exponents of convergence of the zero-sequence and the pole-sequence of a
meromorphic function f , ρ (f ) to denote the order of growth of f , λ (f ) and λ (1/f )

to denote respectively the exponents of convergence of the sequence of distinct zeros and distinct poles of f . In order to express the rate of growth of meromorphic
solutions of infinite order, we recall the following definition.
Definition 1.1 [9, 11, 13] Let f be a meromorphic function. Then the hyper order
ρ2 (f ) of f (z) is defined by
log log T (r, f )
,
r→+∞
log r

ρ2 (f ) = lim

(1.1)

where T (r, f ) is the Nevanlinna characteristic function of f (see [5, 10]) .
Definition 1.2 [6, 9, 11] Let f be a meromorphic function. Then the hyper exponent
of convergence of the sequence of distinct zeros of f (z) is defined by


log log N r, f1
,

(1.2)
λ2 (f ) = lim
r→+∞
log r
123

B. Bela¨ıdi and A. El Farissi - Some results on the complex oscillation...


where N r, f1 is the counting function of distinct zeros of f (z) in {|z| < r}.
Consider the linear differential equation
′′

f + A (z) f = 0,

(1.3)

where A (z) is a transcendental meromorphic function. Many important results have
been obtained on the fixed points of general transcendental meromorphic functions
for almost four decades (see [14]). However, there are a few studies on the fixed points

..
of solutions of differential equations. In [12] , Wang and Lu have investigated the
fixed points and hyper order of solutions of second order linear differential equations
with meromorphic coefficients and their derivatives and have obtained the following
result:
Theorem A [12] Suppose that A (z) is a transcendental meromorphic function
satisfying δ (∞, A) = lim m(r,A)
T (r,A) > 0, ρ (A) = ρ < +∞. Then every meromorphic
r→+∞



′′

solution f (z) 6≡ 0 of the equation (1.3) satisfies that f and f , f all have infinitely
many fixed points and

 ′

 ′′


λ (f − z) = λ f − z = λ f − z = ρ (f ) = +∞,

(1.4)

 ′

 ′′

λ2 (f − z) = λ2 f − z = λ2 f − z = ρ2 (f ) = ρ.

(1.5)

In [9], Theorem A has been generalized to higher order linear differential equations by Liu Ming-Sheng and Zhang Xiao-Mei as follows :
Theorem B [9] Suppose that k ≥ 2 and A (z) is a transcendental meromorphic
function satisfying δ (∞, A) = δ > 0, ρ (A) = ρ < +∞. Then every meromorphic
solution f (z) 6≡ 0 of
f (k) + A (z) f = 0
(1.6)



′′

satisfies that f and f , f , ..., f (k) all have infinitely many fixed points and
 ′



λ (f − z) = λ f − z = ... = λ f (k) − z = ρ (f ) = +∞,

 ′



λ2 (f − z) = λ2 f − z = ... = λ2 f (k) − z = ρ2 (f ) = ρ.

124

(1.7)


(1.8)

B. Bela¨ıdi and A. El Farissi - Some results on the complex oscillation...

Recently, Theorem A has been generalized to differential polynomials by the
first author as follows:
Theorem C [2] Let A (z) be a transcendental meromorphic function of finite order
ρ (A) = ρ > 0 such that δ (∞, A) = δ > 0. Suppose, moreover, that either:
(i) all poles of f are of uniformly bounded multiplicity or that
(ii) δ (∞, f ) > 0.
Let dj (j = 0,1,2) be polynomials that are not all equal to zero, and let ϕ (z) 6≡ 0 be
a meromorphic
solution of
 function of finite order. If f (z) 6≡ 0 is a meromorphic
′′

1
(1.3) with λ f < +∞, then the differential polynomial gf = d2 f + d1 f + d0 f
satisfies λ (gf − ϕ) = +∞.
The first main purpose of this paper is to improve Theorem C. The first theorem

considers the case ” dj (j = 0,1,2) are meromorphic functions
and h 6≡ 0” which is
 

different from ” dj (j = 0,1,2) are polynomials and λ

1
f

< +∞” in Theorem C.

Let us denote by

α 1 = d1 ,

α0 = d0 − d2 A,



β 1 = −d2 A + d0 + d1 ,





(1.9)

β 0 = −d1 A − (d2 A) + d0 ,

(1.10)

h = α1 β 0 − α0 β 1 ,

(1.11)

where A , dj (j = 0.1.2) , ϕ are meromorphic functions. We first obtain:
Theorem 1.1 Let A (z) be a transcendental meromorphic function of finite order
ρ (A) = ρ > 0 such that δ (∞, A) = δ > 0. Let dj (j = 0,1,2) be meromorphic
functions with finite order not all equal to zero such that h 6≡ 0 and let ϕ (z) (6≡ 0) be

a meromorphic function of finite order such that α1 ϕ −β 1 ϕ 6≡ 0. Suppose, moreover,

that either:
(i) all poles of f are of uniformly bounded multiplicity or that
(ii) δ (∞, f ) > 0.
If f (z) 6≡ 0 is a meromorphic solution of (1.3) , then the differential polynomial
′′

gf = d2 f + d1 f + d0 f satisfies λ (gf − ϕ) = ρ (f ) = +∞ and λ2 (gf − ϕ) =
ρ2 (f ) = ρ (A) = ρ.
The second main purpose of this paper is to study the relation between differential polynomials generated by solutions of the differential equation (1.3) and
meromorphic functions of finite iterated order.
125

B. Bela¨ıdi and A. El Farissi - Some results on the complex oscillation...

Before we can state our second result, we need to give some definitions.
For the definition of the iterated order of a meromorphic function, we use the same
r
definition as in [6] , [3, p. 317]
 , [7, p. 129] . For all r ∈ R, we define exp1 r := e
and expp+1 r := exp expp r , p ∈ N.  We also define for all r sufficiently large

log1 r := log r and logp+1 r := log logp r , p ∈ N. Moreover, we denote by exp0 r :=
r, log0 r := r, log−1 r := exp1 r and exp−1 r := log1 r.
Definition 1.3 (see [6, 7]) Let f be a meromorphic function. Then the iterated
p−order ρp (f ) of f is defined by
logp T (r, f )
r→+∞
log r

ρp (f ) = lim

(p ≥ 1 is an integer) .

(1.12)

For p = 1, this notation is called order and for p = 2 hyper-order.
Definition 1.4 (see [6, 7]) The finiteness degree of the order of a meromorphic
function f is defined by







0,
for f rational,
min j ∈ N : ρj (f ) < +∞ , for f transcendental for which
i (f ) =
some j ∈ N with ρj (f ) < +∞ exists,



+∞,
for f with ρj (f ) = +∞ for all j ∈ N.


(1.13)

Definition 1.5 (see [8]) Let f be a meromorphic function. Then the iterated exponent of convergence of the sequence of distinct zeros of f (z) is defined by


logp N r, f1
(p ≥ 1 is an integer) .
(1.14)
λp (f ) = lim
r→+∞
log r
For p = 1, this notation is called exponent of convergence of the sequence of distinct
zeros and for p = 2 hyper-exponent of convergence of the sequence of distinct zeros
(see [9]).
Definition 1.6 (see [8]) Let f be a meromorphic function. Then the iterated exponent of convergence of the sequence of distinct fixed points of f (z) is defined by


1
logp N r, f −z
(p ≥ 1 is an integer) .
(1.15)
τ p (f ) = λp (f − z) = lim
r→+∞
log r
For p = 1, this notation is called exponent of convergence of the sequence of distinct
fixed points and for p = 2 hyper-exponent of convergence of the sequence of distinct
126

B. Bela¨ıdi and A. El Farissi - Some results on the complex oscillation...

fixed points (see [9]). Thus τ p (f ) = λp (f − z) is an indication of oscillation of
distinct fixed points of f (z) .
We obtain the following result:
Theorem 1.2 Let A (z) be a transcendental meromorphic function of finite iterated
p−order ρp (A) = ρ > 0 such that δ (∞, A) = δ > 0. Let dj (j = 0,1,2) be meromorphic functions with finite iterated p−order not all equal to zero such that h 6≡ 0
and let ϕ (z) (6≡ 0) be a meromorphic function of finite iterated p−order such that

α1 ϕ − β 1 ϕ 6≡ 0. Suppose, moreover, that either:
(i) all poles of f are of uniformly bounded multiplicity or that
(ii) δ (∞, f ) > 0.
If f (z) 6≡ 0 is a meromorphic solution of (1.3) , then the differential polynomial
′′

gf = d2 f + d1 f + d0 f satisfies λp (gf − ϕ) = ρp (f ) = +∞ and λp+1 (gf − ϕ) =
ρp+1 (f ) = ρp (A) = ρ.
Setting p = 1 and ϕ (z) = z in Theorem 1.2, we obtain the following corollary:
Corollary 1.1 Let A (z) be a transcendental meromorphic function of finite order
ρ (A) = ρ > 0 such that δ (∞, A) = δ > 0, let dj (j = 0,1,2) be meromorphic
functions with finite order not all equal to zero such that h 6≡ 0 and α1 − β 1 z 6≡ 0.
Suppose, moreover, that either:
(i) all poles of f are of uniformly bounded multiplicity or that
(ii) δ (∞, f ) > 0.
If f (z) 6≡ 0 is a meromorphic solution of (1.3) , then the differential polynomial
′′

gf = d2 f + d1 f + d0 f has infinitely many fixed points and satisfies τ (gf ) = ρ (f ) =
+∞, τ 2 (gf ) = ρ2 (f ) = ρ (A) = ρ.
2. Several Lemmas
We need the following lemmas in the proofs of our theorems.
Lemma 2.1 (see Remark
1.3 of [6]) . If f is a meromorphic function with i (f ) =
 ′
p ≥ 1, then ρp (f ) = ρp f .
Lemma 2.2 [8] If f is a meromorphic function with 0 < ρp (f ) < ρ (p ≥ 1) , then
ρp+1 (f ) = 0.
Lemma 2.3 [4] Let A0 , A1 , ..., Ak−1 , F 6≡ 0 be finite order meromorphic functions.
If f is a meromorphic solution with ρ (f ) = +∞ of the equation


f (k) + Ak−1 f (k−1) + ... + A1 f + A0 f = F,
then λ (f ) = λ (f ) = ρ (f ) = +∞.
127

(2.1)

B. Bela¨ıdi and A. El Farissi - Some results on the complex oscillation...

Lemma 2.4 [2] Let A0 , A1 , ..., Ak−1 , F (6≡ 0) be finite order meromorphic functions.
If f is a meromorphic solution of the equation (2.1) with ρ (f ) = +∞ and ρ2 (f ) = ρ,
then f satisfies λ2 (f ) = λ2 (f ) = ρ2 (f ) = ρ.
Lemma 2.5 [2] Let k ≥ 2 and A (z) be a transcendental meromorphic function of
finite order ρ (A) = ρ > 0 such that δ (∞, A) = δ > 0. Suppose, moreover, that
either:
(i) all poles of f are of uniformly bounded multiplicity or that
(ii) δ (∞, f ) > 0.
Then every meromorphic solution f (z) 6≡ 0 of (1.6) satisfies ρ (f ) = +∞ and
ρ2 (f ) = ρ (A) = ρ.
Lemma 2.6 [1] Let k ≥ 2 and A (z) be a transcendental meromorphic function
of finite iterated p−order ρp (A) = ρ > 0 such that δ (∞, A) = δ > 0. Suppose,
moreover, that either:
(i) all poles of f are of uniformly bounded multiplicity or that
(ii) δ (∞, f ) > 0.
Then every meromorphic solution f (z) 6≡ 0 of (1.6) satisfies i (f ) = p + 1 and
ρp (f ) = +∞, ρp+1 (f ) = ρp (A) = ρ.
Lemma 2.7 [1] Let A0 , A1 , ..., Ak−1 , F 6≡ 0 be finite iterated p−order meromorphic
functions. If f is a meromorphic solution with ρp (f ) = +∞ and ρp+1 (f ) = ρ <
+∞ of the equation (2.1) , then λp (f ) = ρp (f ) = +∞ and λp+1 (f ) = ρp+1 (f ) = ρ.
Lemma 2.8 Let A (z) be a transcendental meromorphic function with finite iterated p−order ρp (A) = ρ > 0 such that δ (∞, A) = δ > 0, let dj (j = 0,1,2) be
meromorphic functions with finite iterated p−order not all equal to zero such that
h 6≡ 0. Suppose, moreover, that either:
(i) all poles of f are of uniformly bounded multiplicity or that
(ii) δ (∞, f ) > 0.
If f (z) 6≡ 0 is a meromorphic solution of (1.3) , then the differential polynomial
′′

gf = d2 f +d1 f +d0 f satisfies i (gf ) = p+1 and ρp (gf ) = ρp (f ) = +∞, ρp+1 (gf ) =
ρp+1 (f ) = ρp (A) = ρ.
Proof. Suppose that f (6≡ 0) is a meromorphic solution of equation (1.3) . Then by
′′

Lemma 2.6, we have ρp (f ) = +∞ and ρp+1 (f ) = ρp (A) = ρ. Set gf = d2 f + d1 f +
′′
d0 f, we need to prove ρp (gf ) = +∞ and ρp+1 (gf ) = ρ. By substituting f = −Af
into gf , we get

gf = d1 f + (d0 − d2 A) f.
(2.18)
Differentiating both a sides of equation (2.18), we obtain










gf = (−d2 A + d0 + d1 )f + (−d1 A − (d2 A) + d0 )f.
128

(2.19)

B. Bela¨ıdi and A. El Farissi - Some results on the complex oscillation...

Then by (1.9) , (1.10), (2.18) and (2.19) , we have



α1 f + α0 f = gf ,




(2.20)

β 1 f + β 0 f = gf .

(2.21)

h = α1 β 0 − β 1 α0 .

(2.22)

Set
By the condition h 6≡ 0 and (2.20) − (2.22) , we get


f=

α1 gf − β 1 gf
h

.

(2.23)

If ρp (gf ) < +∞, then by (2.23) and Lemma 2.1 we obtain ρp (f ) < +∞, and this is
a contradiction. Hence ρp (gf ) = ρp (f ) = +∞.
Now we prove that ρp+1 (gf ) = ρp+1 (f ) = ρp (A) = ρ. By (2.18), Lemma 2.1 and
Lemma 2.2 we have ρp+1 (gf ) 6 ρp+1 (f ) and by (2.23) we get ρp+1 (f ) 6 ρp+1 (gf ) .
Hence ρp+1 (gf ) = ρp+1 (f ) = ρp (A) = ρ.
Lemma 2.9 Let A (z) be a transcendental meromorphic function with finite order
ρ (A) = ρ > 0 such that δ (∞, A) = δ > 0, let dj (j = 0,1,2) be meromorphic
functions with finite order not all equal to zero such that h 6≡ 0. Suppose, moreover,
that either:
(i) all poles of f are of uniformly bounded multiplicity or that
(ii) δ (∞, f ) > 0.
If f (z) 6≡ 0 is a meromorphic solution of (1.3) , then the differential polynomial
′′

gf = d2 f + d1 f + d0 f satisfies ρ (gf ) = ρ (f ) = +∞ and ρ2 (gf ) = ρ2 (f ) = ρ (A) =
ρ.
Proof. Suppose that f (6≡ 0) is a meromorphic solution of equation (1.3) . Then
by Lemma 2.5, we have ρ (f ) = +∞ and ρ2 (f ) = ρ (A) = ρ. By using a similar
arguments as in the proof of Lemma 2.8, we can prove Lemma 2.9.
3. Proof of Theorem 1.1
Suppose that f (z) 6≡ 0 is a meromorphic solution of (1.3) . Then by Lemma 2.5
′′

we have ρ (f ) = +∞ and ρ2 (f ) = ρ (A) = ρ. Set w (z) = d2 f + d1 f + d0 f − ϕ.
Since ρ (ϕ) < +∞, then by Lemma 2.9 we have ρ (w) = ρ (gf ) = ρ (f ) = +∞ and
129

B. Bela¨ıdi and A. El Farissi - Some results on the complex oscillation...

ρ2 (w) = ρ2 (gf ) = ρ2 (f ) = ρ (A) = ρ. In order to prove λ (gf − ϕ) = +∞ and
λ2 (gf − ϕ) = ρ (A) = ρ we need to prove only λ (w) = +∞ and λ2 (w) = ρ (A) = ρ.
Substituting gf = w + ϕ into (2.23), we get


α1 w − β 1 w
+ ψ,
f=
h
where

(3.1)



α1 ϕ − β 1 ϕ
ψ=
.
(3.2)
h
Substituting (3.1) into equation (1.3) , we obtain
 ′′

α1 ′′′
′′

w + φ2 w + φ1 w + φ0 w = − ψ + A (z) ψ = W,
(3.3)
h

where φj (j = 0, 1, 2) are meromorphic functions with ρ φj < +∞ (j = 0, 1, 2).
By ρ (ψ) < +∞ and the condition ψ 6≡ 0, it follows by Lemma 2.5 that W 6≡ 0.
Then by Lemma 2.3 and Lemma 2.4, we obtain λ (w) = λ (w) = ρ (w) = +∞ and
λ2 (w) = λ2 (w) = ρ2 (w) = ρ, i.e., λ (gf − ϕ) = ρ (f ) = +∞ and λ2 (gf − ϕ) =
ρ2 (f ) = ρ (A) = ρ.
4. Proof of Theorem 1.2
Suppose that f (z) 6≡ 0 is a meromorphic solution of (1.3) . Then by Lemma 2.6 we
′′

have ρp (f ) = +∞ and ρp+1 (f ) = ρp (A) = ρ. Set w (z) = d2 f + d1 f + d0 f − ϕ.
Since ρp (ϕ) < +∞, then by Lemma 2.8 we have ρp (w) = ρp (gf ) = ρp (f ) = +∞
and ρp+1 (w) = ρp+1 (gf ) = ρp+1 (f ) = ρp (A) = ρ. In order to prove λp (gf − ϕ) =
+∞ and λp+1 (gf − ϕ) = ρp (A) = ρ, we need to prove only λp (w) = +∞ and
λp+1 (w) = ρp (A) = ρ. Substituting gf = w + ϕ into (2.23) and using a similar
reasoning as in the proof of Theorem 1.1, we get that
 ′′

α1 ′′′
′′

w + φ2 w + φ1 w + φ0 w = − ψ + A (z) ψ = W,
(4.1)
h

where φj (j = 0, 1, 2) are meromorphic functions with ρp φj < ∞ (j = 0, 1, 2). By
ρp (ψ) < +∞ and the condition ψ 6≡ 0, it follows by Lemma 2.6 that W 6≡ 0. By
Lemma 2.7, we obtain λp (w) = ρp (w) = +∞ and λp+1 (w) = ρp+1 (w) = ρ, i.e.,
λp (gf − ϕ) = ρp (f ) = +∞ and λp+1 (gf − ϕ) = ρp+1 (f ) = ρp (A) = ρ.

130

B. Bela¨ıdi and A. El Farissi - Some results on the complex oscillation...

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Benharrat Bela¨ıdi and Abdallah El Farissi
Department of Department of Mathematics
Laboratory of Pure and Applied Mathematics
University of University of Mostaganem
Address B. P. 227 Mostaganem-(Algeria)
email: belaidi@univ-mosta.dz; elfarissi.abdallah@yahoo.fr

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