Convergence of the outlying measures

For C = inf {η i , i ∈ [1; r]}, we get η i C + 1 − C ≥ C 2 0. We choose the following function ξx = r Y j=1 1 − x A 2 j + r X i=1 x A 2 i r Y j=1, j 6=i x − A 2 j A 2 i − A 2 j p C + 1η i − C. In Step 2.1 and 2.2, the stationary symmetric measures associated to ξ converge to p δ + P r i=1 p i 2 € δ A i + δ −A i Š . Step 3. It remains to prove that all conditions V-1–V-8 are satisfied by the function V defined in Step 1. The only one which really needs to be carefully analyzed is the existence of three solutions to the equation V ′ x = 0. Since W defined by 2.7 and 2.8 is an even function, ρx = W ′ x x is well defined and represents some even polynomial function which tends to + ∞ as |x| becomes large. Hence, there exists some R 0 large enough such that ρ is strictly decreasing on the interval ] − ∞; −R] and strictly increasing on [R; +∞[. Let us now define α ′ = sup z ∈[−R;R] ρz. Then, for any α α ′ , the equation ρz = α admits exactly two solutions. This implies the existence of exactly three solutions to V ′ x = 0 i.e. condition V-3.

2.2 Convergence of the outlying measures

In the preceding section, we analyzed the convergence of the unique symmetric invariant measure u ǫ as ǫ → 0. In [5], we proved that the set of invariant measures does not only contain u ǫ . In particular, for ǫ small enough, there exist asymmetric ones. We suppose therefore that ε is less than the critical threshold below which the measures u + ε and u − ε defined by 2.2 and 2.3 exist. We shall focus our attention on their asymptotic behavior. Let us recall the main property concerning the mean m ± ǫ of these measures: for all δ 0, there exists ε 0 small enough such that m ± ε − ±a + V 3 ±a 4V ′′ a α + V ′′ a ε ≤ δε, ǫ ≤ ǫ . 2.15 Here a and −a are defined by V-3. Let us note that we do not assume V ′′ to be a convex function nor u + ε resp. u − ε to be unique. Theorem 2.4. The invariant measure u + ε resp. u − ε defined by 2.2 and 2.3 converges weakly to δ a resp. δ −a as ε tends to 0. Proof. We just present the proof for u + ε since the arguments used for u − ε are similar. Let us define W + ε x = V x + α 2 x 2 − αm + εx. Let f a continuous non-negative bounded function on R whose maximum is denoted by M = sup z ∈R f z. According to 2.2, we have Z R f xu + ε xd x = R R f x exp ” − 2 ε W + ε x — d x R R exp ” − 2 ε W + ε x — d x . 2.16 2095 We introduce U y = V y + α 2 y 2 − αa y. By 2.15, for ǫ small enough, we obtain Z R exp − 2 ε W + ε y d y ≤ Z R ξ + y exp − 2 ε U y d y where ξ + y = exp ¨ − αV 3 a 2V ′′ a α + V ′′ a y + 2 αδ y « . By Lemma A.4 in [5] in fact a slight modification of the result: the function f m appearing in the statement needs just to be C 3 -continuous in a small neighborhood of the particular point x µ , the following asymptotic result as ǫ → 0 yields: Z R ξ + y exp − 2 ε U y d y = Ç πε α + V ′′ a exp − 2 ε Ua ξ + a1 + o1. We can obtain the lower-bound by similar arguments, just replacing ξ + y by ξ − y where ξ − y = exp ¨ − αV 3 a 2V ′′ a α + V ′′ a y − 2αδ y « . Therefore, for any η 1, there exists some ǫ 1 0, such that 1 η ξ − a ≤ r U ′′ a πε e 2Ua ε Z R e − 2 ε W + ε x d x ≤ η ξ + a, 2.17 for ǫ ≤ ǫ 1 . In the same way, we obtain some ǫ 2 0, such that 1 η f a ξ − a ≤ r U ′′ a πε e 2Ua ε Z R f xe − 2 ε W + ε x d x ≤ η f aξ + a, 2.18 for ǫ ≤ ǫ 2 . Taking the ratio of 2.18 and 2.17, we immediately obtain: 1 η 2 f a exp [ −4αaδ] ≤ Z R f xu + ε xd x ≤ η 2 f a exp [4 αaδ] , for ǫ ≤ minǫ 1 , ǫ 2 . δ is arbitrarily small and η is arbitrary close to 1, so we deduce the convergence of R R f xu + ε xd x towards f a.

2.3 The set of limit measures

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