Penghitungan Stationing Kontrol Overlaping

commit to user 85

3.3 Penghitungan Stationing

Data – data tikungan : d A – 1 : 947,484 m d 1 – 2 : 454,588 m d 2 – 3 : 498,121 m d 3 – 4 : 531,507 m d 4 – B : 553,263 m 1. Tikungan PI 1 S-S Tc 1 = 105,033 m Lc 1 = 209,467 m 2. Tikungan PI 2 S-C-S Tt 2 = 133,597 m Ls 2 = 34 m Lc 2 = 81,838 m 3. Tikungan PI 3 S-C-S Tt 3 = 107,533 m Ls 3 = 34 m Lc 3 = 71,791 m 4. Tikungan PI 4 S-C-S Tt 4 = 54,373 m Ls 4 = 45 m Lc 4 = 12,608 m commit to user 86 STA A = 0 + 000 STA PI 1 = Sta A + d A – 1 = 0 + 000 + 947,484 = 0 + 947,484 m STA TC 1 = Sta PI 1 – Tc 1 =0 + 947,484 – 105,033 = 0 + 842,451 m STA CT 1 = Sta TC 1 + Lc 1 = 0 + 842,45 + 209,467 = 1 + 051,918 m STA PI 2 = Sta CT 1 + d 1-2 – Tc 1 = 1 + 051,918 + 454,588 – 105,033 = 1 + 401,473 m STA TS 2 = Sta PI 2 – Tt 2 =1 + 401,473 – 133,597 = 1 + 267,876 m STA SC 2 = Sta TS 2 + Ls 2 = 1 + 267,876 + 34 = 1 + 301,876 m STA CS 2 = Sta SC 2 + Lc 2 = 1 + 301,876 + 81,838 = 1 + 383,714 m commit to user 87 STA ST 2 = Sta CS 2 + Ls 2 = 1 + 383,714 + 34 = 1 + 417,714 m STA PI 3 = Sta ST 2 + d 2-3 – Tt 2 = 1 + 417,714 + 498,121 – 133,597 = 1 + 782,238 m STA TS 3 = Sta PI 3 – Tt 3 =1 + 782,238 – 107,533 = 1 + 674,705 m STA SC 3 = Sta TS 3 + Ls 3 = 1 + 674,705 + 34 = 1 + 708,705 m STA CS 3 = Sta SC 3 + Lc 3 = 1 + 708,705 + 71,791 = 1 + 780,496 m STA ST 3 = Sta CS 3 + Ls 3 = 1 + 780,496 + 34 = 1 + 814,496 m STA PI 4 = Sta ST 3 + d 3-4 – Tt 3 = 1 + 814,496 + 531,507 – 107,533 = 2 + 238,47 m STA TS 4 = Sta PI 4 – Tt 4 =2 + 238,47 – 54,373 = 2 + 184,097 m commit to user 88 STA SC 4 = Sta TS 4 + Ls 4 = 2 + 184,097 + 45 = 2 + 229,097 m STA CS 4 = Sta SC 4 + Lc 4 = 2 + 229,097 + 12,608 = 2 + 241,705 m STA ST 4 = Sta CS 4 + Ls 4 = 2 + 241,705 + 45 = 2 + 286,705 m STA B = Sta ST 4 + d 4-B – Tt 4 = 2 + 286,705 + 553,263 – 54,373 = 2 + 785,595 m

3.4 Kontrol Overlaping

Diketahui: Diketahui : det 11 , 11 3600 40000 40 m ja m km ren V    Syarat overlapping d ≥ 3 dt ≥ 3 × 11,11 mdt .dt d ≥ 33,33 m Aman commit to user 89 Koordinat : A = 0 ; 0 PI – 1 = 325 ; -890 PI – 2 = 550 ; -1285 PI – 3 = 700 ; -810 PI – 4 = 1050 ; -1210 B = 1600 ; -1150 Jembatan 1 = 190 ; -530 Jembatan 2 = 435 ; -1075 Jembatan 3 = 620 ; -1045 Jembatan 4 = 810 ; -970 Jembatan 5 = 1235 ; -1175 Jarak A – Jembatan 1 =     m 028 , 563 530 190 2 2      Jarak Jembatan 1 – PI 1 =     m 480 , 384 530 890 190 325 2 2      Jarak PI 1 – Jembatan 2 =     m 232 , 215 890 1075 325 435 2 2      Jarak Jembatan 2 – PI 2 =     m 426 , 239 1075 1285 435 550 2 2      Jarak PI 2 – Jembatan 3 =     m 250 1285 1045 550 620 2 2      Jarak Jembatan 3 – PI 3 =     m 244 , 248 1045 810 620 700 2 2      Jarak PI 3 – Jembatan 4 =     m 165 , 194 810 970 700 810 2 2      Jarak Jembatan 4 – PI 4 =     m 411 , 339 970 1210 810 1050 2 2      commit to user 90 Jarak PI 4 – Jembatan 5 =     m 282 , 188 1210 1175 1050 1235 2 2      Jarak Jembatan 5 – B =     m 855 , 365 1175 1150 1235 1600 2 2      STA Jembatan 1 = STA A + Jarak A - Jembatan 1 = 0 + 000 + 563,028 = 0 + 563,028 m STA Jembatan 2 = STA CT 1 + Jarak PI 1 – Jembatan 2 – Tc 1 = 1 + 051,918 + 215,232 – 105,033 = 1 + 162,117 m STA Jembatan 3 = STA ST 2 + Jarak PI 2 - Jembatan 1 – Tt 2 = 1 + 417,714 + 250 – 133,597 = 1 + 534,117 m STA Jembatan 4 = STA ST 3 + Jarak PI 3 – Jembatan 4 – Tt 3 = 1 + 814,496 + 194,165 – 107,533 = 1 + 901,128 m STA Jembatan 5 = STA ST 4 + Jarak PI 4 – Jembatan 5 – Tt 4 = 2 + 286,705 + 188,282 – 54,373 = 2 + 420,614 m Sehingga agar tidak over laping d n 33,33 m 1. A – Jembatan 1 d 1 = STA Jembatan 1 - ½ asumsi – STA A = 0+ 563,028 – ½ x 30 – 0+ 000 = 548,028 m 33,33 m  Aman commit to user 91 2. Jembatan 1 – PI 1 d 2 = STA TC 1 - STA Jembatan 1 - ½ asumsi = 0 + 842,451 – 0 + 563,028 - ½ x 30 = 264,423 m 33,33 m  Aman 3. PI 1 – Jembatan 2 d 3 = STA Jembatan 2 - ½ asumsi – STA CT 1 = 1 + 162,117 - ½ x 30 – 1 + 051,918 = 95,199 m 33,33 m  Aman 4. Jembatan 2 – PI 2 d 4 = STA TS 2 – STA Jembatan 2 - ½ asumsi = 1 + 267,876 – 1 + 162,117 − ½ x 30 = 90,759 m 33,33 m  Aman 5. PI 2 – Jembatan 3 d 5 = STA Jembatan 3 - ½ asumsi – STA ST 2 = 1 + 534,117 - ½ x 30 – 1 + 417,714 = 101,403 m 33,33 m  Aman 6. Jembatan 3 – PI 3 d 6 = STA TS 3 – STA Jembatan 3 - ½ asumsi = 1 + 674,705 – 1+ 534,117 − ½ x 30 = 125,588 m 33,33 m  Aman 7. PI 3 – Jembatan 4 d 7 = STA Jembatan 4 - ½ asumsi – STA ST 3 = 1 + 901,128 - ½ x 30 – 1 + 814,496 = 71,632 m 33,33 m  Aman commit to user 92 8. Jembatan 4 – PI 4 d 8 = STA TS 4 – STA Jembatan 4 - ½ asumsi = 2 + 184,097 – 1 + 901,128 − ½ x 30 = 267,969 m 33,33 m  Aman 9. PI 3 – Jembatan 4 d 9 = STA Jembatan 5 - ½ asumsi – STA ST 4 = 2 + 420,614 - ½ x 30 – 2 + 286,705 = 118,909 m 33,33 m  Aman 10. Jembatan 5 dengan B d 10 = STA B – STA Jembatan 5 - ½ asumsi = 2 + 785,595 – 2 + 420,614 - ½ x 30 = 349,981 m 33,33 m  Aman commit to user 93 commit to user 94

3.5 Perhitungan Alinemen Vertikal