Data Analysis METHOD OF RESEARCH
42
Table 4.2 The Highest to The Smallest Scores
No Name
Initial Total of the Correct
Answer Score
X X
2
1 30 Fi XI
28 93
8.649 2
18 Un XI 22
73 5.329
3 26 My XI
22 73
5.329 4
08 Vi XI 21
70 4.900
5 13 Pu XI
21 70
4.900 6
47 Ab XI 21
70 4.900
7 27 Vi XI
20 66
4.356 8
45 Cl XI 20
66 4.356
9 07 Ar XI
19 63
3.969 10 25 Ra XI
19 63
3.969 11 48 Jo XI
19 63
3.969 12 28 Ma XI
19 63
3.969 13 29 Yo XI
19 63
3.969 14 03 Lo XI
18 60
3.600 15 06 Ant XI
18 60
3.600 16 17 Ko XI
18 60
3.600 17 24 Di XI
18 60
3.600 18 35 Er XI
18 60
3.600 19 43 Au XI
18 60
3.600 20 09 Jo XI
17 56
3.136 21 10 Lu XI
17 56
3.136 22 20 Ra XI
17 56
3.136 23 21 Fr XI
17 56
3.136 24 22 Ma XI
17 56
3.136 25 23 So XI
17 56
3.136 26 33 St XI
17 56
3.136 27 37 Du XI
17 56
3.136
43
No Name
Initial Total of the Correct
Answer Score
X X
2
28 44 No XI 17
56 3.136
29 50 Vi XI 17
56 3.136
30 01 Wid XI 16
53 3.136
31 02 Be XI 16
53 3.136
32 12 Ja XI 16
53 3.136
33 34 Ek XI 16
53 3.136
34 60 Ma XI 16
53 3.136
35 31 Ra XI 15
50 2.500
36 32 Ju XI 14
46 2.116
37 39 No XI 14
46 2.116
38 49 Ho XI 14
46 2.116
39 04 He XI 13
43 1.849
40 41 Am XI 13
43 1.849
41 46 Sa XI 13
43 1.849
42 51 Mi XI 13
43 1.849
43 52 Ke XI 13
43 1.849
44 15 Cr XI 12
40 1.600
45 16 Je XI 12
40 1.600
46 36 Ci XI 12
40 1.600
47 42 He XI 12
40 1.600
48 55 Eg XI 12
40 1.600
49 56 Gr XI 12
40 1.600
50 05 Ev XI 11
36 1.296
51 11 Pe XI 11
36 1.296
52 14 In XI 11
36 1.296
53 38 Cy XI 10
33 1.089
54 40 Jo XI 10
33 1.089
55 57 Ri XI 10
33 1.089
56 58 Me XI 10
33 1.089
44 After being ranked, the highest score of the students’ test result in using
conditional sentences is 93 and the lowest score is 23. It is also found that there are 922 the correct answers of 60 students which describe the correct answer on average
15 and the total of score is 3.077 which describe students on average 51,2 and the quadrate of total score is 170.370.
After finishing the tabulation of the raw scores, the standard deviation of the test result is found out in following formulation:
SD = 1 }
N
Where, SD
= standard deviation ∑X
= the total of correct answer N
= the number of respondents ∑X
2
= the quadrate of the total score
No Name
Initial Total of the Correct
Answer Score
X X
2
57 53 Fe XI 9
30 900
58 54 El XI 9
30 900
59 59 Ch XI 9
30 900
60 19 Dw XI
7 23
529
TOTAL 922
3.077 170.370
45 So,
SD = 1
} N
= 1 √ {60 x 170.370 – 3.077
2
} 60
= 1 √ 10.222.200 – 9.467.929
60
= 1 √ 754.271
60
= 1 868,49 6
= 14,47
= 14 rounded
The calculation of mean is:
=
∑X N
=
922 60
= 15,36
= 15 rounded
After knowing the mean and the standard Deviation, then the coefficient of the reliability is calculated:
46 KRr =
]
= ]
= ]
= ]
=
1,034 1 – 0,038 =
1,034 x 0,962 =
0,99
The calculation above shows that the reliability of the test is 0,99. So, the reliability of the test is very high. It is based on Arikunto 1986:93, the standard of
reliability is: 0,00 – 0,40
= The reliability is low
0,41 – 0,70 =
The reliability is significant 0,71 – 0,90
= The reliability is high
0,91 – 1,00 =
The reliability is very high
47