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n = s
b
= 120
1000 = 8,33 ~ 9
As yang timbul = 9. ¼ . π . 10
2
= 706,5
mm
2
As
perlu
686,38…..…ok Dipakai tulangan
∅ 10 – 120 mm
5.6. Penulangan tumpuan arah y
Mu = 1200,46 kgm = 12,0046.10
6
Nmm Mn =
φ Mu
= =
8 ,
10 .
12,0046
6
15,0056.10
6
Nmm Rn
= =
2
.dx b
Mn =
2 6
95 .
1000 10
. 15,0056
1,663 Nmm
2
m = 294
, 11
25 .
85 ,
240 .
85 ,
= =
c f
fy
ρ
perlu
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− fy
Rn .
m 2
1 1
. m
1
= . 294
, 11
1 ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− 240
663 ,
1 .
294 ,
11 .
2 1
1 = 0,0072
ρ ρ
max
ρ ρ
min
, di pakai ρ
perlu
= 0,0072 As
perlu
= ρ
perlu
. b . dx = 0,0072 . 1000 . 95
= 686,38 mm
2
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Digunakan tulangan ∅ 10
As = ¼ . π . 10
2
= 78,5
mm
2
S =
perlu
As b
As. =
38 ,
686 1000
. 5
, 78
= 114,368 ~ 120 mm
n = s
b
= 120
1000 = 8,33 ~ 9
As yang timbul = 9. ¼ . π . 10
2
= 706,5
mm
2
As
perlu
686,38…..…ok Dipakai tulangan
∅ 10 – 120 mm
5.7. Penulangan lapangan arah x
Mu = 528,77 kgm = 5,2877.10
6
Nmm Mn =
φ Mu
=
6 6
10 .
610 ,
6 8
, 10
. 5,2877
= Nmm
Rn =
=
2
.dx b
Mn =
2 6
95 .
1000 10
. 610
, 6
0,732 Nmm
2
m = 294
, 11
25 .
85 ,
240 .
85 ,
= =
c f
fy
ρ
perlu
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− fy
Rn .
m 2
1 1
. m
1
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− 240
732 ,
. 294
, 11
. 2
1 1
. 294
, 11
1 =
0,0031
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ρ ρ
max
ρ ρ
min
, di pakai ρ
perlu
= 0,0031 As =
ρ
min
. b . dx = 0,0031. 1000 . 95
= 295,24
mm
2
Digunakan tulangan ∅ 10
As = ¼ .
π . 10
2
= 78,5
mm
2
S =
perlu
As b
As .
= 24
, 295
1000 .
5 ,
78 = 265,885 ~ 250 mm
Jarak maksimum = 2 x h = 2 x 120
= 240
mm n =
s b
= 240
1000 = 4,2
∼ 5 As yang timbul = 5. ¼ .
π . 10
2
= 392,5
mm
2
As295,24....…ok Dipakai tulangan
∅ 10 – 240 mm
5.8. Penulangan lapangan arah y
Mu = 443,03 kgm = 4,4303.10
6
Nmm Mn =
φ Mu
=
6 6
10 .
538 ,
5 8
, 10
. 4,4303
= Nmm
Rn =
=
2
.dx b
Mn =
2 6
95 .
1000 10
. 538
, 5
0,614 Nmm
2
m = 294
, 11
25 .
85 ,
240 .
85 ,
= =
c f
fy
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ρ
perlu
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− fy
Rn .
m 2
1 1
. m
1
= ⎟⎟⎠
⎞ ⎜⎜⎝
⎛ −
− 240
614 ,
. 294
, 11
. 2
1 1
. 294
, 11
1 =
0,0026 ρ
ρ
max
ρ ρ
min
, di pakai ρ
perlu
= 0,0026 As =
ρ
min
. b . dx = 0,0026. 1000 . 95
= 247,29
mm
2
Digunakan tulangan ∅ 10
As = ¼ .
π . 10
2
= 78,5
mm
2
S =
perlu
As b
As. =
29 ,
247 1000
. 5
, 78
= 317,14 ~ 300 mm Jarak maksimum = 2 x h
= 2 x 120 =
240 mm
n = s
b
= 240
1000 = 4,2
∼ 5 As yang timbul = 5. ¼ .
π . 10
2
= 392,5
mm
2
As247,29...…ok Dipakai tulangan
∅ 10 – 240 mm
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5.9. Rekapitulasi Tulangan
