Normality Test Homogeneity Test Hypothesis Testing

30 10 9 -9.78 -2.35 95.65 5.52 31 32 14 12.22 2.65 149.33 7.02 32 13 8 -6.78 -3.35 45.97 11.22 33 22 3 2.22 -8.35 4.93 69.72 34 8 6 -11.78 -5.35 138.77 28.62 35 9 1 -10.78 -10.35 116.21 107.12 36 17 6 -2.78 -5.35 7.73 28.62 37 11 10 -8.78 -1.35 77.09 1.82 ∑ 732 420 0.14 0.05 3904.27 2212.43 Mean 19.78 11.35 From Table 4.15, it could be seen that the average of gained score of experimental class was higher than controlled class. It meant that there was effectiveness of using pictures in experimental class in students’ writing of recount text. The data were calculated based on the step of the test. The formulation as followed: 1. Determining mean of variable XM x , with the formula:

2. Determining

1 mean of variable YM y , with the formula: 3. Determining of standard of deviation XSD x , with the formula: √ √ √ 4. Determining of standard of deviation YSD y , with the formula: √ √ √ 5. Determining of standard errors mean of variable XSE mx , with the formula: √ √ 6. Determining of standard errors mean of variable YSE my , with the formula: √ √ 7. Determining of standard errors of different mean of variable X and mean of variable Y, with the formula: √ √ √ √ = 2.13 8. Determining with the formula: df = N 1 +N 2 -2 = 37+37-2 =72 Based on the hypothesis that had been explained in chapter III, which was: Ho: There was effectiveness of using pictures on students’ writing of recount text. Ha: There was no effectiveness of using pictures on students’ writing of recount text. To prove the hypothesis, the data obtained from experimental and controlled class were calculated by using t-test formula with assumption as follows: If t o ≥ t table the Null Hypothesis H o is rejected, it means that there was effectiveness of using picture on students’ writing of recount text. In the other hand, if t o ≤ t table the Null Hypothesis is accepted, it means that there was no effectiveness of using picture on students’ writing of recount text. Based on the description of the calculation above, it could be concluded that: a The value of t table in the significance 1 was 2.63 and 5 was 1.99 b The value of t was 3.96 c So, the result was 1.99 3.96 2.63. It meant that t o t observation was higher than t t t table.

C. Interpretation of the Result

The discussion of the research was based on the research question, which was to know whether there was effectiveness of using pictures on students’ writing of recount text at the tenth grade students of SMA Negeri 9 Kota Tangerang Selatan. Based on the post- test result was known that the students’ writing of recount text showed difference in both experimental class and controlled class. The average of pre-test score in experimental class was 61.24 and in controlled class was 52.46. Comparing with the average score of post-test, experimental class had 81.02 and controlled class had 63.81. The post-test in experimental was higher than the controlled class. Each class had 37 students, so the degree of freedom df was 37 + 37 – 2 = 72. The critical value with df 78 in significance of 5 was 1.99 while in significance 1 was 2.63. The t o was 3.96. Therefore, t o = 3.96 was higher that the degree of significance 5 and 1, 1.99 3.96 2.63, which meant that the null hypothesis was rejected and the alternative hypothesis was accepted. Related to the theories in chapter II about writing, recount text and picture, picture can be used in a class because of the two advantages of picture for teaching and learning, which are sufficient amount of language and help students to focus attention and develop critical judgment. Therefore, in teaching writing of recount text by using pictures was effective based on the result of the study and the theory. It could be concluded that using pictures was effective on students’ writing on recount text at the tenth grade students of SMA Negeri 9 Kota Tangerang Selatan.