Place And Time of Reseach  Place

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CHAPTER IV FINDING AND DISCUSSION

This chapter focuses on the findings and the discussions of the study. The findings discus some findings in the study that gathers from questionnaire while discussion talks about discussion about that finding and some assumptions according that finding. A. Finding On this part will talk about the interpretation of X 1 , X 2 and Y. Total statistical description can be seen in the table below: Table 4.1 Descriptive Statistics Mean Std. Deviation N Student’s achievement 74.4545 9.21507 88 Visual’s learning style 59.0114 10.59114 88 Parent’s attention 97.8750 19.41016 88 The Table 4.1 above, it is known that Mean is the middle line between the numbers. The Mean for visual learning style is 59.01, that mean visual learning style has middle path 59.01, this number has middle in Likert Scale, while Mean for parents attention is 97.87. this mean that parents attention has good in the Likert Scale, The Mean for student’s achievement is 74.45 that mean student achievement has middle in Scale Likert. While standard deviation for visual learning style is 10.59, while for parents attention is 19.41, in student’s achievement is 9.21. 1. Pre-requisite Analysis a Normality Test for X 1 and X 2 and Y To measure the normality, the writer use formula of Pearson Product Moment: 39 n∑XY - ∑X ∑Y rxy = ______________________ √ n.∑X² - ∑X² N.∑Y²-∑Y² Note : rxy : Correlation coefficient N : Number of respondents x : Distribution of student who gain learning experience y : Distribution of students outcome ∑y : Total score of students outcome ∑xy : Total number of x multipleb by y x² : Guarded from x y² : guarded from y From the formula above, it gained: Table 4.2 Normality Test for X 1 , X 2 and Y Normality Test Visual learning style Parents’ attention Student’s achieveme nt N 88 88 88 Normal Parameters a Mean 82.1136 79.4773 74.4545 Std. Deviation 6.50629 11.28928 9.21507 Most Extreme Differences Absolute .137 .086 .113 Positive .075 .086 .112 Negative -.137 -.048 -.113 Kolmogorov-Smirnov Z 1.283 .807 1.057 Asymp. Sig. 2-tailed .074 .533 .214 40 From the Table 4.2 above, visual learning style has sig 0.074, it means 0.074 0.05, that explains Visual learning style has normal distribution, while parents attention gained sig 0.533, It has bigger than 0.05 or it stated 0.533 0.05.that explain parents attention has normal distribution. S tudent’s achievement scored 0.214. it is bigger than 0.05 or 0.214 0.05 that means students achievement has normal distribution. To summarize, it knows that all sig. has more than r-critics 0.05 that explains all variables have normal distribution. b. Homogenity Test The formula used is: nS²- ∑Si² α = ___________ n-1 S² Note : α : alpha coefficient n : amount of respondent S² : variants total of score Sі² : variants of item. From the formula, it gained: