B.2.3 Burner B-101
Fungsi : Tempat pembakaran gas alam sebagai sumber panas preheater B-102
CpdT N
CpdT N
C H
r dT
dQ
in s
out s
r 303
298 1136
298
30 .
a. Menghitung Panas Reaksi Pembakaran Gas Alam ∆Hr
Reaksi pembakaran gas alam: CH
4g
+ 2O
2g
CO
2g
+ 2H
2
O
g
………1 C
2
H
6g
+
2 7
O
2g
2CO
2g
+ 3H
2
O
g
………2 C
3
H
8g
+ 5O
2g
3CO
2g
+ 4H
2
O
g
………3 C
4
H
10g
+
2 13
O
2g
4CO
2g
+ 5H
2
O
g
………4
1 Panas Reaksi Pembakaran Metana CH
4
∆Hr
1
30
o
C = ∆H
r o
1
+
303 298
2 4
2 2
2 2
dT Cpg
Cpg Cpl
Cpg
O CH
O H
CO
r
1
= 30,0480 kmoljam ∆H
r o
1
= ∆H
r o
CO2
+ 2 ∆H
r o
H2O
–∆H
r o
CH4
– 2 ∆H
r o
O2
= -393.504,7656 +2 x -241.834,933 – -78.451,6800
– 2 x 0 = -798722,9542 Jmol
UNIVERSITAS SUMATERA UTARA
∆Hr
1
30
o
C = ∆H
r o
1
+
303 298
2 4
2 2
2 2
dT Cpg
Cpg Cpl
Cpg
O CH
O H
CO
=
-798.722,9542 + [186,2256 + 2 x 374,6878 – 255,2257
– 2 x 147,2875] = -798.337,1537 Jmol
2 Panas Reaksi Pembakaran Etana C
2
H
6
∆Hr
2
30
o
C = ∆H
r o
2
+
303 298
2 7
2 6
2 2
2
3 2
dT Cpg
Cpg Cpl
Cpg
O H
C O
H CO
r
2
= 2,5040 kmoljam ∆H
r o
2
= 2 ∆H
r o
CO2
+ 3 ∆H
r o
H2O
- ∆H
r o
C2H6
–
2 7
∆H
r o
O2
= 2x-393.504,7656 + 3x-241.834,933 – -84.684,0665
–
2 7
x0 = -1.427.830,2637 Jmol
∆Hr
2
30
o
C = ∆H
r o
2
+
303 298
2 7
2 6
2 2
2
3 2
dT Cpg
Cpg Cpl
Cpg
O H
C O
H CO
= -1.427.830,2637+ [2 x 186,2256 + 3 x 374,6878 – 265,8178 –
2 7
x 147,2875]
=
-1.427.152,1744 Jmol
3 Panas Reaksi Pembakaran Propana C
3
H
8
∆Hr
3
30
o
C = ∆H
r o
3
+
303 298
2 8
3 2
2
5 4
3 dT
Cpg Cpg
Cpl Cpg
O H
C O
H CO
r
3
= 0,4173 kmoljam ∆H
r o
3
= 3∆H
r o
CO2
+ 4 ∆H
r o
H2O
- ∆H
r o
C3H8
– η ∆H
r o
O2
= 3x-393.504,7656 +4x-241.834,933 – -103.846,7654
– 5 x 0 = -2.044.007,2634 Jmol
UNIVERSITAS SUMATERA UTARA
∆Hr
3
30
o
C = ∆H
r o
3
+
303 298
2 8
3 2
2
5 4
3 dT
Cpg Cpg
Cpl Cpg
O H
C O
H CO
= -2.044.007,2634 + [3 x 186,2256 + 4 x 374,6878 – 370,2066 – 5 x 147,2875]
=
-2.043.056,4796 Jmol
4 Panas Reaksi Pembakaran Butana C
4
H
10
∆Hr
4
30
o
C = ∆H
r o
2
+
303 298
2 13
2 10
4 2
2
5 4
dT Cpg
Cpg Cpl
Cpg
O H
C O
H CO
r
4
= 0,4173 kmoljam ∆H
r o
4
= 4 ∆H
r o
CO2
+ η ∆H
r o
H2O
- ∆H
r o
C4H10
–
2 13
∆H
r o
O2
= 4x-393.504,7656 + 5x-241.834,933 – -126.147,4607
–
2 13
x0 = -2.657.046,2667 Jmol
∆Hr
4
30
o
C = ∆H
r o
2
+
303 298
2 13
2 10
4 2
2
5 4
dT Cpg
Cpg Cpl
Cpg
O H
C O
H CO
= -1.427.830,2637 + [2 x 186,2256 + 3 x 374,6878
– 166.052,4848
–
2 13
x 147.2875]
=
-2.657.374,7234 Jmol
Panas Reaksi Total:
T Hr
r
i i
i
4
4
=
C Hr
r
i i
i 4
4
30
= r
1
∆Hr
1
30
o
C + r
2
∆Hr
2
30
o
C + r
3
∆Hr
3
30
o
C + r
4
∆Hr
4
30
o
C =
30,0480 x -798.337,1537 + 2,5040 x -1.427.152,1744 + 0,4173 x -2.043.056,4796 + 0,4173 x -2.657.374,7234
=
-29.523.663,9010 kJjam
UNIVERSITAS SUMATERA UTARA
b. Menghitung Panas Masuk 1 Panas Alur 10
