b. Menghitung Panas Masuk 1 Panas Alur 10
CH
4
: Qi
CH4
= N
10 CH4
.
303 298
4
dT Cpg
CH
= 30,0480 kmoljam x 255,2257 Jmol = 7.669,0199 kJjam
C
2
H
6
: Qi
C2H6
= N
10 C2H6
.
303 298
6 2
dT Cpg
H C
= 2,5040 kmoljam x 265,8178 Jmol = 665,6076 kJjam
C
3
H
8
: Qi
C3H8
= N
10 C3H8
.
303 298
8 3
dT Cpg
H C
= 0,4173 kmoljam x 370,2066 Jmol = 154,4995 kJjam
C
4
H
10
: Qi
C4H10
= N
10 C4H10
.
303 298
1 0 4
dT Cpg
H C
= 0,4173 kmoljam x 490,6778 Jmol = 204,7761 kJjam
2 Panas Alur 12
O
2
: Qi
O2
= N
12 O2
.
303 298
2
dT Cpg
O
= 49,7800 kmoljam x 147,2875 Jmol = 18.181,0788 kJjam
N
2
: Qi
N2
= N
12 N2
.
303 298
2
dT Cpg
N
= 464,3671 kmoljam x 167,6749 Jmol = 77.862,7303 kJjam
UNIVERSITAS SUMATERA UTARA
c. Menghitung Panas Keluar 1 Panas Alur 13
O
2
: Qo
O2
= N
13 O2
.
O
T O
dT Cpg
298
2
= 49,7800 kmoljam .
O
T O
dT Cpg
298
2
N
2
: Qo
N2
= N
13 N2
.
O
T N
dT Cpg
298
2
= 464,3671 kmoljam .
O
T N
dT Cpg
298
2
CO
2
: Qo
CO2
= N
13 CO2
.
O
T CO
dT Cpg
298
2
= 37,9773 kmoljam .
O
T CO
dT Cpg
298
2
H
2
O : Tekanan di alur 13 sebesar 1 atm = 101,325 kPa Titik didih air = 373 K
∆H
VL373
= 2257,3 kJkg Reklaitis, 1983 = 2257,3 kJkg x 18,016 kgkmol
= 40667,5168
Qo
H2O
= N
13 H2O
.
O
T O
H
dT Cp
298
2
= 71,3640 x
dT Cpv
H dT
Cpl
O
T O
H VL
O H
373 373
298
2 2
Asumsi tidak ada panas yang hilang selama pembakaran, sehingga dQdt = 0 dQdt =
C Hr
r
i i
i 4
4
30
+
Qo – Qi
= -29.523.663,9010 kJjam + Qo – 104.737,7123 kJjam
Qo = 29.628.401,6133 kJjam
UNIVERSITAS SUMATERA UTARA
Qo = N
13 O2
.
O
T O
dT Cpg
298
2
+ N
13 N2
.
O
T N
dT Cpg
298
2
+ N
13 CO2
.
O
T CO
dT Cpg
298
2
+ N
13 H2O
.
O
T O
H
dT Cp
298
2
= 49,7800.
O
T O
dT Cpg
298
2
+ 464,3671 .
O
T N
dT Cpg
298
2
+ 37,9773.
O
T CO
dT Cpg
298
2
+ 71,3640.
dT Cpv
H dT
Cpl
O
T O
H VL
O H
373 373
298
2 2
Dengan menggunakan Metode Newton-Rapshon pada program Matlab diperoleh suhu To = 1135,6570 = 1136 K = 863
C
UNIVERSITAS SUMATERA UTARA
Maka, O
2
: Qi
O2
= N
13 O2
.
1136 298
2
dT Cpg
O
= 49,7800 kmoljam x 27.494,7093 Jmol = 1.368.687,9449 kJjam
N
2
: Qi
N2
= N
13 N2
.
1136 298
2
dT Cpg
N
= 464,3671 kmoljam x 49.501,7634 Jmol = 22.986.992,0204 kJjam
CO
2
: Qi
CO2
= N
13 CO2
.
1136 298
2
dT Cpg
CO
= 37,9773 kmoljam x 40.858,0236 Jmol = 1.551.678,4385 kJjam
H
2
O : Qi
H2O
= N
13 H2O
.
1136 298
2
dT Cp
O H
= 47,5760 kmoljam x
dT Cpv
H dT
Cpl
O H
VL O
H 1136
373 373
298
2 2
= 71,3640 x 52.141,7527 Jmol = 3.721.043,2095 kJjam
Tabel B.7 Neraca Energi pada Burner B-101
Komponen Masuk kJjam
Keluar kJjam H
10
H
12
H
13
CH
4
7.669,0199 -
- C
2
H
6
665,6076 -
- C
3
H
8
154,4995 -
- C
4
H
10
204,7761 -
- O
2
- 18.181,0788
1.368.687,9449 N
2
- 77.862,7303
22.986.992,0204
UNIVERSITAS SUMATERA UTARA
Tabel B.7 Neraca Energi ............. Lanjutan
Komponen Masuk kJjam
Keluar kJjam H
10
H
12
H
13
CO
2
- -
1.551.678,4385 H
2
O -
- 3.721.043,2095
Jumlah 8.693,9032
96.043,8091 29.628.401,6133
Sub Total 104.737,7123
29.628.401,6133 ∆Hr
29.523.663,9010 -
Total 29.628.401,6133
29.628.401,6133
B.2.4 Rotary Kiln Pre-Heater B-102
Fungsi : Pemanas awal bahan baku sampai suhu 617 C, sebelum dikirim ke Electric
Furnace B-103
c. Menghitung Panas Masuk 1 Panas Alur 9
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