The solution getdoc65b5. 281KB Jun 04 2011 12:04:27 AM

An interesting relationship between the two models analyzed here can be established by observing that the waiting-time of the k-th event of the process governed by 1.7 coincides in distribution with the waiting time of the 2k-th event for the first model. This suggests to interpret c N ν as a fractional Poisson process of the first type, which jumps upward at even-order events A 2k and the probability of the successive odd-indexed events A 2k+1 is added to that of A 2k . As a consequence, the distribution of c N ν can be expressed, in terms of the processes N and T 2 ν , as follows: Pr ¦ c N ν t = k © = Pr N T 2 ν t = 2k + Pr N T 2 ν t = 2k + 1 , k ≥ 0. We also study the probability generating functions of the two models, which are themselves solu- tions to fractional equations; in particular in the second case an interesting link with the fractional telegraph-type equation is explored. For ν = 1, equation 1.7 takes the following form d 2 p k d t 2 + 2λ d p k d t = −λ 2 p k − p k −1 , k ≥ 0 and the related process can be regarded as a standard Poisson process with Gamma-distributed interarrival times with parameters λ, 2. This is tantamount to attributing the probability of odd- order values A 2k+1 of a standard Poisson process to the events labelled by 2k. Moreover, it should be stressed that, in this special case, the equation satisfied by the probability generating function b Gu, t, t 0, |u| ≤ 1, i.e. ∂ 2 Gu, t ∂ t 2 + 2λ ∂ Gu, t ∂ t = λ 2 u − 1Gu, t, ν ≤ 1 coincides with that of the damped oscillations. All the previous results are further generalized to the case n 2 in the concluding remarks: the structure of the process governed by the equation d n ν p k d t n ν + n 1 λ d n−1ν p k d t n−1ν + ... + n n − 1 λ n −1 d ν p k d t ν = −λ n p k − p k −1 , k ≥ 0, 1.8 where ν ∈ 0, 1], is exactly the same as before and all the previous considerations can be easily extended. 2 First-type fractional recursive differential equation

2.1 The solution

We begin by considering the following fractional recursive differential equation d ν p k d t ν = −λp k − p k −1 , k ≥ 0, 2.1 with p −1 t = 0, subject to the initial conditions p k 0 = ¨ 1 k = 0 k ≥ 1 . 2.2 687 We apply in 2.1 the definition of the fractional derivative in the sense of Caputo, that is, for m ∈ N, d ν d t ν ut = 1 Γm−ν R t 1 t−s 1+ ν−m d m ds m usds, for m − 1 ν m d m d t m ut, for ν = m . 2.3 We note that, for ν = 1, 2.1 coincides with the equation governing the homogeneous Poisson process with intensity λ 0. We will obtain the solution to 2.1-2.2 in terms of GML functions defined in 1.6 and show that it represents a true probability distribution of a process, which we will denote by N ν t, t 0 : therefore we will write p ν k t = Pr N ν t = k , k ≥ 0, t 0. 2.4 Theorem 2.1 The solution p ν k t, for k = 0, 1, ... and t ≥ 0, of the Cauchy problem 2.1-2.2 is given by p ν k t = λt ν k E k+1 ν,ν k+1 −λt ν , k ≥ 0, t 0. 2.5 Proof By taking the Laplace transform of equation 2.1 together with the condition 2.2, we obtain L ¦ p ν k t; s © = Z ∞ e −st p ν k td t = λ k s ν−1 s ν + λ k+1 2.6 which can be inverted by using formula 2.5 of [24], i.e. L n t γ−1 E δ β,γ ωt β ; s o = s βδ−γ s β − ω δ , 2.7 where Re β 0, Reγ 0, Reδ 0 and s |ω| 1 Re β for β = ν, δ = k + 1 and γ = ν k + 1. Therefore the inverse of 2.6 coincides with 2.5. ƒ Remark 2.1 For any ν ∈ 0, 1], it can be easily seen that result 2.5 coincides with formula 2.10 of [2], which was obtained by a different approach. Moreover Theorem 2.1 shows that the first model proposed by Mainardi et al. [17] as a fractional ver- sion of the Poisson process called renewal process of Mittag-Leffler type has a probability distribution coinciding with the solution of equation 2.1 and therefore with 2.5. We derive now an interesting relationship between the GML function in 2.5 and the Wright func- tion W α,β x = ∞ X k=0 x k kΓ αk + β , α −1, β 0, x ∈ R. Let us denote by v 2 ν = v 2 ν y, t the solution to the Cauchy problem    ∂ 2 ν v ∂ t 2 ν = λ 2 ∂ 2 v ∂ y 2 , t 0, y ∈ R v y, 0 = δ y, for 0 ν 1 v t y, 0 = 0, for 1 2 ν 1 . 2.8 688 then it is well-known see [14] and [15] that the solution of 2.8 can be written as v 2 ν y, t = 1 2 λt ν W −ν,1−ν − | y| λt ν , t 0, y ∈ R. 2.9 In [2] the following subordinating relation has been proved: p ν k t = Z +∞ e − y y k k v 2 ν y, td y = Pr N T 2 ν t = k , k ≥ 0, 2.10 where v 2 ν y, t = ¨ 2v 2 ν y, t, y 0, y 2.11 is the folded solution of equation 2.8. In 2.10 T 2 ν t, t 0 represents a random time indepen- dent from the Poisson process N with transition density given in 2.9 and 2.11. This density can be alternatively expressed in terms of the law g ν ·; y of a a stable random variable S ν µ, β, σ of order ν, with parameters µ = 0, β = 1 and σ = € y λ cos πν 2 Š 1 ν ,as v 2 ν y, t = 1 Γ1 − ν Z t t − w −ν g ν w; y λ d w 2.12 see [20], formula 3.5, for details. By combining 2.5 and 2.10, we extract the following integral representation of the GML functions, in terms of Wright functions: E k+1 ν,ν k+1 −λt ν = 1 k λ k+1 t νk+1 Z +∞ e − y y k W −ν,1−ν − y λt ν d y. 2.13 Remark 2.2 Since result 2.13 holds for any t 0, we can choose t = 1, so that we get, by means of a change of variable, E k+1 ν,ν k+1 −λ = 1 k Z +∞ e −λ y y k W −ν,1−ν − yd y. This shows that the GML function E k+1 ν,ν k+1 can be interpreted as the Laplace transform of the function y k k W −ν,1−ν − y. In particular, for ν = 1 2 , since 2.10 reduces to Pr ¦ N 1 2 t = k © = Z +∞ e − y y k k e − y 2 4λ 2 t p πλ 2 t d y = Pr N |B λ t| = k , where B λ t is a Brownian motion with variance 2λ 2 t independent of N , we get for t = 1 E k+1 1 2 , k 2 +1 −λ = 1 k Z +∞ e −λ y y k e − y 2 4 p π d y. 2.14 The previous relation can be checked directly, by performing the integral in 2.14. 689

2.2 Properties of the corresponding process

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