Normality Test Homogeneity Test

40 Table 4.7 Statistical Calculation on Gained Score of Experimental Class X and Controlled Class Y No. X Y X y x 2 y 2 1 4 4 -7.4 -5.53 54.76 30.5809 2 8 16 -3.4 6.47 11.56 41.8609 3 14 2 2.6 -7.53 6.76 56.7009 4 4 4 -7.4 -5.53 54.76 30.5809 5 14 12 2.6 2.47 6.76 6.1009 6 14 2 2.6 -7.53 6.76 56.7009 7 8 20 -3.4 10.47 11.56 109.6209 8 2 14 -9.4 4.47 88.36 19.9809 9 20 10 8.6 0.47 73.96 0.2209 10 14 16 2.6 6.47 6.76 41.8609 11 10 20 -1.4 10.47 1.96 109.6209 12 8 8 -3.4 -1.53 11.56 2.3409 13 12 -6 0.6 -15.53 0.36 241.1809 14 16 28 4.6 18.47 21.16 341.1409 15 12 10 0.6 0.47 0.36 0.2209 16 18 8 6.6 -1.53 43.56 2.3409 17 22 2 10.6 -7.53 112.36 56.7009 18 2 24 -9.4 14.47 88.36 209.3809 19 8 4 -3.4 -5.53 11.56 30.5809 20 4 -2 -7.4 -11.53 54.76 132.9409 21 10 6 -1.4 -3.53 1.96 12.4609 22 12 8 0.6 -1.53 0.36 2.3409 23 14 12 2.6 2.47 6.76 6.1009 24 16 6 4.6 -3.53 21.16 12.4609 25 8 12 -3.4 2.47 11.56 6.1009 26 16 4 4.6 -5.53 21.16 30.5809 41 No. X Y X y x 2 y 2 27 22 18 10.6 8.47 112.36 71.7409 28 10 6 -1.4 -3.53 1.96 12.4609 29 12 10 0.6 0.47 0.36 0.2209 30 8 8 -3.4 -1.53 11.56 2.3409 SUM 342 286 857.2 1677.467 AVG

11.4 9.53

28.57333 55.91557 Table 4.7 shows the total of gained score on Experimental Class X and Controlled Class Y. From the table above, the summation of gained score in Experimental Class is 342 while in the Controlled Class it has 286. It means that gained score on Experimental Class is higher than the Controlled Class. After calculating the gained score, the t-test formula was calculated as follows: 1. Determining mean of variable X Experiment Class: � � = ∑ � = = . 2. Determining mean of variable Y Control Class: � = ∑ � = = . 3. Determining standard deviation of variable X: � = √ ∑ � 2 = √ 5 . = √ . = . 4. Determining standard deviation of variable Y:e � = √ ∑ � 2 = √ . = √ . = . 5. Determining standard error of mean variable X: � = � √ − = 5. √ − = 5. 5. = . 42 6. Determining standard error of mean variable Y: � = � √ − = . √ − = . 5. = . 7. Determining standard error of different mean of variable x and mean of variable Y: � − = √� + � = √ . + . = √ . + . = √ . = 1.69 8. Statistical t-test formula: � �= � − � ��−� = . − .5 . = .. = . 9. Determining t t le in significance level 0.05, with df degree of freedom df = N x + N y – 2 = 30 + 30 – 2 = 58 From the calculation above, the df value is 58 and from degree of significant value 0.05 or t t is 1.67. 10. Hypothesis Testing From the calculation above, the calculated t-test of t was 1.10 and the degree of freedom df was 58. Furthermore, the degree significance that was used for this research is 5 or 0.05, therefore from t table it was 1.67. Compared to the t table, the result of t was lower than t table. Those calculations were meant to know if video game has positive effect on students’ reading comprehension of narrative text on eighth grade students of SMPN 96 Jakarta Selatan. Therefore, the hypotheses are: H : Video Game has no positive effect on Students’ Reading Comprehension of Narrative Text H 1 : Video Game has a positive effect on students’ Reading Comprehension of Narrative Text.

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