Proposition 4.4 formula H. We have for q
≥ q that
X
i jq t
=q Z
t
X
i jq−1 s
X
k
∂
k
F
i
ds , x
s
∂
j
x
k s
D x
s
− ∂
k
F
i
ds , y
s
∂
j
y
k s
D y
s
− q Z
t
X
i jq−1 s
X
k ,l,m
∂
m
F
k
ds , x
s
∂
l
x
m s
∂
l
x
k s
∂
j
x
i s
D x
s 3
− ∂
m
F
k
ds , y
s
∂
l
y
m s
∂
l
y
k s
∂
j
y
i s
D y
s 3
+ β
L
− β
N
4 q
2
− d
− 1 2
β
N
q −
1 2
β
L
q Z
t
X
i jq s
ds +
qq − 1
2 β
N
Z
t
X
i jq−2 s
X
k
X
k j2 s
ds − q
β
N
+ β
L
2 Z
t
X
i jq−1 s
X
k ,l
∂
j
x
k s
∂
l
x
i s
∂
l
x
k s
D x
s 3
− ∂
j
y
k s
∂
l
y
i s
∂
l
y
k s
D y
s 3
ds + qq − 1
β
N
+ β
L
4 Z
t
X
i jq−2 s
X
k ,n
X
l
∂
l
x
n s
∂
l
x
k s
∂
j
x
i s
D x
s 3
− ∂
l
y
n s
∂
l
y
k s
∂
j
y
i s
D y
s 3
2
ds − qq − 1
β
N
+ β
L
2 Z
t
X
i jq−2 s
X
k ,l
X
k j s
∂
l
x
k s
∂
l
x
i s
∂
j
x
i s
D x
s 3
− ∂
l
y
k s
∂
l
y
i s
∂
j
y
i s
D y
s 3
ds +
3 4
q β
N
+ β
L
Z
t
X
i jq−1 s
X
k ,l,m,n
∂
l
x
k s
∂
l
x
n s
∂
m
x
k s
∂
m
x
n s
∂
j
x
i s
D x
s 5
∂
l
y
k s
∂
l
y
n s
∂
m
y
k s
∂
m
y
n s
∂
j
y
i s
D y
s 5
ds + qq − 1
Z
t
X
i jq−2 s
X
k ,l
∂
j
x
k s
∂
j
y
l s
D x
s
D y
s
˜b
i ,i
k ,l
x
s
− y
s
ds − qq − 1
Z
t
X
i jq−2 s
X
k ,l,m,n
∂
j
x
k s
∂
m
y
n s
∂
m
y
l s
∂
j
y
i s
D x
s
D y
s 3
+ ∂
j
y
k s
∂
m
x
n s
∂
m
x
l s
∂
j
x
i s
D y
s
D x
s 3
˜
b
i ,l
k ,n
x
s
− y
s
ds + qq − 1
Z
t
X
i jq−2 s
X
k ,l,m,n,p,r
∂
l
x
m s
∂
l
x
k s
∂
j
x
i s
∂
p
y
r s
∂
p
y
n s
∂
j
y
i s
D x
s 3
D y
s 3
˜b
k ,n
r ,m
x
s
− y
s
ds. 33
Proof: There is nothing left to show.
Proposition 4.4 will be useful to estimate the expectation in Lemma 2.3 on the event {T ≤ τ}
but since this requires some additional preparations we will first consider the reversed case in the following intermezzo.
4.3 Treating Small
|x − y| And Large T
Since we obviously have from Schwarz’ inequality that E
sup
≤t≤T
|ψ
t
x − ψ
t
y|
q
11
{T ≥τ}
1 q
≤ E
sup
≤t≤T
|ψ
t
x − ψ
t
y|
2q
1 2q
P [T ≥ τ]
1 2q
34 it seems reasonable to compute some useful estimate for the tails of τ. We will also immediatly
specify conditions on r and ˜r. Assume first with Lemma 1.3 that ˜r ¯r is small enough to ensure that for any 0
≤ r ≤ ˜r we have p
2 1 − B
L
r ≤ 2
p β
L
r and d
− 1 1
− B
N
r r
− cr ≤ 2d − 1β
N
− c r.
35 2343
Lemma 4.5 tails of τ .
If we assume q ≥ q
then we have for T ≤
log
˜r |x− y|
128β
L
q
∧
log
˜r |x− y|
4
p
β
L
[
2d −1β
N
−c−2β
L
] =
log
˜r |x− y|
128β
L
q
that P [T ≥ τ] ≤
2 ˜r
2q
|x − y|
2q
∧
2 ˜r
4q
|x − y|
4q
. Proof: Let X
t
= |x − y| + R
t
2 p
β
L
X
s
dW
s
+ R
t
2d − 1β
N
− c X
s
ds i.e.
X
t
:= |x − y| exp
n 2
p β
L
W
s
+ 2d − 1β
N
− c − 2β
L
t o
for some BM W
t t
≥0
. Then we may start with see 3 and 35
P [T ≥ τ] =P
sup
≤t≤T
|x
t
− y
t
| ≥ ˜r
≤ P
sup
≤t≤T
X
t
≥ ˜r
36 =P
sup
≤t≤T
W
t
≥ 1
2 p
β
L
log ˜r
|x − y| −
2d − 1β
N
− 2β
L
− c
+
T
≤P
sup
≤t≤1
W
t
≥ log
˜r |x− y|
2 p
β
L
T −
2d − 1β
N
− 2β
L
− c
+
p T
=: I X .
Let first 2d − 1β
N
− 2β
L
− c ≤ 0. Then we have using 1 − Φt ≤ e
−12t
2
that I X
≤2
1 −
Φ
log
˜r |x− y|
2 p
β
L
T
≤ 2 e
−
1 8
log
˜r |x− y|
2
βL T
=2 |x − y|
˜r
1 8βL T
log
˜r |x− y|
≤ 2
˜r
2q
|x − y|
2q
37 for T
≤
log
˜r |x− y|
16β
L
q
remember |x − y| r ˜r . Let now 2d − 1β
N
− 2β
L
− c 0. In this case we can use for T
≤
log
˜r |x− y|
4
p
β
L
[
2d −1β
N
−c−2β
L
] ∧
log
˜r |x− y|
128β
L
q
that
I X =P
sup
≤t≤1
W
t
≥ log
˜r |x− y|
2 p
β
L
T −
2d − 1β
N
− 2β
L
− c p T
≤P
sup
≤t≤1
W
t
≥ log
˜r |x− y|
4 p
β
L
T
= 2
1 −
Φ
log
˜r |x− y|
4 p
β
L
T
≤2 exp ¨
− 1
2 1
16β
L
T log
˜r |x − y|
2
« = 2
|x − y| ˜r
log ˜r
|x− y| 32βL T
≤2 |x − y|
2q
˜r
2q
∧ 2 |x − y|
4q
˜r
4q
. 38
The proof is complete.
2344
Lemma 4.6 estimate for T after τ. For
|x − y| ≤ r ≤ e
−1
˜r and arbitrary q ≥ q
and T 0 we have
E
sup
≤t≤T
|ψ
t
x − ψ
t
y|
q
11
{T ≥τ}
1q
≤ ¯c
2
|x − y|
2
e
Λ
2
+
1 2
q σ
2 2
T
39 with Λ
2
:= Λ
1
∨ 1, σ
2
:= p
2σ
1
∨ 2 p
128β
L
∨ 2 and ¯c
2
:=
p 2 ¯
C
1
˜r
∨
1 ˜r
β
N
+β
L
128β
L
+
p 2π˜ce
− 5
12
p
16β
L
∨
2β
L
+β
N
˜r
∨
2e
− 5
12
p
256˜cπβ
L
˜r
. Proof: If T
≤
log
˜r |x− y|
128β
L
q
∧
log
˜r |x− y|
4
p
β
L
[
2d −1β
N
−c−2β
L
] =
log
˜r |x− y|
128β
L
q
then we just have to combine Lemmas 4.2 and 4.5 with 34 to obtain
E
sup
≤t≤T
|ψ
t
x − ψ
t
y|
q
11
{T ≥τ}
1q
≤ |x − y| ¯
C
1
˜r 2
1 2q
e
Λ
1
+
1 2
σ
2 1
2q
T
which means we only have to consider the case T ≥
log
˜r |x− y|
128β
L
q
. By Lemma 4.2 we first observe for T
:=
log
˜r |x− y|
128β
L
q
that E
sup
≤t≤T
|ψ
t
x − ψ
t
y|
q
1q
≤ β
N
+ β
L
log
˜r |x− y|
128β
L
q + 2e
−
5 12
p 2π˜c
p q +
1 s
log
˜r |x− y|
128β
L
q ≤
β
N
+ β
L
128β
L
+ p
2π˜ce
−
5 12
p 16β
L
˜r |x − y|
≤
β
N
+ β
L
128β
L
+ p
2π˜ce
−
5 12
p 16β
L
˜r |x − y|
Λ2+ 1
2 σ2
2 q
128βL q
−1
40 =
1 ˜r
β
N
+ β
L
128β
L
+ p
2π˜ce
−
5 12
p 16β
L
|x − y|e
Λ2+ 1
2 σ2
2 q
128βL q
log
˜r |x− y|
≤ ¯c
2
|x − y|e
Λ
2
+
1 2
q σ
2 2
T
. Since f : T
7→ ¯c
2
|x − y|e
Λ
2
+
1 2
q σ
2 2
T
is a convex function and g : T 7→ β
N
+ β
L
T + 2e
−
5 12
p 2π˜c
p q +
1 p
T is concave one we may just check that f
′
T ≥ g
′
T .
g
′
T = β
N
+ β
L
+ e
−
5 12
p 256π˜cβ
L
p qq +
1 1
log
˜r |x− y|
≤ ¯c
2
˜r 2
Λ
2
+ 1
2 q
σ
2 2
˜r |x − y|
Λ2+ 1
2 σ2
2 q
128βL
−1
+ ¯c
2
˜r 2
Λ
2
+ 1
2 q
σ
2 2
˜r |x − y|
Λ2+ 1
2 σ2
2 q
128βL
−1
=¯c
2
Λ
2
+ 1
2 q
σ
2 2
˜r |x − y|
Λ2+ 1
2 σ2
2 q
128βL
|x − y| = f
′
T .
41 Thus the proof of Lemma 4.6 is complete.
To treat 33 we finally need the following proposition.
2345
Proposition 4.7 expectation of zero-mean-martingales on rare events. For i
, j ∈ {1, . . . , d} we define ˇ
M
t
= ˇ M
i j t
:= R
t
X
i jq−1 s
d V I I
t
− R
t
X
i jq−1 s
d V I I I
t
. Then we have 1. ˇ
M
t
is a zero-mean-martingale and we have any t ≥ 0 that
¬ ˇ M
¶
t
≤ ˇct a.s. for ˇc := 4d
2
+ 2d
4
+ d
6
max
k ,l,m,n
sup
z ∈R
d
∂
k
∂
l
b
m ,n
z. 2. For all
≤ t ≤ T and q ≥ q we get that
E ˇ
M
t
11
{T ≤τ}
≤ |x − y|
2q ¯c
3
˜r
2q
e
Λ
3
+
1 2
σ
2 3
q+ σ
2 4
q
2
T
=: f T for ¯c
3
:= p
2ˇc ∨
q
ˇc 128β
L
∨ 1, Λ
3
:=
1 2e
, σ
3
:= q
64β
L
e
∨ 128β
L
ˇc
1 4
and σ
4
:= p
256β
L
. Proof: 1. is clear from the definition of ˇ
M except for the value of ˇc. This value follows from 30,
31 and 32 since ¬ ˇ
M ¶
t
≤ 〈V I I〉
i
+ 〈V I I I〉
t
+ 2| 〈V I I, V I I I〉
t
|. For the proof of 2. first assume T
≤
log
˜r |x− y|
128β
L
q
. From Lemma 4.5 we know that P [T τ] ≤ |x − y|
4q 2 ˜r
4q
. This combined with Schwarz’ inequality and 1. yields
E ˇ
M
t
11
{T ≤τ}
=
E ˇ
M
t
11
{T τ}
≤
q E
¬ ˇ M
¶
T
p P
[T τ] ≤
p 2ˇcT
|x − y|
2q
˜r
2q
≤ p
2ˇc |x − y|
2q
˜r
2q
e
T 2e
42 which proves Proposition 4.7 in this case. We always have as above that
E ˇ
M
t
11
{T ≤τ}
≤
p ˇcT =: gT and so we can conclude for the same T
as before gT
= È
ˇc 128β
L
r log
˜r |x − y|
≤ È
ˇc 128β
L
˜r |x − y|
1 2e
≤¯c
3
˜r |x − y|
σ2 3
128βL
≤ ¯c
3
˜r |x − y|
Λ3+ σ 2
3 q+
σ2 4
q2 128βL q
|x − y| ˜r
2q
=|x − y|
2q
¯c
3
˜r
2q
e
Λ
3
+
1 2
σ
2 3
q+ σ
2 4
q
2
T
=: f T 43
so now with Lemma 1.4 we only have to establish the inequality g
′
T ≤ f
′
T to complete the
proof of Proposition 4.7. The proof of this is as follows. g
′
T =
1 2
s 128β
L
q ˇc
log
˜r |x− y|
≤ 1
2 p
128β
L
q ˇc
44
≤ |x − y|
˜r
2
Λ
3
+ 1
2 σ
2 3
q + σ
2 4
q
2
˜r |x − y|
Λ3+ 1
2 σ2
3 q+
σ2 4
q2 128βL
= f
′
T .
The proof is complete.
2346
4.4 Evaluation Of Formula H