23
To know the class percentage, the writer used formula as follow:
3
P = the class percentage F = total percentage score
N = number of students After getting the score of students per section, the writer identified
whether or not there was improvement of students’ reading skill from pretest to the average of students writing score in cycle 1 and cycle 2. Meanwhile, in
analyzing it the writer used the following formula:
4
P =
P : percentage of students’ improvement y : pre-test result
y
1
: post-test 1
3
Anas Sudjiono, Pengantar Statistik Pendidikan, Jakarta: Raja Grafindo Persada, 2008, p. 43.
4
David E. Meltzer, The Relationship Between Mathematics Preparation and Conceptual Learning Gains in physis: A possible Hidden Variable in Diagnostic Pretest Score, Iowa:
Departement of Physis And Astronomy, 2008, p. 3.
100 y
y y
P
1
100 N
F P
24
P : percentage of students’ improvement y : pre-test result
y
2
: post-test 2
B. Research Finding
1.
The Description of the Data
As mentioned in chapter one, the writer conducted the research field. She got the data from observation, interview, and test; the test is consisting of
pre-test and post-test. The pre-test was given before the action research and the post-test was given after action research.
Table 4.1 The Studen
ts’ Reading Score of Pre-test, Post-test 1, and Post-test 2
Students Number Pre- test
Post-test Post-test
Cycle 1 Cycle 2
1 40
60 80
2 35
55 65
3 55
70 85
4 30
55 60
5 55
60 80
6 45
60 80
7 45
55 75
8 60
70 80
9 40
60 70
10 30
50 60
11 55
65 80
12 65
75 90
100 y
y y
P
2
25
To compare the result between pre-test and post test of each cycle, the writer uses some steps, first she calculated the students mean score of the test and
then calculating the students improvement score from pre-test in cycle 1 and cycle 2.
In analyzing the data of pre-test, the first is to get the mean score of the class. It is calculated as following:
n X
X
13 40
55 75
14 55
55 80
15 30
50 80
16 40
60 75
17 50
60 80
18 35
60 65
19 50
60 80
20 40
55 75
21 50
65 80
22 40
60 80
23 70
70 90
24 60
65 90
25 55
65 75
26 55
60 85
27 50
70 90
28 35
55 60
29 50
60 80
30 40
55 75
31 40
65 80
32 40
60 80
33 70
70 90
34 50
70 90
35 50
60 90
Total 1720
2140 2750
Mean 49.14
61.14 78.57
26
35 1720
14 .
49
From that calculation, the mean score of the class in pre-test is 49.14. It means that the students
’ motivation in reading score before implementing of research is 49.14.
The second step is to know the persentage of students’ score who passed the KKM 70. It is calculated by using as follows:
100 N
F P
100 35
2 P
P = 5. 71
From that computation, the students’ score percentage in the pre-test is 5.71. it
means that there are 2 students who passed the KKM and there are 33 students are still below the KKM.
And then, the writer calculates the result of the post test 1 to know the students’ score improvement from the pre-test to post test 1. There are three steps
to get this improvement. Those are calculating the students’ mean score of the
class, calculating the students’ improvement score into percentage and calculating
the class percentage. The first step is to calculate the mean score of post-test 1. The calculated
as follow:
n X
X
35 2140
