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Difficulty Level Discriminating Power

Where: r 11 : reliability of test k : the number of the items p : proportion the subject answering the item incorrectly q : proportion the subject answering the item correctly S 2 : total variance Arikunto 1998:193

3.7.4.5 Difficulty Level

After conducting and getting the result of the try out, then I classify and select the items by using this formula: Where, ID : Index of difficulty of item RU : The number of students in upper group who answered the item correctly RL : The number of students in lower group who answered the item correctly T RL RU ID + = ⎟⎟⎠ ⎞ ⎜⎜⎝ ⎛ ∑ − ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ = 2 2 11 S pq S 1 - k k r T : The real number of the students The criteria used here are: 0 IK 0.30 is difficult 0.30 IK 0.70 is medium 0.70 IK 1.00 is easy

3.7.4.6 Discriminating Power

The discriminating power will measure how well the test items arranged to identify the differences in the students’ competence. The formula is: Where, DP : The discriminating index RU : The number of students in upper group who answered the item correctly RL : The number of students in lower group who answered the item correctly T U : The number of students in upper group T L : The number of students in lower group L U T RL T RU DP − = The criteria are: Interval Criteria DP 0.00 0.0 DP 0.20 0.20 DP 0.40 0.40 DP 0.70 0.70 DP 1.00 Very poor Poor Satisfactory Good Excellent

3.8 Methods of Analyzing the Data

Since this study combines a quantitative approach and a qualitative one, the analysis of the data is presented in a quantitative and also qualitative way. It is evaluated by means of appropriate statistical procedure and the average score of the class to support the argument. To decide whether the students are success or failed in doing activities those have been planned above will be assessed by referring to the criterion of the students’ mastery level for English lesson based on the criterion of Department of National Education. Department of Education and Culture 1994: 29 maintains that the students can be argued to finish their study successfully if 85 students of the whole can achieve 65 of the material given. In scoring the test, I give the score based on the sum of the items that they give the correct answer. After I get the total score for each student, I will count student’s test result using the following formula:

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