Overview of the proof
Notation 2.9. For k = 0, 1 and a ∈ R we let
F
k
a = 1
− a, k = 0, a,
k = 1. We give the proof of the following result for rescaled competing species models
ξ
N
with rates of change as in 18 in Section 3.
Theorem 2.10. Suppose that A
ξ
N
→ u in
C
1
. Let the transition rates of ξ
N
x be as in 18 and q
k,m,N i j
satisfying Hypothesis 2.5. Then the
A ξ
N t
: t ≥ 0
are C-tight as cadlag C
1
-valued processes and the
ν
N t
: t ≥ 0
are C-tight as cadlag Radon measure valued processes with the vague topology. If
A ξ
N
k
t
, ν
N
k
t t
≥0
converges to u
t
, ν
t t
≥0
, then ν
t
d x = u
t
xd x for all t ≥ 0. For the special case with no short-range competition we further have that if Hypothesis 2.7 holds, then
the limit points of A ξ
N t
are continuous C
1
-valued processes u
t
which solve ∂ u
∂ t =
∆u 6
+ X
k=0,1
1 − 2k X
m ≥2, j=0,1
q
k,m 0 j
F
j
u F
1 −k
u
m −1
F
k
u + p
2u1 − u ˙
W 21
with initial condition u . If we assume additionally
〈u , 1
〉 ∞, then u
t
is the unique in law [0, 1]- valued solution to the above SPDE.
The claim of Theorem 1.5 now follows from the first part of Theorem 2.10. Indeed, rewrite 16 in the form 18 and use Remark 2.3.
Assume additionally that there is no short-range competition and recall Remark 2.8. The second part of Theorem 2.10 yields that the limit points of A
ξ
N t
, with ξ
N t
being the system with transition rates as in 16, are continuous
C
1
-valued processes u
t
which solve 21. To obtain the claim of Theorem 1.8, it remains to show that every solution to 21 can be rewritten as a solution to 8. This follows
from Corollary 2.11 below. Uniqueness in law of the former solution then implies uniqueness in law of the latter.
Corollary 2.11. Under the assumptions of Theorem 1.8, the SPDE 21 may be rewritten as
u
t
= ∆u
6 + 1 − uu
∞
X
m=0
α
m+1
u
m
− u1 − u
∞
X
m=0
α
m+1 1
1 − u
m
+ p
2u1 − u ˙
W . Proof. First recall Remark 1.7. Next use the definition of F
k
a and collect terms appropriately. Then recall how we rewrote the transition rates in Lemma 2.2 and Remark 2.4 to obtain 18 from 16.
Now, analogously, rewrite 8 as 21.
3 Proof of Theorem 2.10