The problem can be written in matrix form as The problem can be written in matrix form as a

73 c = Q\Qc c = 11.5094 11.5094 19.0566 16.9983 11.5094

7.7 The problem can be written in matrix form as

⎪ ⎪ ⎭ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎩ ⎪ ⎪ ⎨ ⎧ − = ⎪ ⎪ ⎪ ⎭ ⎪⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎩ ⎪⎪ ⎪ ⎨ ⎧ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ ⎡ − − − − − − − − 1000 1 866 . 5 . 1 1 5 . 1 1 866 . 866 . 5 . 5 . 866 . 3 2 2 3 2 1 V V H F F F MATLAB can then be used to solve for the forces and reactions, A = [0.866 0 -0.5 0 0 0; 0.5 0 0.866 0 0 0; -0.866 -1 0 -1 0 0; -0.5 0 0 0 -1 0; 0 1 0.5 0 0 0; 0 0 -0.866 0 0 -1] b = [0 -1000 0 0 0 0]; F = A\b F = -500.0220 433.0191 -866.0381 -0.0000 250.0110 749.9890 Therefore, F 1 = –500 F 2 = 433 F 3 = –866 H 2 = 0 V 2 = 250 V 3 = 750

7.8 The problem can be written in matrix form as

⎪ ⎪ ⎭ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎩ ⎪ ⎪ ⎨ ⎧ = ⎪ ⎪ ⎪ ⎭ ⎪⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎩ ⎪⎪ ⎪ ⎨ ⎧ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ ⎡ − − − − − − − − − 200 20 10 5 5 15 10 10 1 1 1 1 1 1 1 1 1 1 43 54 65 32 52 12 i i i i i i MATLAB can then be used to solve for the currents, 74 A = [1 1 1 0 0 0 ; 0 -1 0 1 -1 0; 0 0 -1 0 0 1; 0 0 0 0 1 -1; 0 10 -10 0 -15 -5; 5 -10 0 -20 0 0]; b = [0 0 0 0 0 200]; i = A\b i = 6.1538 -4.6154 -1.5385 -6.1538 -1.5385 -1.5385 7.9 k1 = 10;k2 = 40;k3 = 40;k4 = 10; m1 = 1;m2 = 1;m3 = 1; km = [1m1k2+k1, -k2m1,0; -k2m2, 1m2k2+k3, -k3m2; 0, -k3m3,1m3k3+k4]; x = [0.05;0.04;0.03]; kmx = kmx kmx = 0.9000 0.0000 -0.1000 Therefore, 1 x = −0.9, 2 x = 0 , and 3 x = 0.1 ms 2 . 75 CHAPTER 8 8.1 The flop counts for the tridiagonal algorithm in Fig. 8.6 can be summarized as MultDiv AddSubtr Total Forward elimination 3n – 1 2n – 1 5n – 1 Back substitution 2n – 1 n – 1 3n – 2 Total 5n – 4 3n – 3 8n – 7 Thus, as n increases, the effort is much, much less than for a full matrix solved with Gauss elimination which is proportional to n 3 . 8.2 The equations can be expressed in a format that is compatible with graphing x 2 versus x 1 : 6 34 6 1 3 5 . 1 2 1 2 + − = + = x x x x which can be plotted as 1 2 3 4 5 6 7 8 9 10 2 4 6 8 10 12 Thus, the solution is x 1 = 4, x 2 = 5. The solution can be checked by substituting it back into the equations to give 34 30 4 5 6 4 24 40 16 5 8 4 4 = + = + − = − = −

8.3 a

The equations can be expressed in a format that is compatible with graphing x 2 versus x 1 : 10 114943 . 12 11 . 1 2 1 2 + = + = x x x x 76 which can be plotted as