lowclass boundary was 59.5. In addition, the lowest absolute frequency was 2 on the class interval 64-67 with relative frequency 6.66 and the higest
absolute frequency was 9 with relative frequency 30 on the both class interval 72-75 and 80-83. In the addition, the total numbers of absolute
frequency were 30. The whole description of statistical calculation can be seen on the appendix..
B. Data Analysis
1. Normality Test of Pre-Test
Lilliefors Normality test was used in this study to find out the distribution of pre-test data. It is used in order to know the data normally distributed or not.
Table 4.8 The Result of Normality Pre-test of Experimental and Controlled Class
No Source
Experimental Controlled
1. N
30 30
2. Average
67.63 69.16
3. Variance
66.69 58.85
4. Standard Deviation
8.10 7.67
5. Maximal Score
80 80
6. Minimal Score
53 57
7. T
value
0,1257 0,1163
8. T
table
0.1590 9.
Criteria Normal
The following is the writer ’s assumption:
Ho : the data of normal distribution H
1
: the data of un normal distribution
The criteria is Ho accepted if T
value
0.1590 and rejected if T
value
0.1590 with α =
5.
Based to Table 4.4, it can bee seen that T
value
in experimental class is smaller than T
table
, with the closest Lilliefors critical value of 30 with degree of significance 0.05 which is T
value
T
table
0.1257 0.1590. In addition, T
value
in controlled class is smaller than T
table
, with the closest Lilliefors critical value of 30 with degree of significance 0.05 which is T
value
T
table
0.1163 0.1590. It shows that Null Hypothesis Ho is accepted and the data of pre-test is normally distributed. The
whole description of Lilliefor Test calculation on the table above can be seen on the appendix.
2. Normality Test of Post-Test
Lilliefors Normality test was used in this study to find out the distribution data of post-test. It is used in order to know the data normally distributed or not.
Table 4.9
The Result of Normality Post-test of Experimental and Controlled Class
No Source
Experimental Controlled
1. N
30 30
2. Average
80.63 73.76
3. Variance
36.94 47.37
4. Standard Deviation
6.07 6.88
5. Maximal Score
89 83
6. Minimal Score
70 60
7. T
value
0.0850 0.1105
8. T
table
0.1590 9.
Criteria Normal
The following is the writer’s assumption:
Ho: the data of normal distribution H
1
: the data of un normal distribution The criteria is Ho accepted if T
value
0.1590 and rejected if T
value
0.1590 with α =
5.
Based on Table 4.5, it can be seen that T
value
in experimental class is smaller than T
table
, with the closest Lilliefors critical value of 30 with degree of significance 0.05 which is T
value
T
table
0.0850 0.1590. In addition, T
value
in controlled class is smaller than T
table
, with the closest Lilliefors critical value of 30 with degree of significance 0.05 which is T
value
T
table
0.1105 0.1590. It shows that Null Hypothesis Ho is accepted and the data of post-test is normally distributed. The
whole description of Lilliefor Test calculation on the table above can be seen on the appendix.
3. Homogeneity Test of Pre-Test
The homogeneity test was used to find out whether the group sample which was taken from population is homogeneous or not. The following is the calculation of
homogeneity test of pre-test: Variance of Pre-Test of Experimental Class
S
2
=
∑
-
∑
= –
= 4 586.5 –67.16
2
= 4 586.5 – 4 510.46
= 76.04 Variance of Pre-Test of Controlled Class
S
2
=
∑
-
∑
