Pemecahan LP LANDASAN TEORI

16 Lampiran 1 Pemecahan masalah pencabangan pada contoh 1 dengan menggunakan Lindo 6.1 a. Pemecahan LP MAX 5 X1 + 4 X2 SUBJECT TO X1 +X2 = 5 10 X1 + 6 X2 = 45 X1 =0 x2 =0 END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1 23.75000 VARIABLE VALUE REDUCED COST X1 3.750000 0.000000 X2 1.250000 0.000000 ROW SLACK OR SURPLUS DUAL PRICES 2 0.000000 2.500000 3 0.000000 0.250000 4 3.750000 0.000000 5 1.250000 0.000000 NO. ITERATIONS= 2

b. Pemecahan LP

1 MAX 5 X1 + 4 X2 SUBJECT TO X1 +X2 = 5 10 X1 + 6 X2 = 45 X1 =3 X1 =0 x2 =0 END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1 23.00000 VARIABLE VALUE REDUCED COST X1 3.000000 0.000000 X2 2.000000 0.000000 ROW SLACK OR SURPLUS DUAL PRICES 2 0.000000 4.000000 17 3 3.000000 0.000000 4 0.000000 1.000000 5 3.000000 0.000000 6 2.000000 0.000000 NO. ITERATIONS= 2 c. Pemecahan LP 2 MAX 5 X1 + 4 X2 SUBJECT TO X1 +X2 = 5 10 X1 + 6 X2 = 45 X1 =4 X1 =0 x2 =0 END LP OPTIMUM FOUND AT STEP 1 OBJECTIVE FUNCTION VALUE 1 23.33333 VARIABLE VALUE REDUCED COST X1 4.000000 0.000000 X2 0.833333 0.000000 ROW SLACK OR SURPLUS DUAL PRICES 2 0.166667 0.000000 3 0.000000 0.666667 4 0.000000 -1.666667 5 4.000000 0.000000 6 0.833333 0.000000 NO. ITERATIONS= 1 d. Pemecahan LP 3 MAX 5 X1 + 4 X2 SUBJECT TO X1 +X2 = 5 10 X1 + 6 X2 = 45 X1 =4 X2 =0 X1 =0 x2 =0 END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1 22.50000 18 VARIABLE VALUE REDUCED COST X1 4.500000 0.000000 X2 0.000000 0.000000 ROW SLACK OR SURPLUS DUAL PRICES 2 0.500000 0.000000 3 0.000000 0.500000 4 0.000000 1.000000 5 4.500000 0.000000 6 0.000000 0.000000 NO. ITERATIONS= 2 e. Pemecahan LP 4 MAX 5 X1 + 4 X2 SUBJECT TO X1 +X2 = 5 10 X1 + 6 X2 = 45 X1 =4 X2 =1 X1 =0 x2 =0 END NO FEASIBLE SOLUTION AT STEP 2 SUM OF INFEASIBILITIES= 0.166666671633720 VIOLATED ROWS HAVE NEGATIVE SLACK, OR EQUALITY ROWS NONZERO SLACKS. ROWS CONTRIBUTING TO INFEASIBILITY HAVE NONZERO DUAL PRICE. f. Pemecahan LP 5 MAX 5 X1 + 4 X2 SUBJECT TO X1 +X2 = 5 10 X1 + 6 X2 = 45 X1 =4 X2 =0 X1 =0 x2 =0 END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1 20.00000 VARIABLE VALUE REDUCED COST X1 4.000000 0.000000 X2 0.000000 0.000000 19 ROW SLACK OR SURPLUS DUAL PRICES 2 1.000000 0.000000 3 5.000000 0.000000 4 0.000000 5.000000 5 0.000000 4.000000 6 4.000000 0.000000 7 0.000000 0.000000 NO. ITERATIONS= 2

g. Pemecahan