Observation Reflection on Teacher’s Improvement Cycle Two
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The calculating of post-test 1 is as follows: x =
∑x n
x = 3200 39
x = 82.05
From that calculation, the mean score of the class in post-test 1 is 82.05. It means that the students‟ pronunciation mean score after using
minimal pair drill or after implementing CAR showed the improvement, it is 82.05. If we compare with the previous test pre-test score 82.05, the
difference is 13.84 points by calculation as follows 82.05-68.21 = 13.84.
So, the writer could say that the improvemen t students‟ pronunciation
score is 13.84. The next phase is to know the percentage of pre-test and post-test
difference, it is calculated as follows: P= y1-y x 100
y P= 82.05-68.21 x 100
68.21 P= 13.84 x 100
68.21
P= 20.29
So , the percentages of students‟ mean score improvement from pre-
test to post-test 1 is 20.29. The improvement did not valuably increase.
Next, after calculating the students‟ post-test 1 score, the next step is to calculate the post-test 2; it can be seen as follows:
x = ∑x
n x = 3565
39
x = 91.41
50
From that calculation, the mean score of the class in post-test 2 showed the valuably improvement, it is 91.41.
To calculate the percentage of students‟ improvement of pronunciation test score between pre-test and post-test 2, the writer
computes as follows: P= y2-y x 100
y P= 91.41-68.21 x 100
68.21 P= 23.2 x 100
68.21
P= 34.01
From that computation, it can be seen that the students‟ mean score of post-test 2 showed the higher improvement than the comparison of
mean score in post-test 1, the percentage is 34.01.