Perencanaan Kolom

3.5 Perencanaan Kolom

3.5.1 Kolom lantai 1

  Kolom 80x 80 (frame 2 )

  = 1125725 Nmm • Ukuran kolom

  = (800 x 800 ) mm

  • Diameter tulangan pokok = 25 mm • Selimut beton (p)

  = 50 mm

  • Diameter sengkang

  = 12 mm

  • d = 800-50-12-252

  2621461 , 3 = 429,43 mm > ½ b = 400 mm

  = 0,85 . 458,21 = 389,48 mm Dengan mengabaikan displacement concrete Ccb = ab . b . 0,85 . fc

  = 389,48 . 800 . 0,85. 22,5 = 5959044 N

  Tsb = Csb Karena kolom simetri Pnb = Ccb + Csb – Tsb

  = 5959044 N Prb = 0,65 . Pnb

  P ≤ Prb 2621461,3 N ≤ 3893378,6 N control keluluhan baja

  v y= 0,000167

  50 = 0,0244 ≥ vy = 0,000167

  = 1223153371 + 700 Tsb 1125725900 = 1223153371 + 700 Tsb Tsb = 271967,03 N

  Dipakai tulngan 16 D25

  800 100 − ( 4 . 25 )

  Spasi =

  = 150 mm

  Penulangan geser Tu = 328431,3 Nmm Vu = 1212800 Nmm

  2 S 2 X y = (800-100) . (800-100) =343000000 2 mm

  Tu 2 ≤ υ . 124 . fc . Sx y 1212800 Nmm ≤ 40674769,4 Nmm

  0 , 6 = 88539,02 N ≥ 0 Perlu tulangan geser

  23 . b . d . fc = 23 . 800 . 725,5 . 22 , 5 = 1835385,95 N

  Vs ≤ 23 . b . d . fc

  88539,02 N ≤ 1835385,95 N Dimensi memenuhi syarat Smaks = d4

  = 725,5 4 = 181,375 mm , dipakai 150 mm

  Penulangan geser

  Dipakai D 12-150

3.5.2 Kolom lantai 2

  Kolom 80x 80 (frame 3 )

  P

  = 2053252,2 N

  Vu

  = 255349 N

  Tu

  = 3390700 Nmm

  Mu

  = 629904200 Nmm • Ukuran kolom

  = (800 x 800 ) mm

  • Diameter tulangan pokok = 25 mm • Selimut beton (p)

  = 50 mm

  • Diameter sengkang

  2053252 , 2 = 306,78 mm < ½ b = 400 mm

  = 0,85 . 458,21 = 389,48 mm Dengan mengabaikan displacement concrete Ccb = ab . b .0,85 . fc

  = 389,48 . 800 . 0,85 . 22,5 = 5959044 N

  Tsb = Csb Karena kolom simetri Pnb = Ccb + Csb - Tsb

  = 5959044 N

  Prb = 0,65 . Pnb

  = 0,65 . 5959044 = 3893378,6 N

  P ≤ Prb 2053252,2 N ≤ 3893378,6 N control keluluhan baja v y= 0,000167

  50 = 0,0244 ≥ vy = 0 ,000167

  = 1223153371 + 700 Tsb 629904200 = 1223153371 + 700 Tsb Tsb = 847498,8 N

  As’ = Tsb

  fy

  Dipakai tulangan 16 D 25

  Penulangan geser Tu = 3390700 Nmm Vu = 255349 Nmm

  S 2 X 2 y = (800 – 100 ) . ( 800 – 100 ) = 2 343000000 mm

  Tu 2 ≤ υ . 124 . fc . Sx y 3390700 Nmm ≤ 40674769,4 Nmm

  Vc = 16 . b . d . fc

  = 458846,48 N

  0 , 6 = 33264,81 N ≥ 0 Perlu tulangan geser

  23 . b . d . fc = 23 . 800 . 725,5 . 22 , 5 = 1835385,95 N

  Vs ≤ 23 . b . d . fc 33264,81 N ≤ 1835385,95 N

  Dimensi memenuhi syarat Smaks = d4

  = 725,5 4 = 181,375 mm , dipakai 150 mm

  Penulangan geser

  Dipakai D12 - 150

3.5.3 Kolom lantai 3

  Kolom 70x 70 (frame 4 )

  = 568184500 Nmm • Ukuran kolom

  = (700 x 700 ) mm

  • Diameter tulangan pokok = 25 mm • Selimut beton (p)

  = 50 mm

  • Diameter sengkang

  1483837 , 2 = 382,92 mm < ½ b = 350 mm

  Cb =

  . d

  600 + fy

  = 0,85 . 395,05 = 355,79 mm Dengan mengabaikan displacement concrete Ccb = ab . b . 0,85 . fc

  = 355,79 . 700 . 0,85 . 22,5 = 4495452,039 N

  Tsb = Csb Karena kolom simetri Pnb = Ccb + Csb - Tsb

  = 4495452,039 N Prb = 0,65 . Pnb

  = 0,65 . 4495452,039 = 2922043,83 N

  P ≤ Prb 1438837,2 N ≤ 2922043,83 control keluluhan baja

  v y= 0,000167

  50 = 0,021 ≥ vy = 0,000167

  = 818644293,6 N + 600 Tsb 568184500 = 818644293,6 + 600 Tsb Tsb = 417432,98 N

  2 = 2385,33 mm Dipakai tulangan 12 D25

  700 100 − ( 3 . 25 )

  Spasi =

  2 = 262,5 mm, dipakai 150 mm Penulangan geser

  Tu = 10660000 Nmm Vu = 227489,4 Nmm

  2 S 2 X y = ( 700 –100 ) . ( 700 –100 )

  2 = 216000000 mm

  υ . 124 . fc . Sx 2 y = 0,6 . 124 .

  = 25614449,05 Nmm

  Tu 2 ≤ υ . 124 . fc . Sx y 10660000 Nmm ≤ 256140449,05 Nmm

  0 , 6 = 32998,18 N ≥ 0 Perlu tulangan geser

  23 . b . d . fc = 23 . 700 . 625,5 . 22 , 5 = 1184603,27 N

  Vs ≤ 23 . b . d . fc 32998,18 N ≤ 1184603,27 N

  Dimensi memenuhi syarat Smaks = d 4

  = 156.375 mm, dipakai 150 mm Penulangan geser Vs Av = s

  fy . d

  = 2 22,609 mm Dipakai D 12-150

3.5.4 Kolom lantai 4

  Kolom 60x 60 (frame 19 )

  = 736591000 Nmm • Ukuran kolom

  = (600 x 600 ) mm

  • Diameter tulangan pokok = 25 mm • Selimut beton (p)

  = 50 mm

  • Diameter sengkang

  = 12 mm

  • Fy = 350 MPa • d = 600 - 50 - 12 - 25 2

  = 525,5 mm

  e= Mu

  1118951 , 9 = 658,28 mm > 12 b = 300mm

  = 0,85 . 331,89 = 282,11 mm Dengan mengabaikan displacement concrete Ccb = ab . b . 0,85 . fc

  = 282,11 . 600 . 0,85 . 22,5 = 3237218,28 N

  Tsb = Csb Karena kolom simetri Pnb = Ccb + Csb - Tsb

  = 3237218,28 N Prb = 0,65 . Pnb

  = 0,65 . 3237218,28 = 2104191,88 N

  P ≤ Prb 1118951,9 N ≤ 2104191,88 N control keluluhan baja P ≤ Prb 1118951,9 N ≤ 2104191,88 N control keluluhan baja

  = 514539659,5 + 500 Tsb 736591000 = 514539659,5 + 500 Tsb Tsb = 444102,68 N

  Dipakai tulangan 8 D 25

  600 100 − ( 3 . 25 )

  Spasi =

  2 = 212,5 mm, dipakai 150 mm

  Penulangan geser

  Vu = 333098,7 Nmm

  2 S 2 X y = ( 600 – 100 ) . ( 600 – 100 ) = 2 125000000 mm

  υ . 124 . fc . Sx 2 y = 0,6 . 124 . 22 , 5 . 1256000000

  =14823176,53 Nmm

  Tu 2 ≤ υ . 124 . fc . Sx y 16062300 Nmm ≥ 14823176,53 Nmm

  b . d

  Ct =

  2 ∑

  0 , 6 = 316403,45 N ≥ 0

  Perlu tulangan geser

  23 . b . d . fc = 23 . 600 . 525,5 . 22 , 5 = 997066,14 N

  Vs ≤ 23 . b . d . fc 316403,45 N ≤ 997066,14 N

  Dimensi memenuhi syarat Smaks = d 4

  = 525,5 4 = 131,13 mm, dipakai 150 mm

  Penulangan geser Vs Av = s

  Dipkai D 12-150 mm

  Kolom lantai 5

  Kolom 60x 60 (frame 20 )

  P

  = 801470,1 N

  Vu

  = 242316,6 N

  Tu

  = 78669000 Nmm

  = 703405000 Nm • Ukuran kolom

  Mu

  = (600 x 600 ) mm

  • Diameter tulangan pokok = 25 mm • Selimut beton (p)

  = 50 mm

  • Diameter sengkang

  801470 , 1 = 877,64 ≥ ½ b = 300 mm

  = 0,85 . 331,89 = 282,11 mm Dengan mengabaikan displacement concrete Ccb = ab . b . 0,85 . fc

  = 3237218,28 N Tsb = Csb Karena Tsb dan Csb simetri Pnb = Ccb + Csb - Tsb

  = 3237218,28 N Prb = 0,65 . Pnb

  = 0,65 . 3237218,28 = 2104191,88 N

  P ≤ Prb 801470,1 N ≤ 2104191,88 N Kontrol Keluluhan baja v y= 0,000167

  Mnb = Ccb( h -

  = 514539659,5 + 500 Tsb 703405000 = 514539659,5 + 500 Tsb Tsb = 377730,68 N

  As’ = Tsb

  fy

  = 2 2158,46 mm Dipakai tulangan 8 D25

  600 100 − ( 3 . 25 )

  Spasi =

  2 = 212,5 mm, dipakai 150 mm Penulangan geser

  Tu = 78669000 Nmm Vu =242316,6 Nmm

  2 S 2 X y = ( 600 –100 ) . (600 –100 ) =125000000 2 mm

  Tu 2 ≤ υ . 124 . fc . Sx y 78669000 Nmm ≥ 14823176,53 Nmm

  b . d

  Ct =

  2 ∑

  x y

  600 . 525 , 5

  =

  125000000

  = 0,0025

  0 , 6 = 293566,07 N ≥0

  Perlu tulangan geser

  23 . b . d . fc = 23 . 600 . 525,5 . 22 , 5 = 997066,14 N

  Vs ≤ 23 . b . d . fc 293566,07 N ≤ 997066,14 N

  Dimensi memenuhi syarat Smaks = d 4

  = 525,5 4 = 131,13 mm, dipakai 150 mm Penulangan geser

  Dipakai D12-150