Table 4.4 Normality Testing of Posttest
S² = 50.494
L
o
= 0.088 L
t
= 0.145
According to the Table 4.3 and 4.4, the value of L
o
of pretest and posttest are 0.096 and 0.088, so L
o
L
t
0.096 and 0.088 0.145. It means H
a
is accepted, so the normality testing of pretest and posttest for controlled class indicates that data are
distributed normally. b. Data of Experimental Class
1 H
a
: Data has been distributed normally L
o
L
t
. H
o
: Data has not been distributed normally L
o
L
t
. 2 Because number of data is more than 30, the value of standard error is
gotten from L
t
= significance level, number of sample. L
t
5 = 0.05, 37
3 L
o
see appendix 4 and 5
Table 4.5 Normality of Pretest
S² = 76.887
L
o
= 0.1084 L
t
= 0.145
Table 4.6 Normality of Posttest
Based on the table above, it is gotten 0.1084 and 0.088 as the value of L
o
for the pretest and posttest of experimental class. Then, the value of L
o
is compared to the value of L
t
to get the result of normality testing of the data. From the data, L
o
L
t
. It means the data of this research are distributed normally.
2. Homogeneity Testing
a. H
a
: Condition of experimental class is not different from controlled class. H
o
: Condition of experimental class is different from controlled class. b. α = 5 : Significance Level
c. F
table
see Distribution table for the statistic: F
t
α, n-1, n-1 = F 0.05, 36, 36 = 1.74 d.
e. Conclusion : F
o
F
t
1.14 and 1.43 1.74, H
a
is accepted, so the data of pretest and posttest from controlled and experimental class are homogenous.
S² = 35.243
L
o
= 0.088 L
t
= 0.145
3. Hypothesis Testing
Hypothesis testing is the last step to answer the formulation of this research. From the hypothesis testing, it will be found the result whether entertaining Power
Point media gives significant influence on students’ understanding of Passive Voice. a. H
a
: There is an influence of using Power Point media on students’ understanding of Passive Voice t
o
t
t
. H
o
: There is no influence of using Power Point media on students’ understanding of Passive Voice t
o
t
t
b. α = 5 c. t
t
see appendix 2 = 0.05, n1+n2-2 = 0.05, 72
= 2.00 d. Hypothesis testing is calculated by the formula, as follows:
in which: : mean score of controlled class
: mean score of experimental class : Standard Error of experimental and controlled class
SE : Standard Error
SD : Deviation Standard
n : number of students
e. The steps in calculating hypothesis testing 1 M
X
: 72.40 M
Y
: 80.45 2 SD
X
: 7.1 SD
Y
: 5.93
