= kkaljam
Reaksi II CaCH
3
COO
2
+ H
2
SO
4
2CH
3
COOH + CaSO
4
ΔHf CaCH
3
COO
2
= ΔHf
o
25 =
kkalkg x kgjam
= kkaljam
ΔHf H
2
SO
4
= ΔHf
o
25 =
kkalkg x kgjam
= kkaljam
ΔHf CH
3
COOH =
ΔHf
o
25 kkalkg x
kgjam =
kkaljam ΔHf CaSO
4
= ΔHf
o
25 =
kkalkg x kgjam
= kkaljam
ΔHr
o
25 =
ΔHf produk - ΔHf reaktan
= {-1061,023 + -727,689} - {-770,362+-606,675}
= kkaljam
m.Cp.dT =
x x
55 -1061,023
H2SO4
Σ
-411,675 -727,689
Reaktan
CaC
2
O
4
-1935,946 0,376
-38532,532
Komponen
-606,675
m.Cp.dTr ΔHr
o
80 = ΔHr
o
25 + m.Cp.dTp - m.Cp.dTr
0,495 4310,370
-29944,659
0,307 -770,362
m.Cp.dTp
6508,698 6479,813
-2490,662 90,269
4400,639
0,426 12988,511
kkaljam ΔHr
o
25 = ΔHfp -ΔHfr
-1556,563 0,495
-1976,327
0,769
Produk
CaSO
4
C
2
H
2
O
4
Universitas Sumatera Utara
CaCH
3
COO
2
= kkaljam
m.Cp.dT =
x x
55 H
2
SO
4
= kkaljam
mCp.dT =
x x
55 CH
3
COOH =
kkaljam m.ʃCp.dT
= x
CaSO
4
= kkaljam
ΔHr
o
80 II =
ΔHf
o
25 +
m.Cp.dTp - m.Cp.dTr
= +
- =
kkaljam
Reaksi III : CaHCOO
2
+ H
2
SO
4
2HCOOH + CaSO
4
ΔHf CaHCOO
2
= ΔHf
o
25 =
kkalkg x kgjam
= kkaljam
ΔHf H
2
SO
4
= ΔHf
o
25 =
kkalkg x kgjam
= kkaljam
20,932
2549,272 6,264
10,792
4,167
-423,913
ΔHr
o
80 = ΔHr
o
25 + m.Cp.dTp - m.Cp.dTr m.Cp.dTr
kkaljam
27,196 -411,675
0,376 0,522
4,167 0,426
9,781 0,307
6,264
0,306 14,958
ΔHr
o
25 = ΔHfp -ΔHfr m.Cp.dTp
20,932
0,406
-1976,327 Σ
-411,675
1035,709 CaSO
4
CH
3
COOH 10,792
14,958 27,196
-605,289 0,371
Komponen Reaktan
CaCH
3
COO
2
H
2
SO
4
Produk
Universitas Sumatera Utara
ΔHf HCOOH =
= kkalkg x
kgjam =
kkaljam ΔHf CaSO
4
= =
kkalkg x kgjam
= kkaljam
ΔHr
o
25 =
ΔHf produk - ΔHf reaktan
= {-1058,600+-611,290} - {605,290 + 1035,709}
= kkaljam
m.Cp.dT =
x x
55 CaHCOO
2
= m.Cp.dT
= x
x 55
H
2
SO
4
= kkaljam
mCp.dT =
x x
55 HCOOH
= kkaljam
m.ʃCp.dT =
x CaSO
4
= kkaljam
ΔHr
o
80 III =
ΔHf
o
25 +
m.Cp.dTp - m.Cp.dTr
= +
- =
kkaljam
18,781 6,249
0,288 0,524
0,425
18,781
HCOOH Σ
4,157 8,286
-2100,310 12,443
-2490,662 ΔHf
o
25 ΔHf
o
25
0,406 -2126,087
0,306 kkaljam
6,249
-2100,310 12,443
4,157
Reaktan CaHCOO
2
H
2
SO
4
-1058,600
-2106,647
12,531
ΔHr
o
80 = ΔHr
o
25 + m.Cp.dTp - m.Cp.dTr ΔHr
o
25 = ΔHfp -ΔHfr
0,288
9,781 0,425
0,561
0,371
Komponen
12,531
Produk CaSO
4
kkaljam
-2100,310 -611,290
m.Cp.dTp m.Cp.dTr
8,286
Universitas Sumatera Utara
Reaksi IV :
CaOH
2
+ H
2
SO
4
CaSO
4
+ 2H
2
O ΔHf CaOH
2
= ΔHf
o
25 =
kkalkg x kgjam
= kkaljam
ΔHf H
2
SO
4
= ΔHf
o
25 =
kkalkg x kgjam
= kkaljam
ΔHf CaSO
4
= ΔHf
o
25 =
kkalkg x kgjam
= kkaljam
ΔHf 2H
2
O =
ΔHf
o
25 =
kkalkg x kgjam
= kkaljam
ΔHr
o
25 =
ΔHf produk - ΔHf reaktan
= {-4680,415+-1597,250} - {-2767,181 +
-3255,136} =
kkaljam m.ʃCp.dT
= x
CaOH
2
= kkaljam
m.Cp.dT =
x x
55 H
2
SO
4
= kkaljam
m.ʃCp.dT =
x CaSO
4
= kkaljam
m.Cp.dT =
x x
55 2H
2
O =
kkaljam ΔHr
o
80 IV =
ΔHf
o
25 +
m.Cp.dTp - m.Cp.dTr
= +
- =
kkaljam -343,707
-3183,514 1,022
-3255,136
-2676,181
18,380 -3210,994
0,497 -4680,415
-1597,250
16,263
43,894 27,631
28,155 -1976,327
1,354
-346,348 -2490,662
0,497 1,029
-346,348 1,022
46,535 15,905
1,354 0,371
9,781 1,879
1,879
Universitas Sumatera Utara
ΔHr total =
ΔHr
o
25I + ΔHr
o
25II + ΔHr
o
25III + ΔHr
o
25IV =
+ +
+ kkaljam
= kkaljam
Karena reaksi terjadi eksoterm maka diperlukan air pendingin Air pendingin yang masuk pada suhu 25
o
C =
K dan keluar pada
45
o
C =
K Neraca Panas
Q pendingin =
ΔHp + ΔHr
o
25 total -ΔHr =
11636,441 + -32802,992 -117162,495 =
kkaljam Q air pendingin =
m.Cp.dT =
m x
x -
m =
x 20
m =
kgjam
Neraca Panas di Reaktor Asam Oksalat
-346,348
-72723,062
Q air pendingin
ΔHr
o
80 = ΔHr
o
25 + m.Cp.dTp - m.Cp.dTr ΔHr
