Perencanaan Pelat Lantai Perhitungan Momen

commit to user Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat 123 50 30 30 50 500 500 500 400 500 500 500 200 200 200 200 Naik Turun 20 20 A 20 30 A B C C B A A D D D D A D E F F D D D D C C B D D G H I D D D D D A B C F C A A x x x x x x x x B F G H I G H G H E B A B C D E F G H C C E 1 2 3 4 5 4 1 1 2

BAB 5 PELAT

LANTAI

5.1. Perencanaan Pelat Lantai

Gambar 5.1. Denah Plat Lantai Lantai 2 5.2. Perhitungan Pembebanan Pelat Lantai a. Beban Hidup qL Berdasarkan PPIUG 1983 yaitu : Beban hidup fungsi gedung untuk puskesmas tiap 1 m = 250 kgm b. Beban Mati qD tiap 1 m Berat plat sendiri = 0,12 × 2400 × 1 = 288 kgm Berat keramik 1 cm = 0,01 × 2400 × 1 = 24 kgm Berat Spesi 2 cm = 0,02 × 2100 × 1 = 42 kgm Berat plafond + instalasi listrik = 25 kgm Berat Pasir 2 cm = 0,02 × 1600 × 1 = 32 kgm qD = 411 kgm commit to user 124 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat A 500 20 c. Beban Ultimate qU Untuk tinjauan lebar 1 m pelat maka : qU = 1,2 qD + 1,6 qL = 1,2 . 411 + 1,6 . 250 = 893,2 kgm 2

5.3. Perhitungan Momen

a. Tipe A A 500 20 Gambar 5.2. Pelat Tipe A 2,5 2,0 5,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .92 = 328,697 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .47 = 167,922 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .122 = -435,882 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .79 = -282,251 kgm b. Tipe A’ Gambar 5.3. Pelat Tipe A’ commit to user 125 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat 2,5 2,0 5,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .90 = 321,552 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .48 = 171,494 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .120 = -428,736 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .78 = -278,678 kgm c. Tipe B B 20 300 Gambar 5.4. Pelat Tipe B 1,5 2,0 3,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .69 = 246,523 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .51 = 182,213 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .94 = -335,843 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .76 = -271,533 kgm d. Tipe B’ B 200 Gambar 5.5. Pelat Tipe B’ 1,5 2,0 3,0 Lx Ly = = commit to user 126 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .56 = 200,077 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .37 = 132,194 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .76 = -271,533 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .57 = -203,650 kgm e. Tipe C 20 200 C Gambar 5.6. Pelat Tipe C 1,0 2,0 2,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .38 = 135,766 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .43 = 153,630 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .55 = -196,504 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .60 = -214,368 kgm f. Tipe C’ 20 200 C Gambar 5.7. Pelat Tipe C’ 1,0 2,0 2,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .36 = 128,620 kgm commit to user 127 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .36 = 128,620 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .52 = -185,785 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .52 = -185,785 kgm g. Tipe D 500 30 D Gambar 5.8. Pelat Tipe D 1,67 3,0 5,0 Lx Ly = = → 1,7 Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .59 = 474,289 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .36 = 289,397 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .81 = -651,143 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .57 = -458,212 kgm h. Tipe D’ 500 300 D Gambar 5.9. Pelat Tipe D’ 1,67 3,0 5,0 Lx Ly = = → 1,7 Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .61 = 490,367 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .35 = 281,358 kgm commit to user 128 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .82 = -659,182 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .57 = -458,212 kgm i. Tipe E E 40 Gambar 5.10. Pelat Tipe E 1,3 3,0 4,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .50 = 401,940 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .38 = 305,474 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .69 = -554,677 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .57 = -458,212 kgm j. Tipe F 200 400 F Gambar 5.11. Pelat Tipe F 2,0 2,0 4,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .88 = 314,406 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .49 = 175,067 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .118 = -421,590 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .79 = -282,251 kgm commit to user 129 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat k. Tipe G G 30 Gambar 5.12. Pelat Tipe G 1,0 3,0 3,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .36 = 289,397 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .36 = 289,397 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .52 = -418,018 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .52 = -418,018 kgm l. Tipe H 200 300 H Gambar 5.13. Pelat Tipe H 1,5 2,0 3,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .56 = 200,077 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 2 2 .37 = 132,194 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .76 = -271,533 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 2 2 .57 = -203,650 kgm commit to user 130 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat m. Tipe I I 400 30 Gambar 5.14. Pelat Tipe I 1,3 3,0 4,0 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .50 = 401,940 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 3 2 .38 = 305,474 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .69 = -554,677 kgm Mty =- 0,001.qu . Lx 2 . x = -0.001. 893,2. 3 2 .57 = -458,212 kgm n. Tipe x x 50 25 Gambar 5.15. Pelat Tipe x 5 0,5 2,5 Lx Ly = = Mlx = 0,001.qu . Lx 2 . x = 0.001. 893,2. 0,5 2 .108 = 24,116 kgm Mly = 0,001.qu . Lx 2 . x = 0.001. 893,2. 0,5 2 .79 = 17,641 kgm Mtx = -0,001.qu . Lx 2 . x = -0.001. 893,2. 0,5 2 .124= -27,689 kgm commit to user 131 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat Tabel 5.1. Perhitungan Plat Lantai TIPE PLAT LyLx m Mlx kgm Mly kgm Mtx kgm Mty kgm 52 = 2,5 328,697 167,922 -435,882 -282,251 52 = 2,5 321,552 121,494 -428,736 -278,678 32= 1,5 246,523 182,213 -335,843 -271,533 32= 1,5 200,077 132,194 -271,533 -203,650 22=1,0 135,766 153,630 -196,504 -214,368 22=1,0 128,620 128,620 -185,785 -185,785 53=1,7 474,289 289,397 -651,143 -458,212 53=1,7 490,367 281,358 -650,182 -458,212 43=1,3 401,940 305,474 -554,677 -458,212 42=2,0 314,406 175,067 -421,590 -282,251 33=1,0 289,397 289,397 -418,018 -418,018 32=1,5 200,077 132,194 -271,533 -203,650 43=1,3 401,940 305,474 -554,677 -458,212 2,50.5=5,0 24,116 17,641 -27,689 - A B A’ B’ C C’ D D’ E F G H I x commit to user 132 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat h d d y d x Dari perhitungan momen diambil momen terbesar yaitu: Mlx = 490,367 kgm Mly = 305,474 kgm Mtx = -651,143 kgm Mty = -458,212 kgm Data : Tebal plat h = 12 cm = 120 mm Tebal penutup d’ = 20 mm Diameter tulangan ∅ = 10 mm b = 1000 fy = 240 Mpa f’c = 20 Mpa Tinggi efektif Gambar 5.16. Perencanaan Tinggi Efektif dx = h – p - ½ Ø = 120 – 20 – 5 = 95 mm dy = h – p – Ø - ½ Ø = 120 – 20 - 10 - ½ . 10 = 85 mm Untuk plat digunakan : ρb = ⎟⎟ ⎠ ⎞ ⎜⎜ ⎝ ⎛ + fy fy fc 600 600 . . . 85 , β = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + 240 600 600 . 85 , . 240 20 . 85 , = 0,043 commit to user 133 Tugas Akhir Perencanaan St rukt ur dan Rencana Anggaran Biaya Gedung Puskesmas 2 L ant ai Bab 5 Perencanaan Plat ρ max = 0,75 . ρb = 0,032 ρ min = 0,0025 untuk pelat

5.4. Penulangan lapangan arah x