Normality Test Calculation of the Experimental and Control Normality Test Calculation of the

Figure A .2. Normal Histogram of the Control Class‟ Pretest Score Both the figure A.1 and A.2 above represented the histogram which had a shape like a bell-curve indicating that the distribution data was normal. Even though the histog ram‟s bell-curve in the figure A.2 was fatter and shorter than the figure one, but both curves were symmetrical. Hence, it could be said that the data of the experimental and control class‟ pretest met the criteria of normality.

B. The Histogram of the Experimental and Control

Class’ Posttest The following was two normal histograms which showed that the data of the experimental and control class‟ posttest score met the criteria of normal distribution: Figure B .1. Normal Histogram of the Experimental Class‟ Posttest Score Figure B .2. Normal Histogram of the Control Class‟ Posttest Score Both the figure B.1 and B.2 presented that both the histograms had a curve-bell shape look-alike and the curves were symmetrical. It meant that the experimental and control class‟ posttest met the criteria of normality. 80 APPENDIX 8 Homogeneity Test

A. Homegeneity Test

After finishing the normality test, the homogeneity test was also required as a prerequisite to do analysis test. To calculate homogeneity test, the researcher used Levene Statistic Test from IBM Statistics SPSS 19 software. The following is the result which was obtained from this calculation: Table A.1 Test of Homogeneity of Variances Pretest Score Levene Statistic df1 df2 Sig. 1.847 1 50 .180 After gaining the result of homogeneity test of the experimental and control class’ pretest, it was continued to interpret the result using the degree of significance 5 α = 0.05. The criteria of taking the decision of homogeneity test is as follow: 1. Determining the hypothesis: H : sample data comes from population which has homogenous variance. H 1 : sample data comes from population which does not have homogenous variance. 2. Deciding criteria to test the hypothesis: If the significance level probability value p ≥ 0.05, H is accepted. If the significance level probability value p 0.05, H is rejected. From the result of the Levene Statistic Test above, it could be seen that the significance level or probability value p of the data from the experiment and control’s pretest score was 0.180. It meant that the significacance level or

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