Mencari Panjang Batang Perencanaan Gording

33 = 2 2 6 . 10 . 6 1 5 . 3856 10 . 6 . 6 1 9 . 2507 + = 89.354 kgcm = 89.354 kgcm 2 ≤ 100 kgcm 2 = σ ltr OK Jadi, usuk kayu dengan dimensi 57 cm aman dipakai Gambar 1. Rangka Kuda - Kuda

4. Mencari Panjang Batang

Tabel 3. Gaya-gaya pada Kuda-kuda No Batang Panjang Batang cm No Batang Panjang Batang cm a1 = a12 140 d1 = d10 180 a2 = a11 140 d2 = d9 210 a3 = a10 140 d3 = d8 254 a4 = a9 150 d4 = d7 249 a5 = a8 104 d5 = d6 277 a6 = a7 104 d11 = d12 306 b1= b12 156 v1 = v11 62 b2 = b11 156 v2 = v10 98 b3 = b10 156 v3 = v9 134 b4 = b9 167 v4 = v8 170 b5 = b8 200 v5 = v7 196 34 b6 = b7 200 v6 231 b13 = b16 119 v12 = v14 98 b14 = b15 115 v13 231

5. Perencanaan Gording

Jarak gording = 1.5 m Jarak kuda-kuda = 3.6 m a. Pembebanan Beban mati - berat sendiri gording taksiran = 3.6 x 1.5 = 5.4 kgm - berat sendiri genteng = 50 x 1.5 = 75 kgm - berat penggantung + plafond = 18 x 1.5 = 27 kgm = 107.4 kgm - berat lain-lain 10 = 10 x 107.4 = 10.74 kgm q = 118.14 kgm Momen akibat beban mati q x = q x cos 30 = 118.14 x 0.866 = 102.312 kgm qy = q x sin 30 = 118.14 x 0.5 = 59.07 kgm Mx = 18 x 102.312 x 3.6 2 = 165.745 kgm 35 My = 18 x 59.07 x 3.6 2 Beban Hidup P = 100 kg Py = P x sin 30 = 100 x 0.5 = 50 kg Px = P x cos 30 = 100 x 0.866 = 86.6 kg My = ¼ x Py x l = ¼ x 50 x 3.6 = 45 kgm Mx = ¼ x Px x l = ¼ x 86.6 x 3.6 = 77.94 kgm Beban angin Koefisien angin tekan = 0.02 x 30 -0.4 = 0.2 w = 0.2 x 1.5 x 25 = 7.5 kgm M = 18 x 7.5 x 3.6 2 = 12.15 kgm Koefisien angin hisap = -0.4 w = -0.4 x 1.5 x 25 = -15 kgm M = 18 x -15 x 3.6 2 = -24.3 kgm Momen kombinasi a. Beban mati + beban hidup 36 Mx = 165.745 + 77.94 = 243.69 kgm My = 95.693 + 45 = 140.69 kgm b. Beban mati + beban hidup + beban angin Mx = 165.745 + 77.94 + 12.15 = 255.84 kgm My = 95.693 + 45 = 140.69 kgm b. Pendimensian Gording Direncanakan memakai profil C tipis, atap yang didunakan adalah atap genteng jadi merupakan struktur yang tegar sehingga diambil momen arah x yang terbesar Mx = 255.84 kgm 3 2 99 . 15 1600 25584 cm cm kg kgcm Mx Wx = = = σ Dicoba profil C 150x50x20x4.5 dari tabel Profil Baja didapatkan : W x = 49.0 cm 3 W y = 10.5 cm 3 Ix = 368 cm 4 Iy = 35.7 cm 4 Weight = 9.20 kgm Kontrol tegangan σ ytsb = M x W x = 2558449.0 cm 3 = 522.12 kgcm 2 σ = 1600 kgcm 2 Kontrol lendutan f ijin = l 250 x 1 = 360 250 = 1.44 cm 37 fx = xExlx Pxxl xExlx xqxxl 48 384 5 3 4 + = 368 10 1 . 2 48 360 6 . 86 368 10 1 . 2 384 360 02312 . 1 5 6 3 6 4 x x x x x x x x x + = 0.29 + 0.11 = 0.4 cm fy = xExIy l Pyx xExIy l xqyx 48 2 384 2 5 3 4 + = 7 . 35 10 1 . 2 48 2 360 50 7 . 35 10 1 . 2 384 2 360 5907 . 5 6 3 6 4 x x x x x x x x x + = 0.11 + 0.08 = 0.19 cm f = 2 2 fy fx + = + 2 4 . 2 19 . = 0.44 cm 1.44 cm……………oke

6. Menghitung Pembebanan Kuda-kuda