L5 - 17
Uji Cukup ∑ Xi
2
= 42
2
+ 44.5
2
+ ...... + 40
2
= 248917.31 ∑ Xi
2
= 42+ 44.5 + ..... + 40
2
= 4914.10
2
= 24148378.81
2 2
2
i i
i
x x
x N
c N
2
4914.10 1
24148378.8 248917.31
100 1
. 2
= 12.31 N = 100
N’ N → data yang diperoleh sudah cukup
8. Lebar Pinggul
Uji Normal
k = 3.3 log n + 1
= 3.3 log 100 + 1 = 7.6 ≈ 8 kelas c = Xmax – Xmin k
= 46 – 31 7.6 = 1.974 ≈ 2
Batas Kelas oi
Z1 Z2
PZ1 P Z2
PZ2 - PZ1
ei ei
gab oi
gab
2
30.95 -
∞ -1.948
0.026 0.026
2.569 9.323
5 2.004
30.95 – 32.95
5 -1.948
-1.321 0.026
0.093 0.068
6.754 32.95
– 34.95 21
-1.321 -0.694
0.093 0.244
0.151 15.062
15.062 21
2.341 34.95
– 36.95 27
-0.694 -0.067
0.244 0.473
0.230 22.952
22.952 27
0.714 36.95
– 38.95 20
-0.067 0.560
0.473 0.712
0.239 23.902
23.902 20
0.637 38.95
– 40.95 15
0.560 1.188
0.712 0.882
0.170 17.011
17.011 15
0.238 40.95
– 42.95 5
1.188 1.815
0.882 0.965
0.083 8.272
11.751 12
0.005 42.95
– 44.95 6
1.815 2.442
0.965 0.993
0.027 2.748
44.95 – 46.95
1 2.442
3.069 0.993
0.999 0.006
0.623 46.95
3.069 ∞
0.999 1
0.001 0.107
100 1
100 100
100 5.939
L5 - 18
Tabel uji normal v = k
– r – 1 v = 6
– 2 – 1 = 3 α = 0.05
2
v, α
= 7.815
2
hasil perhitungan = 5.939
2
hasil perhitungan
2
v, α
sehingga mengikuti distribusi normal Uji Seragam
Subgroup 1
2 3
4 5
6 7
8 9
10 rata - rata
1 37.2
38.7 35.6
39.6 35.2
40.8 40.5
37.0 40.0
37.5 38.21
2 39.6
33.4 36.9
40.0 40.5
39.0 33.0
40.4 36.7
42.3 38.18
3 34.2
38.4 34.0
36.9 39.2
35.7 37.5
31.0 33.4
36.0 35.63
4 34.3
34.0 41.3
39.5 33.5
34.0 38.7
38.0 43.9
40.0 37.72
5 38.5
37.0 35.5
37.0 34.2
40.9 34.6
33.5 37.0
34.0 36.22
6 35.0
42.0 38.5
32.5 35.8
33.8 36.6
44.8 35.3
35.8 37.01
7 46.0
36.0 36.0
36.1 37.8
32.5 37.2
34.0 44.0
34.6 37.42
8 35.4
38.8 41.2
35.2 35.8
35.7 33.3
36.5 35.0
36.0 36.29
9 36.7
32.0 44.0
36.0 36.0
44.5 32.0
41.7 43.4
37.3 38.36
10 34.5
34.5 36.4
34.5 37.8
37.3 39.8
34.7 37.0
39.4 36.59
37.16 Rata-rata
x
= 37.16 = 3.19
008 .
1 10
3.19
n
x
x
c x
BKB
= 37.16 – 21.008 = 35.15
x
c x
BKA
= 37.16 + 21.008 = 39.18
L5 - 19
Grafik Uji Seragam Lebar Pinggul
35.63 36.22
37.01 37.42
36.29 36.59
38.36 37.72
38.18 38.21
BKB = 35.15 BKA = 39.18
34 35
36 37
38 39
40
1 2
3 4
5 6
7 8
9 10
Subgroup ke - R
a ta
- r
a ta
Berdasarkan grafik di atas, dapat disimpulkan bahwa data seragam karena berada dalam batas BKA dan BKB.
Uji Cukup ∑ Xi
2
= 37.2
2
+ 39.6
2
+ ...... + 39.4
2
= 139115.61 ∑ Xi
2
= 37.2+ 39.6 + ..... + 39.4
2
= 3716.30
2
= 13810885.69
2 2
2
i i
i
x x
x N
c N
2
3716.30 9
13810885.6 139115.61
100 1
. 2
= 2.92 N = 100
N’ N → data yang diperoleh sudah cukup
9. Lebar Bahu
