L5 - 31
Uji Cukup ∑ Xi
2
= 8
2
+ 7.5
2
+ ...... + 7.1
2
= 7774.42 ∑ Xi
2
= 8+ 7.5 + ..... + 7.1
2
= 868.80
2
= 754813.44
2 2
2
i i
i
x x
x N
c N
2
868.80 44
. 754813
42 .
7774 100
1 .
2
= 11.99
N = 100 N’ N → data yang diperoleh sudah cukup
14. Tebal Dada
Uji Normal
k = 3.3 log n + 1
= 3.3 log 100 + 1 = 7.6 ≈ 8 kelas c = Xmax – Xmin k
= 32 – 13 7.6 = 2.5
Batas Kelas oi
Z1 Z2
PZ1 P Z2
PZ2 - PZ1
ei ei
gab oi
gab
2
12.95 -
∞ -2.218 0.013
0.013 1.329
6.846 9
0.678 12.95 - 15.45
7 -2.218
-1.487 0.013
0.068 0.055
5.517 15.45 - 17.95
11 -1.487
-0.757 0.068
0.224 0.156
15.603 15.603
8 3.704
17.95 - 20.45 31
-0.757 -0.027
0.224 0.489
0.265 26.478
26.478 28
0.087 20.45 - 22.95
27 -0.027
0.703 0.489
0.759 0.270
26.980 26.980
25 0.145
22.95 - 25.45 17
0.703 1.434
0.759 0.924
0.165 16.508
16.508 15
0.138 25.45 - 27.95
4 1.434
2.164 0.924
0.985 0.061
6.061 7.585
15 7.248
27.95 - 30.45 2
2.164 2.894
0.985 0.998
0.013 1.334
30.45 - 32.95 1
2.894 3.624
0.998 1.000
0.002 0.176
32.95 3.624
∞ 1.000
1 0.000
0.014 100
1 100
100 100
12.00
L5 - 32
Tabel uji normal v = k
– r – 1 v = 6
– 2 – 1 = 3 α = 0.05
2
v, α
= 7.815
2
hasil perhitungan = 12
2
hasil perhitungan
2
v, α
sehingga mengikuti distribusi normal Uji Seragam
Subgroup 1
2 3
4 5
6 7
8 9
10 rata - rata
1 23.0
18.3 26.0
23.0 13.0
15.0 17.2
19.0 23.0
23.0 20.37
2 18.6
15.8 21.0
25.0 20.0
17.0 23.4
21.8 23.0
22.0 20.47
3 21.0
19.0 15.0
18.0 13.0
22.0 18.0
17.1 24.0
19.0 18.61
4 22.0
25.0 18.0
20.0 19.0
18.0 19.0
22.0 28.0
21.0 21.20
5 19.5
22.0 21.0
17.0 24.5
22.0 17.0
17.5 27.0
19.9 20.74
6 20.0
24.0 23.0
16.0 22.0
20.2 19.5
19.0 17.0
27.1 20.84
7 22.0
18.6 28.0
23.0 21.5
22.3 18.6
20.0 19.0
22.8 21.50
8 18.8
21.2 19.0
20.4 18.3
21.5 23.5
24.0 26.0
22.7 21.54
9 19.6
17.5 14.1
22.2 21.3
32.0 15.0
22.5 23.0
18.0 20.52
10 21.1
16.4 21.1
20.2 18.0
22.0 14.0
22.0 20.5
23.0 19.83
20.56 Rata-rata
x
= 20.54 = 3.42
08 .
1 10
3.42
n
x
x
c x
BKB
= 20.54 – 21.08 = 18.38
x
c x
BKA
= 20.54 + 21.08 = 22.71
L5 - 33
20.37 20.47
18.61 21.20
20.74 20.84
21.50 21.54
20.52 19.83 BKB = 18.38
BKA = 22.71
18.0 18.5
19.0 19.5
20.0 20.5
21.0 21.5
22.0 22.5
23.0
1 2
3 4
5 6
7 8
9 10
R a
ta -
r a
ta
Subgroup ke -
Grafik Uji Seragam Tebal Dada
Berdasarkan grafik di atas, dapat disimpulkan bahwa data seragam karena berada dalam batas BKA dan BKB.
Uji Cukup ∑ Xi
2
= 23
2
+ 18.6
2
+ ...... + 23
2
= 43400.69 ∑ Xi
2
= 23+ 18.6 + ..... + 23
2
= 1951.5
2
= 3808352.25
2 2
2
i i
i
x x
x N
c N
2
1951.5 25
. 3808352
69 .
43400 100
1 .
2
= 55.85
N = 100 N’ N → data yang diperoleh sudah cukup
15. Panjang Jari Tengah
