L5 - 8
N = 100 N’ N → data yang diperoleh sudah cukup
4. Tinggi Popliteal
Uji Normal
k = 3.3 log n + 1
= 3.3 log 100 + 1 = 7.6 ≈ 8 kelas c = Xmax – Xmin k
= 48.8 – 37.6 7.6 = 1.47 ≈ 1.5
Batas Kelas oi
Z1 Z2
PZ1 P Z2
PZ2 - PZ1
ei ei
gab oi
gab
2
37.55 -
∞ -2.057
0.020 0.020
1.985 7.133
9 0.489
37.55 – 39.05
9 -2.057
-1.466 0.020
0.071 0.051
5.148 39.05
– 40.55 13
-1.466 -0.875
0.071 0.191
0.119 11.944
11.944 13
0.093 40.55
– 42.05 17
-0.875 -0.284
0.191 0.388
0.197 19.737
19.737 17
0.379 42.05
– 43.55 28
-0.284 0.307
0.388 0.620
0.232 23.233
23.233 28
0.978 43.55
– 45.05 18
0.307 0.898
0.620 0.815
0.195 19.483
19.483 18
0.113 45.05
– 46.55 8
0.898 1.488
0.815 0.932
0.116 11.639
11.639 8
1.138 46.55
– 48.05 4
1.488 2.079
0.932 0.981
0.050 4.952
6.831 7
0.004 48.05
– 49.55 3
2.079 2.670
0.981 0.996
0.015 1.500
49.55 2.670
∞ 0.996
1 0.004
0.379 100
1 100
100 100
3.194
Tabel uji normal v = k
– r – 1 v = 7
– 2 – 1 = 4 α = 0.05
2
v, α
= 9.488
2
hasil perhitungan = 3.194
2
hasil perhitungan
2
v, α
sehingga mengikuti distribusi normal
L5 - 9
Uji Seragam
Subgroup 1
2 3
4 5
6 7
8 9
10 rata - rata
1 42.0
41.5 45.0
41.6 38.7
43.5 43.2
39.4 46.0
43.7 42.46
2 48.8
39.5 43.5
45.5 41.5
41.6 44.0
42.5 38.8
43.0 42.91
3 43.0
42.0 48.0
45.0 37.6
42.2 47.0
39.5 42.3
38.0 42.79
4 46.5
45.0 46.4
43.7 42.5
41.3 42.5
38.3 43.6
42.3 43.21
5 46.5
43.8 43.0
41.5 42.4
42.5 42.3
40.5 43.7
39.0 42.52
6 45.0
46.2 39.0
40.4 43.5
41.8 43.1
43.2 41.0
41.9 42.51
7 45.9
45.7 40.0
42.1 44.2
42.0 39.4
42.0 43.2
42.1 42.66
8 40.5
43.5 48.5
44.3 40.3
39.5 42.2
43.4 41.5
44.0 42.77
9 47.8
44.5 39.7
48.6 39.0
43.0 41.1
44.1 44.0
41.2 43.30
10 44.6
38.6 43.0
47.6 42.7
39.2 44.7
42.0 40.4
43.2 42.60
42.77 Rata-rata
x
= 42.77 = 2.54
80 .
10 2.54
n
x
x
c x
BKB
= 42.77 – 20.80 = 41.17
x
c x
BKA
= 42.77 + 20.80 = 44.38
Grafik Uji Seragam Tinggi Popliteal
42.77 42.66
42.51 42.52
42.79 42.6
43.3 43.21
42.91 42.46
BKB = 41.17 BKA = 44.38
40 41
42 43
44 45
1 2
3 4
5 6
7 8
9 10
Subgroup ke - R
a ta
- r
a ta
Berdasarkan grafik di atas, dapat disimpulkan bahwa data seragam karena berada dalam batas BKA dan BKB.
L5 - 10
Uji Cukup ∑ Xi
2
= 42
2
+ 48.8
2
+ ...... + 43.2
2
= 183272.32 ∑ Xi
2
= 42+ 48.8 + ...... + 43.2
2
= 4191.60
2
= 17569510.56
2 2
2
i i
i
x x
x N
c N
2
4191.60 6
17569510.5 183272.32
100 1
. 2
= 17.25 N = 100
N’ N → data yang diperoleh sudah cukup
5. Tebal Paha
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