L5 - 3
Uji Cukup ∑ Xi
2
= 85
2
+ 88
2
+ ...... + 83
2
= 737322.15 ∑ Xi
2
= 85+ 88 + ...... + 83
2
= 8578.70
2
= 73594093.69
2 2
2
i i
i
x x
x N
c N
2
8578.70 9
73594093.6 15
. 737322
100 1
. 2
= 0.75 N = 100
N’ N → data yang diperoleh sudah cukup
2. Tinggi Bahu Duduk
Uji Normal
k = 3.3 log n + 1
= 3.3 log 100 + 1 = 7.6 ≈ 8 kelas c = Xmax – Xmin k
= 66.3 – 53 7.6 = 1.75 ≈ 1.8
Batas Kelas oi
Z1 Z2
PZ1 P Z2
PZ2 - PZ1
ei ei
gab oi
gab
2
52.95 -
∞ -1.925
0.027 0.027
2.710 8.971
9 0.000
54.75 – 54.75
9 -1.925
-1.343 0.027
0.090 0.063
6.260 54.75
– 56.55 19
-1.343 -0.760
0.090 0.224
0.134 13.393
13.393 19
2.347 56.55
– 58.35 19
-0.760 -0.177
0.224 0.430
0.206 20.597
20.597 19
0.124 58.35
– 60.15 17
-0.177 0.405
0.430 0.657
0.228 22.774
22.774 17
1.464 60.15
– 61.95 16
0.405 0.988
0.657 0.838
0.181 18.104
18.104 16
0.244 61.95
– 63.75 14
0.988 1.570
0.838 0.942
0.103 10.346
10.346 14
1.290 63.75
– 65.55 5
1.570 2.153
0.942 0.984
0.042 4.250
5.816 6
0.006 65.55
– 67.35 1
2.153 2.736
0.984 0.997
0.013 1.255
67.35 2.736
∞ 0.997
1 0.003
0.311 100
1 100
100 100
5.476
L5 - 4
Tabel uji normal v = k
– r – 1 v = 7
– 2 – 1 = 4 α = 0.05
2
v, α
= 9.488
2
hasil perhitungan = 5.476
2
hasil perhitungan
2
v, α
sehingga mengikuti distribusi normal Uji Seragam
Subgroup 1
2 3
4 5
6 7
8 9
10 Rata-rata
1 58.0
60.0 59.0
58.2 60.8
66.3 61.5
57.3 57.0
56.0 59.41
2 59.8
55.0 63.5
60.1 62.0
61.2 59.0
60.0 53.5
56.0 59.01
3 57.2
59.0 65.0
56.1 60.8
55.5 63.0
58.0 64.0
54.5 59.31
4 62.0
60.5 58.0
61.0 61.5
57.3 56.0
56.0 55.4
61.8 58.95
5 53.0
57.0 55.5
63.5 54.2
56.0 58.4
61.2 60.0
60.2 57.53
6 65.0
63.0 54.0
57.0 60.9
54.0 57.1
60.2 62.0
58.0 59.12
7 57.7
56.0 62.0
62.0 56.5
55.1 58.9
56.3 59.6
62.0 58.61
8 56.5
61.5 56.0
58.1 57.5
59.0 59.1
63.0 56.4
58.0 58.51
9 59.0
58.8 54.5
64.5 57.3
54.4 58.3
65.0 63.0
63.0 59.78
10 61.2
59.7 55.1
59.2 55.0
53.3 61.1
62.0 57.0
60.2 58.38
58.86 Rata-rata
x
= 58.86 = 3.1
98 .
10 3.1
n
x
x
c x
BKB
= 58.86 – 20.98 = 56.92
x
c x
BKA
= 58.86 + 20.98 = 60.83
L5 - 5
Grafik Uji Seragam Tinggi Bahu Duduk
57.53 59.12
58.51 58.61
59.31 58.38
59.78 58.95
59.01 59.41
BKB = 56.92 BKA = 60.83
54 55
56 57
58 59
60 61
62
1 2
3 4
5 6
7 8
9 10
Subgroup ke - R
a ta
- r
a ta
Berdasarkan grafik di atas, dapat disimpulkan bahwa data seragam karena berada dalam batas BKA dan BKB.
Uji Cukup ∑ Xi
2
= 58
2
+ 59.8
2
+ ...... + 60.2
2
= 347842.46 ∑ Xi
2
= 58+ 59.8 + ...... + 60.2
2
= 5828.60
2
= 33972577.96
2 2
2
i i
i
x x
x N
c N
2
5828.6 6
33972577.9 46
. 347842
100 1
. 2
= 9.56 N = 100
N’ N → data yang diperoleh sudah cukup
3. Tinggi Siku Duduk
