L5 - 26
Grafik Uji Seragam Tinggi Badan Tegak
166.15 166.89
166.15 165.15
167.88 166.29
169.76
162.97 163.70
168.80
BKB = 162.97 BKA = 169.97
162 164
166 168
170
1 2
3 4
5 6
7 8
9 10
Subgroup ke - R
a ta
- r
a ta
Berdasarkan grafik di atas, dapat disimpulkan bahwa data seragam karena berada dalam batas BKA dan BKB.
Uji Cukup ∑ Xi
2
= 160
2
+ 162.5
2
+ ...... + 171.9
2
= 2773664 ∑ Xi
2
= 160+ 162.5 + ..... + 171.9
2
= 16304.60
2
= 265839981.16
2 2
2
i i
i
x x
x N
c N
2
16304.6 16
. 265839981
2773664 100
1 .
2
= 17.34
N = 100 N’ N → data yang diperoleh sudah cukup
12. Pangkal ke Tangan
Uji Normal
k = 3.3 log n + 1
= 3.3 log 100 + 1 = 7.6 ≈ 8 kelas c = Xmax – Xmin k
= 15 – 5 7.6 = 1.316 ≈ 1.3
L5 - 27
Batas Kelas oi
Z1 Z2
PZ1 P Z2
PZ2 - PZ1
ei ei
gab oi
gab
2
4.95 -
∞ -2.472
0.007 0.007
0.671 5.342
2 2.091
4.95 - 6.25 2
-2.472 -1.613
0.007 0.053
0.047 4.671
6.25 - 7.55 20
-1.613 -0.753
0.053 0.226
0.172 17.239
17.239 20
0.442 7.55 - 8.85
33 -0.753
0.107 0.226
0.543 0.317
31.686 31.686
33 0.055
8.85 - 10.15 32
0.107 0.967
0.543 0.833
0.291 29.057
29.057 32
0.298 10.15 - 11.45
10 0.967
1.827 0.833
0.966 0.133
13.291 16.677
13 0.811
11.45 - 12.75 1
1.827 2.687
0.966 0.996
0.030 3.025
12.75 - 14.05 1
2.687 3.547
0.996 1.000
0.003 0.341
14.05 - 15.35 1
3.547 4.406
1.000 1.000
0.000 0.019
15.35 4.406
∞ 1.000
1 0.000
0.001 100
1 100
100 100
3.696
Tabel uji normal v = k
– r – 1 v = 5
– 2 – 1 = 2 α = 0.05
2
v, α
= 5.991
2
hasil perhitungan = 3.696
2
hasil perhitungan
2
v, α
sehingga mengikuti distribusi normal Uji Seragam
Subgroup 1
2 3
4 5
6 7
8 9
10 rata - rata
1 9.0
8.0 9.0
7.3 9.0
10.5 6.0
10.5 6.5
7.5 8.33
2 8.0
9.0 7.0
8.5 9.1
8.0 8.0
9.5 10.0
9.5 8.66
3 9.6
7.5 8.5
8.0 8.0
10.5 7.4
10.5 9.0
7.3 8.63
4 9.0
7.2 8.0
10.0 9.0
10.0 8.5
8.0 7.0
10.0 8.67
5 8.0
8.0 9.0
9.0 10.0
8.0 8.5
8.0 8.5
11.0 8.80
6 8.8
9.0 7.0
8.0 7.0
8.0 8.0
14.0 7.0
9.0 8.58
7 7.4
10.5 7.0
8.0 8.0
7.0 8.0
8.0 8.0
6.5 7.84
8 8.5
12.0 7.0
9.6 8.5
8.0 7.0
9.0 15.0
8.0 9.26
9 9.6
8.0 11.0
11.0 9.0
9.5 9.0
5.0 10.0
6.5 8.86
10 9.0
10.0 9.0
10.0 10.5
10.5 10.0
8.0 7.5
8.0 9.25
8.69 Rata-rata
x
= 8.69 = 1.51
L5 - 28
48 .
10 1.51
n
x
x
c x
BKB
= 8.69 – 20.48 = 7.73
x
c x
BKA
= 8.69 + 20.48 = 9.64
Grafik Uji Seragam Pangkal ke Tangan
8.33 8.66
8.63 8.67
8.80 8.58
7.84 9.26
8.86 9.25
BKB = 7.73 BKA = 9.64
7 7.5
8 8.5
9 9.5
10
1 2
3 4
5 6
7 8
9 10
Subgroup ke - R
a ta
- r
a ta
Berdasarkan grafik di atas, dapat disimpulkan bahwa data seragam karena berada dalam batas BKA dan BKB.
Uji Cukup ∑ Xi
2
= 9
2
+ 8
2
+ ...... + 8
2
= 7774.42 ∑ Xi
2
= 9+ 8 + ..... + 9
2
= 868.80
2
= 754813.44
2 2
2
i i
i
x x
x N
c N
2
868.80 44
. 754813
42 .
7774 100
1 .
2
= 11.99
N = 100 N’ N → data yang diperoleh sudah cukup
L5 - 29
13. Lebar Jari
