L5 - 22
10. Panjang Lengan Bawah
Uji Normal
k = 3.3 log n + 1
= 3.3 log 100 + 1 = 7.6 ≈ 8 kelas c = Xmax – Xmin k
= 34 – 21 7.6 = 1.711≈ 1.7
Batas Kelas oi
Z1 Z2
PZ1 P Z2
PZ2 - PZ1
ei ei
gab oi
gab
2
20.95 -
∞ -2.254
0.012 0.012
1.209 7.380
8 0.052
20.95 - 22.65 8
-2.254 -1.448
0.012 0.074
0.062 6.171
22.65 - 24.35 19
-1.448 -0.642
0.074 0.260
0.187 18.664
18.664 19
0.006 24.35 - 26.05
31 -0.642
0.164 0.260
0.565 0.305
30.472 30.472
31 0.009
26.05 - 27.75 28
0.164 0.970
0.565 0.834
0.269 26.885
26.885 28
0.046 27.75 - 29.45
11 0.970
1.776 0.834
0.962 0.128
12.814 16.600
14 0.407
29.45 - 31.15 2
1.776 2.582
0.962 0.995
0.033 3.294
31.15 - 32.85 2.582
3.388 0.995
1.000 0.005
0.456 32.85 - 34.55
1 3.388
4.194 1.000
1.000 0.000
0.034 34.55
4.194 ∞
1.000 1
0.000 0.001
100 1
100 100
100 0.521
Tabel uji normal v = k
– r – 1 v = 5
– 2 – 1 = 2 α = 0.05
2
v, α
= 5.991
2
hasil perhitungan = 0.521
2
hasil perhitungan
2
v, α
sehingga mengikuti distribusi normal
L5 - 23
Uji Seragam
Subgroup 1
2 3
4 5
6 7
8 9
10 rata - rata
1 24.0
28.0 25.0
24.0 23.5
23.7 25.0
22.5 28.0
25.0 24.87
2 28.0
23.2 28.0
29.5 25.0
26.5 23.0
24.4 27.0
22.0 25.66
3 26.0
25.5 24.0
27.0 26.0
25.2 27.0
26.0 26.5
26.5 25.97
4 26.0
28.0 28.0
23.0 25.0
22.6 23.7
24.0 27.5
25.0 25.28
5 26.0
27.5 29.0
26.0 27.0
34.0 29.5
23.0 23.5
21.3 26.68
6 22.0
27.0 25.0
26.5 25.0
26.0 27.5
25.0 24.5
21.5 25.00
7 24.0
27.0 26.0
23.0 27.5
27.0 25.0
24.0 26.5
28.5 25.85
8 25.0
27.3 21.0
24.5 27.0
27.5 24.2
26.0 29.0
27.5 25.90
9 27.0
27.5 22.0
25.0 25.0
26.0 25.4
27.0 27.0
24.5 25.64
10 26.5
27.5 28.0
24.0 24.0
24.0 26.5
28.5 26.9
26.0 26.19
25.70 Rata-rata
x
= 25.704 = 2.109
67 .
10 2.109
n
x
x
c x
BKB
= 25.704 – 20.67 = 24.37
x
c x
BKA
= 25.704 + 20.67 = 27.04
Grafik Uji Seragam Panjang Lengan Bawah
25.97 25.00
25.85 25.90 26.68
24.87 25.66
25.28 25.64
26.19 BKB = 24.37
BKA = 27.04
23.00 24.00
25.00 26.00
27.00 28.00
1 2
3 4
5 6
7 8
9 10
Subgroup ke - R
a ta
- r
a ta
Berdasarkan grafik di atas, dapat disimpulkan bahwa data seragam karena berada dalam batas BKA dan BKB.
L5 - 24
Uji Cukup ∑ Xi
2
= 24
2
+ 28
2
+ ...... + 26
2
= 66509.92 ∑ Xi
2
= 24+ 28 + ..... + 26
2
= 2570.4
2
= 6606956.16
2 2
2
i i
i
x x
x N
c N
2
2570.4 6606956.16
92 .
6509 6
100 1
. 2
= 2.67 N = 100
N’ N → data yang diperoleh sudah cukup
11. Tinggi Badan Tegak