Hubungan Cepat Rambat Cahaya dan Indeks Bias Medium Sudut Kritis dan Pemantulan Sempurna

119 Cahaya dan Optika medium air medium–1 medium kaca medium–2 Gambar 6.20 Sinar yang melalui dua medium berbeda, yaitu air dan kaca. ,531A1D=D=:9;13181H125A75A1;41A9=549D=;5=549D= 945;B291B=549D= A51C96C5A8141=549D= ,531A1=1C5=1C9B411C 49CD9B;1B52171925A9;DC + + + B9 B9 + + + . 5AB1=11C5AB52DC411C:D7149CD9BB52171925A9;DC L 9;5C18D92 45716A5;D5B941 1:1775?=217 57145=9;91919945;B291B411C495A?58:D7141A91:17 75?=217 2 12 1 n L B9 B9 + + + . L 4501 ;4134501 ; =5=99;9=1;169B9BH19CD ;5351C13181H1411=BD1CD=549D=25A21497C5A219;4571919 945;B291BH1 1;BD4H1:9;1945;B291BB5=1;925B1A;5351C1 3181H1B5=1;9;539 ,5217193?C?8;5351C13181H1411==549D= ;1315298;5394921497;14571;5351C13181H1;5C9;1=5A1=21C 411=19A 1B1H1945;B291B=DC1;;131529825B1A41A9141945;B =DC1; 19A ,519 9CD 41 :D71 411C =5H9=D;1 218F1 ;5C9;1 75?=217=5A1=21C41A9BD1CD=549D=;5=549D=19H17945;B 291BH125A25411:1775?=217 4125B1A;5351C1275?=217 C5AB52DC25AD2181=D6A5;D5B975?=217C5AB52DCC941;25AD218 5C5A171 + 945;B291B=DC1;=549D= + 945;B291B=DC1;=549D= + 945;B291B=549D= A51C96C5A8141=549D= BD4DC41C1749=549D= . BD4DC291B49=549D=

3. Hubungan Cepat Rambat Cahaya dan Indeks Bias Medium

5A81C9;1 04 9B1H1BD1CD75?=21729417 495F1C;1=51D9=549D=;5=549D= H175298A11C ,5C518F1;CD 075?=2172941725A14114129417,+ 2 0 2 0 2 0 2 0 2 2 Gambar 6.21 Pembiasan cahaya melalui dua medium medium 1 medium 2 R S P Q 1 2 2 1 Di unduh dari : Bukupaket.com 120 Mudah dan Aktif Belajar Fisika untuk Kelas X 11=B52D185;B5A9=5DCD;=55CD;1;5351C13181H149411=19AB5?A17 B9BF1=55F1C;1B525A;1B3181H1;5411=19A4571BD4DC41C17J 5=D491 B9BF1=531C1CBD4DC291BH17C5A:14949411=19AC5AH1C125B1AH1 J 9;1;5351C1 3181H149D41A1491771M = BC5CD;1;5351C13181H149411=19A 9 9;5C18D9 J M = B. J 4919A B9 B9 2 r M B9 J B9 J = B M ms = B M = B 149;5351C13181H1411=19A14118 M = B Contoh 6.6 Gambar 6.22 Sinar datang dibiaskan: a mendekati garis normal jika n 1 n 2 ; b menjauhi garis normal jika n 1 n 2 . i n 1 n 2 r n 1 n 2 i r n 1 n 2 n 1 n 2 ,55;?A9;125A1414941B1A;?1=H17411=H1= 19A + B55AC9C1=1; 14171=21A49B1=97 141;5411=125A11;185C1;9;141B1A;?1=C5AB52DCC5A981C?58571=1C 41A95A=D;1119A:9;1 1 9;149981C571=1CB531A1C571;DADB 2 BD4DC1C1A1=1C14171A9B?A=1B525B1AJ 9 1 5A81C9;171=21A 9;1571=1C=5981C9;1B531A1C571;DADB1;1=5=5D895AB1=11 C1.B9.41C1B9 ,91A41C1741A99;1B589771 C1 B9 C1 B9 . . 1C1D 1 . + + =1;1 ;5411=19;1495A?58H19CD 1C1D = 149;5411=1B5=D9;1H1749981C571=1CB531A1C571;DADB14118= 2 5411=19;1DCD;BD4DC1C1A1=1C1571=1C4171A9B?A=1.J 14118 B9 B9 B9 B9 1 . + . + B9 B9J J B589771 C1 C1 J C1 C1 J . = 149;5411=1B5=D9;1DCD;BD4DC.J=5:149 = Contoh 6.7 dasar kolam 4 m n ud = 1 n air = 4 3 r d = 4 m i r d i ,521719;?B5;D5B941A9D;D=,59DB99B91A41C1741A9 =549D=;DA17A11C;5=549D=5298A11C+ + +.++ +0.+,.++.0+.1.-0 11.+.-0+ + B91A1;149291B;1=5:1D8971A9B?A=1 4+6,.104 mata pengamat a b Di unduh dari : Bukupaket.com 121 Cahaya dan Optika

4. Sudut Kritis dan Pemantulan Sempurna

5711 25A91 C1=1; 25A;91D1 ;5C9;1 3181H1 :1CD8 141 5A=D;11H15711141B11CC5A9;=1C181A9:11A1H125A1B1 C1=1;B55AC9C5A751719A141;54D175:119B9;1C5AB52DC3181H1 =5711=9 5=1CD1 B531A1 B5=DA1 1719=11 5=1CD1 B5=DA1411CC5A:1495A81C9;104 1=21AC5AB52DC=5D:D;;13181H125A75A1;41A9=549D=5298 A11C;131;5=549D=;DA17A11CD41A11C1D41A9=549D=25A945;B 291B529825B1A;5=549D=25A945;B291B5298;539B589771B91A291BH1 =5:1D8971A9B?A=1 5C9;1BD4DC41C17?BD4DC291BH1:D71?B55AC949CD:D;;1 ?58B91A 5=D491141B11CBD4DC41C17495A25B1AB91A B91A 41B91ABD4DC291BD25AC1=21825B1A1C1DB5=1;9=5:1D89 71A9B?A=1 141B11C25B1ABD4DC41C17C5AC5CDH1;9B55AC9B91A 3181H149291B;1JC5A814171A9B?A=1B589771B91A291BH1B5:1:1A 45715A=D;112941721C1B=549D=;131D41A1 141;51411 B55AC999BD4DC41C1749B52DCBD4DC;A9C9B 571;1C119BD4DC;A9C9B14118BD4DC41C17;5C9;1B91A41C17 49291B;1B525B1AJ 9;1BD4DC41C17495A25B1A179=552989BD4DC;A9C9B 3181H1C941;1;149291B;1=519;1491CD;1B531A1B5=DA1 AC9H13181H1C941;1;1;5D1A41A9=549D=;131B55AC949CD:D;;1 ?58B91A 5A9BC9F19918H1749B52DC5=1CD1B5=DA1 5A41B1A;1 81 C5AB52DC 411C 49B9=D;1 218F1 5=1CD1 B5=DA181H1C5A:149:9;1=5=5D894D1BH1A1C25A9;DC 1 181H141C1741A9=549D=5298A11C;5=549D=;DA17A11C 2 ,D4DC41C17529825B1A41A9141BD4DC;A9C9B Gambar 6.23 Deskripsi geometri tentang sudut kritis dan pemantulan sempurna n 2 n 1 n 1 n 2 1 2 3 4 5 6 i udara kaca i i i r r r r i r Aktivitas Fisika 6.3 Sepotong plastik transparan terapung dipermukaan air. Agar sinar datang seperti pada gambar di atas dipantulkan sempurna oleh permukaan batas plastik air. Jika indek bias plastik n k dan indek bias air n a , berapa besar sudut ? Tantangan untuk Anda udara air plastik Pemantulan Sempurna Tujuan Percobaan Mengamati pemantulan sempurna. Alat-Alat Percobaan Gelas minum, lilin, dan air. Langkah-Langkah Percobaan 1. Isilah gelas minum dengan air sampai hampir penuh. 2. Letakkan gelas tersebut di pinggir meja. 3. Nyalakan lilin pendek dan letakkan dekat dengan gelas. 4. Perhatikan gambar berikut. Amati dari arah yang berseberangan dengan lilin dari arah agak di bawah permukaan. 5. Apa yang dapat Anda amati? 6. Apa kesimpulan Anda dari kegiatan ini? A9B95=1CD1B5=DA149=1611C;1411=C5;??79;?=D9 ;1B9H1;9141B5A1C?C9;.,-0 B55AC914104 ,5A1C ?C9;14118BD1CDB5A1C81DBC5A2D1C41A91BC9;1C1D;131H17497D1;1 DCD;=5H1DA;13181H11C1D75?=21755;CA?=175C9; ,5A1C?C9; C5A49A91C1B217919C94121791D1AB5217195=2D7;DBH1 17919C9 C5A2D1C41A9;131H17=5=99;9945;B291BC97794125A;D19C1B219; mata pengamat Di unduh dari : Bukupaket.com 122 Mudah dan Aktif Belajar Fisika untuk Kelas X Gambar 6.24 a Pemantulan sempurna pada serat optik. b serat optik. a b Contoh 6.8 9CD7BD4DC;A9C9B25A91H17=5=99;9945;B291B=DC1; 141B11C495C1;;1 49D41A1 9 9;5C18D9 + + B9 + + ; J 149BD4DC;A9C9B25A9114118 J B9 B9 + 5 + 1C1D B9 + + L 5C5A171 ; BD4DC;A9C9B 1 1 sin t i r 5 Pembiasan pada Kaca Plan Paralel 13111A1514118B5;597;131H17;54D1B9B91:17H1 492D1CB5:1:1A 131 1 1A15 411C 497D1;1 DCD; =571=1C9 :11H1B91AH17=5711=95=291B141DCD;=55CD;1945;B 291B;131C5AB52DC ,91A 41C17 41A9 D41A1 =55F19 ;131 B5C521 3= ;5=D491 =5D:D=549D=D41A1;5=219 141A?B5BC5AB52DCB55AC9C1=1;141 04 4104 591A=5711=95A75B5A141A91A18 B91AB5=D1 5B1AH15A75B5A1B91AC5AB52DC411C4989CD7B52171925A9;DC 5A81C9;1 B9 6 . L 45;B291BH17C97791;1=571;921C;1BD4DC;A9C9B;539B589771 B91A41C174571BD4DC41C17H17C941;C5A1D25B1A1;1=5711=9 5=1CD1B5=DA1 1791D1AH17=5AD1;15=2D7;DBC5A2D1C41A91BC9;1C1D =1C5A9119H1725A6D7B9=594D79217919C9 58;1A513181H1 1C1D75?=21755;CA?=175C9;H17=1BD;;5411=B5A1C?C9;=5 711=95=1CD1B5=DA1141B11C;5D1A41A9B5A1C?C9;55A79 3181H1C941;21H1;H178917 5A41B1A;1819CD:9;1H1749;9A9= 14118B9H1B9H1;?=D9;1B9411=25CD;75?=2173181H1141 B11C49C5A9=149C5=1CCD:D1B9H1C5AB52DCB1=19B531A1DCD8C11 21H1;;58917155A79 5A41B1A;1141A?B5BC5A:149H15=1 CD1B5=DA1411C49C5CD;1D125B1AH1BD4DC;A9C9BDCD;4D1 =549D=C5AC5CDB52171925A9;DC 141B11CC5A:1495=1CD1B5=DA125A1;D5AB1=1125A9;DC Gambar 6.25 Seberkas cahaya memasuki kaca plan paralel d D B A O t r 2 r 1 i 1 Gambar 6.26 Pergeseran arah sinar pada kaca plan paralel B9 B9 + . + 4571+ + 41.JB589771 Di unduh dari : Bukupaket.com 123 Cahaya dan Optika 1 cos d r L 5A41B1A;1 495A?58 3?B . 5A41B1A;14501 ;414501 ;495A?58 3?B B9 . 6 . B58977125B1A5A75B5A1B91A B9 L 3?B . . L 5C5A171 BD4DC41C17 C521;13111A15 . BD4DC291B 025B1A5A75B5A1B91A ,525A;1BB91A1B5A:1CD81415A=D;11;13111A15411C=5=25CD;BD4DC 41C17B525B1AJ 9;1C521;13111A153=41BD4DC291B JC5CD;125B1A 5A75B5A1H174911=9?58B91A1B5AC5AB52DC 9 9;5C18D9 J. J3= B9 L 3?B . . B9 J L J 3?B J 149;5C9;1=55F1C9;13111A15B91A1B5A=5711=95A75B5A13=41A9 1A18B5=D1 Contoh 6.9

6. Pembiasan pada Prisma