Radiasi Benda Hitam Perpindahan Kalor secara Radiasi

164 Mudah dan Aktif Belajar Fisika untuk Kelas X 0?08G0=638:4;C0:0=;47B0=0730=B0=00=4=G4101:0= ?4=6C0?0=B4?40=6:0?;4738=38=6:020;80=C0?08:40B0AA4200 :=D4:A8B830:1490;0=A478=660C0?08:410;890BC7:430;0B0=07 30=B0=00=30;014=BC:H0B2080300:78=G0:4;41010=C300 30;0C07:02030?0BB49060A4?0=90=60380A8:0;0B070814 ;0=6AC=6

c. Radiasi Benda Hitam

0415 J 30=68 0-5:. J 4=G0B0:0= 107E0 14A0=G0 4=468 G0=6 38?0=20:0= ;47 AC0BC ?4C:00=?4A0BC0=E0:BC?4A0BC0=;C0AA410=38=634=60=?0=6:0B 4?0BAC7C?4C:00=8BC30?0B38BC;8A34=60=?4A000= 4B40=60= 4=468G0=638?0=20:0=0B0C38A40??4A0BC0=E0:BC?4A0BC0= ;C0A A 0B0CE0BB :=AB0=B0CCB450=;BH0==K J E0BB AC7CCB;0: 48A8D8B0A?4C:00=B830:14A0BC0= =BC:14=3078B0A4?C=07060 14=3014=30;08=7060 :458A84=48A8D8B0A=G0;4187:428;308?030A0BCA430=6:0=C=BC:14=30 14E0=0?CB87A4?C=0 0601460=BC=6?030:40300=?4 C:00=14=30G08BC:4:0A00==G0A4B0E0=030814=30=468G0=6 38?0=20:0=;47A41C0714=3030;0A0BC0=9C;438B4=BC:0=34=60= ?4A000= J J 4B40=60= 4=468G0=638?0=20:0=;47?4C:00=14=30 ;C0A?4C:000=14=30 ;00E0:BC48A84=468A4:= 8:03810=38=6:0=B47030?;8=6:C=60=G0=614AC7C ?4A000= =G00:0=4=9038 J 41C0714=3048;8:8?4C:00=78B0A4?C=014AC7C IC0A?4C:00= 2 40=20:0=4=468:4;8=6:C=60=G0=614AC7CI4=BC:0=4=468?4 A0BC0=E0:BCG0=638?0=20:0=14=30B4A41CB 8 14=3078B0 2 K J Contoh 7.8 J 4=40?0=:=A4?0380A830;0:4783C?0=A470870810=G0:38 9C?082=B7=G0?410:00=?0300;0B?40=660=6+?4=648=60= :?830=B410:0C30=A8AB4?4=38=68=0B0C?40=0A0=C07 Seorang petinju profesional setelah selesai bertanding berada di ruangan yang bersuhu 15°C. Berapa laju energi yang dikeluarkan tubuhnya jika suhu tubuhnya saat itu 34°C, emisivitasnya 0,7, dan luas tubuhnya yang berhubungan langsung dengan udara adalah 1,5 m 2 ? Tantangan untuk Anda Di unduh dari : Bukupaket.com 165 Kalor K J E0BB K J . J K J , 03814A04=468?4A0BC0=E0:BCG0=638?0=20:0=;4714=30B4A41CB030;07 , 030AC7C A41C0714=3040=20:0=4=468A414A0 A40?04=468 G0=638?0=20:0=14=30B4A41CB?030AC7C 8 8:4B07C8 A A 0384=468G0=638?0=20:0=14=30?030AC7C 030;07 A Contoh 7.9 Tes Kompetensi Subbab B 3+,--.6,6-5 47?0=0A14AC7CI38BC0=6:0=:430;03C0 1C07B4:G0=6A0BCB4::408:E0=078B0 30=A0BC=G0;068B4:4=68;0B 8:0AC7CC0=6I140?0:424?0B0=78;0=6=G0 :0; 308 A4B80? B4: :4 ;8=6:C=60= 98:0 ;C0A ?4C:00=B4:030;07K J 4=603C: B41C0B 308 0;C8=8C 34=60= ;C0A ?4=0?0=6 30=?0=90=6 2 8:0AC7C08 30;01490=0 IAC7C38C9C=6?4=603C:I 30=:=3C:B8D8B0AB40; ,IB4=BC:0= 0 :424?0B0=0;80=:0;?0300;80=:0;?030 ?4=603C: 1 :0;G0=64=60;84;0;C8?4=603C:A4;00 90 ?8?0=0A14AC7CI38BC0=6:0=:430;0 20=6:8:408:E0=02:4;0B 8:0AC7C C0=6IB4=BC:0=:424?0B0=78;0=6=G0:0;308 20=6:8:4;8=6:C=60=;C0A20=6:8 2 A0A;02:4=G0B0:0=107E09C;07:0; G0=638;4?0A?030AC0BCA8AB40:0=A00 34=60=9C;07:0;G0=638B480 4C080=?030H0B?030B30?0B3800B84 ;0;C8?4C1070=?0=90=6;C0A30=D;C4 030 CC=G0 ?4C080= H0B 208 70=G0 30?0B 3800B8 4;0;C8 ?4C1070= D;C4 A090 Rangkuman 0;030;074=468G0=638?8=307:0=308 AC0BC14=30:414=30G0=6;08= 0; 94=8A 30?0B 383458=8A8:0= A410608 10=G0:=G0:0;G0=638?4;C:0=AC0BCH0B C=BC:4=08::0=AC7C :6H0BB4A41CB A414A0 I 0?0A8B0A :0; 030;07 10=G0:=G0 G0=6 38?4;C:0=C=BC:4=08::0=AC7C14=30 A414A0 I Kata Kunci • konduksi • konveksi • radiasi • rumah kaca • radiasi benda hitam Di unduh dari : Bukupaket.com 166 Mudah dan Aktif Belajar Fisika untuk Kelas X 0;030;074=468G0=638?8=307:0=308 AC0BC14=30:414=30G0=6;08= 30B86014=BC:?4?8=3070=:0;G08BC :=3C:A8:=D4:A830=0380A8 4?8=3070= :0; 4;0;C8 H0B ?40=B00 34=60=B830:38A4B08?4?8=3070=?0B8:4; ?0B8:4;H0BB4A41CBA0200?40=4=38A41CB 70=B00=0B0C:=3C:A8 4?8=3070=:0;A4200:=D4:A80;80= 38A4B08640:0=0AA00B0C640:0=?0B8:4; ?40=B00=G05;C830 0380A8 030;07 ?4?8=3070= :0; 30;0 14=BC:64;10=64;4:B06=4B8: 30?0B 14?8=307 A4200 =3C:A80=B00= =D4:A8;80= 0380A80=200= 30?0B 4=G4101:0= -03 4C1070= ,C9C3 2=B7 ?48AB8E0=G0 4C080= 4=30 A478=660 B49038 4C1070=C7C 4;41C 414:C 4=6C0? 4=641C= 4=GC1;8 94=8A=G0 4C080=+;C4 4C080=0=90=6 4C080=C0A Peta Konsep Setelah Anda mempelajari bab ini, tentunya Anda telah memahami tentang perubahan wujud zat akibat perubahan kalor. Dapatkah Anda menerangkan mengenai cara perpindahan kalor pada suatu zat? Refleksi Bagaimana dari cara perpindahan tersebut yang belum Anda pahami? Diskusikan dengan teman Anda tentang materi yang belum Anda pahami tersebut. Jika masih menemui kesulitan, bertanyalah kepada guru Fisika Anda. Di unduh dari : Bukupaket.com 167 Kalor 0;0A8AB4A0BC0=8=B4=0A8=0;14A00=AC7C 48;8:8A0BC0= 0 =4EB= 3 :4;D8= 1 E0BB 4 :0;8 2 9C;4 0;01B;B4AB430?0B 60:?8?030AC7C I8B0107:0=ACACA410=G0: 6014AC7C I 8:0B830:030:0;20?C0=0C?C=:0;G0=6 B4A40?1B;B4A 08 :?8 ACAC :0;6I C7C20?C0==G0030;07 0 I 3 I 1 I 4 I 2 I C7CA410B0=61090G0=6?0=90=6=G0 38B8=6:0B:0= 308 I4=9038 IA478=660?0=90=6=G014B0107 8;84B44B01070=?0=90=6AC0BC10B0=61090 G0=6?0=90=6=G0 298:038?0=0A:0=308 IA0?08 I030;07 3 1 4 2 41C071;014=660B41C0B308?4C=66C34=60= :458A84=C08;8=40 K J I030 I 908908=G0 8:01;0B4A41CB38?0=0A:0=A0?08 I?4B01070=;C0A?4C:00=1;0030;07A414A0 30;0 0 K J 3 K J 1 K J 4 K J 2 K J 30=14BCCBBCCB030;07:458A84=C08?0=90=6 :458A84=C08;C0A30=:458A84=C08D;C448:CB 8=8G0=64=C=9C::0=7C1C=60=G0=614=0308 :4B860=G0030;07 3 1 4 2 410B0=614A8C;0C;0?0=90=6=G0 38?0=0A:0= 308AC7C 4=9038 8:0:458A84=C08?0=90=6 10B0=6B4A41CB ?4B01070=?0=90=610B0=6 030;07 1 J 2 J 3 J 4 --4-456+891-515,3+,-16,6-5 4;0BB8?8A308;60?0=90=6=G0 230=;410=G0 2?030AC7C I 8:0?4;0BB4A41CB38?0=0A:0= A0?0834=60=AC7C IB4=G0B0;C0A=G0 2 458A84=C08?0=90=6;60B4A41CB030;07 0 K J I 3 K J I 1 K J I 4 K J I 2 K J I 030AC7CI0AA094=8A40A :6 :458A84=C08?0=90=640A K J I0AA0 94=8A40AB4A41CB?030AC7C I030;07 0 :6 3 :6 1 :6 4 :6 2 :6 0A30;0C0=6B4BCBC?A410=G0:B4:0=0==G0 38C1074=9038:0;8A4C;0?030AC7CG0=6A00 +;C460A0:0=14C1074=9038 3 1 4 2 C0BC60A8340;A410=G0: ?030B4:0=0= 0B 30=AC7CI4C380=60AB4A41CB38?0=0A:0= 78=660AC7C=G0 I30=D;C4=G04:0=0= 60AA4:00=6030;07 0 0B 3 0B 1 0B 4 0B 2 0B 0BC0=:0;94=8A30;0030;07 0 :0;I 3 9C;4 1 :0;6I 4 9C;4:6 2 ::0;:6I C;07?0=0AG0=638?4;C:0=C=BC:4=08::0=AC7C I?030 6008030;07 0 :0; 3 :0; 1 :0; 4 :0; 2 :0; 0=0A94=8AAC0BC14=3038B4=BC:0=;47 0 94=8A14=30=G0 1 :4=08:0=AC7C14=30 2 D;C414=30 3 0AA014=30 4 ;C0A?4C:00=14=30 830;064;0A148A8 60814AC7C I38 0AC::0= 64A14AC7CJI:0;94=8A4AB4A41CB :0;6I 8:070=G0B49038?4BC:00=:0;0=B00 0830=4AA4B4;07B49038:4A4B810=60=0:0=38 ?4;47 0 A4;CC74A4=20830=AC7C=G0380B0A I 1 A4;CC74A4=20830=AC7C=G0 I 2 B830:A4;CC74A4=20830=AC7C=G0 I 3 AC7CA4;CC7A8AB43810E07 I 4 A410680=08414:C30=AC7CA4;CC7A8AB4 I Tes Kompetensi Bab 7 Di unduh dari : Bukupaket.com 168 Mudah dan Aktif Belajar Fisika untuk Kelas X 8-13593,65515 C01C071;0;60G0=6A494=8A0A8=60A8=6 14AC7CI380AC::0=:430;008G0=6AC7C=G0 I43C0=G04=20?08:4A4B810=60=B40;?030 AC7C I 8:00AA0A4B80?1;0 :630=:6:0; 94=8A;60030;07 K :630=:0;94=8A08 030;07 K :6A4;8A87:0;G0=638B480 :43C01;0030;07 0 K 3 K 1 K 4 K 2 K 49038=G0?4?8=3070=:0;?030AC0BCH0B:04=0 64B00=0B0B=G038A41CB 0 0380A8 3 :=3C:A8 1 :=D4:A8 4 B0A8 2 B0=A;0A8 4?4=6B41060B410;=G0 230=;C0A?4=0 ?0=6=G0 4C:00=G0=6A0BC48;8:8AC7C A430=6:0=G0=6;08=14AC7C 8:0 :=3C:B8D8B0AB40;B41060 A14A0 =G0:0;G0=64010BB80?A4:=030;07 0 K 3 K 1 K 4 K 2 K 8:0AC7C14=30G0=614?8904=9038:0;8A4C;0 4=468G0=638?0=20:0=B80?34B8:B80?A0BC0=;C0A 4=9038 0 :0;8A4C;0 3 :0;8A4C;0 1 :0;8A4C;0 4 :0;8A4C;0 2 :0;8A4C;0 ;0G0=6?4C:00==G078B0A4?C=048;8:8 AC7C :=AB0= 4A0=G0 4=468 G0=6 38?0=20:0=B80?34B8:;47?4C:00=1;0B4A41CB 98:0:=AB0=B0B450=;BH0==K J , 030;07 0 K , 1 K , 2 K , 3 K , 4 K , C014=3078B0G0=6A494=8A0A8=60A8=614AC7C I 30= I 8:0 :43C0 14=30 B4A41CB 40=20:0=4=46830;014=BC:0380A8?410=38=6 0=9C;074=468?434B8:G0=638?0=20:0=030;07 3 1 4 2 030AC7CIA41C07:C1CA764=?0=90=6CAC: CAC:=G0 2 8:0:458A84=C08?0=90=6:C1CA8BC I140?0:07D;C4:C1CA?030AC7C I C04;10900A8=60A8=6?0=90=6=G0 ?030AC7C I0:0=38A01C=6C=BC:414=BC:AC0BC;8=B0A0= :44B0 8:0AC7C0:A8C=G0 I140?0:07;410 24;078=8CG0=670CA38A4380:0=380=B00 A01C=60=4; 030AC7C IA41C071B;148A8?4=C72080=G0=6 D;C4=G0 22 8:0:458A84=C08D;C41B; 30=2080=14BCCBBCCB I30= I 140?0:072080=G0=6BC?0798:038?0=0A:0=A0?08 I 8:4B07C8?0=0A94=8A4A :0;6I?0=0A94=8A 08 :0;6I30=:0;;41C4A :0;68BC=6;07 AC7C0:7820?C0= 64AG0=6AC7C=G0JI14030 30;0:0;84B4G0=6:0?0A8B0A?0=0A=G0 :0;I 38BC0=68 608G0=614AC7C I C0?C;C760AC0BCH0B38148:0; :0;A478=660 AC7C14=30B4A41CB14C107308 I4=9038 I 40?0:07:0;G0=638;4?0A:0=060AC7C14=30 BCC=308 I4=9038 I C7C ?030 :43C0 ?4C:00= :4?8=6 14A8 G0=6 48;8:8;C0A 2 30=B410;2030;07 I30= I 8:0:=3C:B8D8B0A14A8 :0;A2I B4=BC:0=?0=0AG0=63870=B0:0=B80?4=8B 41C07;C10=6:428;?03038=38=6BC=6:C4=G4C?08 14=3078B0 8:0;C0A;C10=6 2 30=AC7C=G0 A0034=60=AC7CBC=6:CG08BC I140?0:0; G0=6380380A8:0=;C10=6A4B80?A4:= ;0G0=6038CA=G0248;8:848A8D8B0A ;0B4A41CB4=G40?4=468:0;308;8=6:C=60= =G034=60=;09C Js 40?0AC7C1;08BC A4:00=6 Di unduh dari : Bukupaket.com

A. Arus Listrik dan Muatan

B. Hukum Ohm dan Hambatan

C. Rangkaian Seri dan Paralel

D. Hukum II Kirchhoff

E. Sumber Arus Searah dari

Proses Kimiawi

F. Tegangan Listrik Searah dan Bolak-

Balik Listrik Dinamis 0;0708B830:4=90387010B0=10680AF00:0B:B0C=BC: 4;0:C:0=0:B8D8B0A=F00;8=838A4101:0=?4=40=60=;0?C;0?C 3870?8A4C0AC3CB:B0AC307B4?0A0=60?C;0?C8=84C?0:0= 2=B7?40;0B0=30;0:4783C?0=A4708708F0=640=500B:0=4=468 ;8AB8: A4B4;07 38C107 4=9038 4=468 2070F0 0;C 106080=0 4=468 ;8AB8:8=830?0B4=F0;0:0=;0?C=300:0=4?4;0908=F0?030 1018=8 303C094=8A0CA;8AB8:F08BC0CA;8AB8:1;0:10;8:20,2, 300,230=0CA;8AB8:A400702300,20300CA ;8AB8:1;0:10;8:C0B0=;8AB8:4=60;830;03C00071;0:10;8: 30?C=?0300CA;8AB8:A4007C0B0=;8AB8:70=F04=60;830;0 A0BC007=B7?40;0B0=;8AB8:F0=64=66C=0:0=0CAA4007F08BC :0;:C;0B0+-2 -,20- 90 30= ;0?C A4=B4 030 101 8=8 0:0= 38?4;0908 0CA ;8AB8: A4007 430=6:0= 0CA ;8AB8: 1;0:10;8: 0:0= 38?4;0908;418710=F0:38:4;0A. 169 • memformulasikan besaran-besaran listrik rangkaian tertutup sederhana satu loop; • mengidentifikasi penerapan listrik AC dan DC dalam kehidupan sehari-hari; • menggunakan alat ukur listrik. Setelah mempelajari bab ini, Anda harus mampu: menerapkan konsep kelistrikan dalam berbagai penyelesaian masalah dan berbagai produk teknologi. Hasil yang harus Anda capai: Nyala lampu pada malam hari, selain berfungsi sebagai penerangan juga menjadi bagian dari keindahan kota. Bab 8 Sumber: Young Scientist,1994 Di unduh dari : Bukupaket.com