Design Vapour Space i. Volume vapour space

Laju massa air, F = 152,107 kgjam Densitas uap jenuh air, ρ = 1000 kgm 3 40 o C, 1 atm Space Time uap air dalam vapour space , t = 0,25 jam Volume uap, Vf Faktor kelonggaran = 20 Volume tangki, Vt = 1,2 x Vf = 1,2 x 0,038 = m 3 ii. Dimensi vapour space Perbandingan tinggi tangki dengan diameter tangki H : D = 1 : 1 Volume Silinder = π4 x D 2 H = π4 x D 3 Volume tutup Vh ellipsiodal = π4 x D 2 Hh = π4 x D 2 16 D = π24 x D 3 Vt = Vs + Vh Vt = π4 x D 3 + π24 x D3 Vt = 7π24 x D 3 Brownell Young, 1959 Diameter tangki = = m = in Tinggi silinder H = D = m Tinggi tutup ellipsiodal Hc = 16 x D = 16 x 0,368 m = m Diameter tutup = D = m 0,046 Tutup tangki berbentuk ellipsiodal dengan rasio axis major terhadap minor 2 : 1, sehingga : tinggi head Hh = 16 x D Brownel Young, 1959 0,368 0,368 0,061 0,368 14,48277 3 7 π x0,046 24  3 7 π Vt 24  3 m 038 , 1000 0,25 x 107 , 152 t . F     Diameter liquidcrystal channel, Dn = 0,15 D = 0,15 x 0,368 = m Tinggi conical section, Hn = 12 x D -Dn tan θ = m

b. Design LiquidCrystal Space i. Volume liquidcrystal space

Sudut elevasi, θ = 30 o Laju massa liquidcrystal , F = kgjam Densitas liquidcrystal , ρ = kgm 3 Space time dalam liquidcrystal space , t = 1 jam Volume liquidcrystal , Vf = = Faktor Kelonggaran = 20 Volume tangki, Vt = 1,2 x 0,347 = m 3 ii. Dimensi vapour space Perbandingan tinggi tangki dengan diameter tangki H : D = 1 : 1 Volume Silinder = π4 x D 2 H = π4 x D 3 Volume tutup Vh ellipsiodal = π4 x D 2 Hh = π4 x D 2 16 D = π24 x D 3 696,176 2.005,586 0,417 Tutup tangki berbentuk ellipsiodal dengan rasio axis major terhadap minor 2 : 1, sehingga : tinggi head Hh = 16 x D Brownel Young, 1959 0,055 0,090 3 7 π x0,04624  3 m 347 , 2.005,586 1 x 696,176 t . F   Vt = Vs + Vh Vt = π4 x D 3 + π24 x D3 Vt = 7π24 x D 3 Brownell Young, 1959 Diameter tangki = = m = in Tinggi silinder H = D = m Tinggi tutup ellipsiodal Hc = 16 x D = 16 x 1,650 m = m Diameter tutup = D = m Diameter sambungan, Dl = 0,15 D = 0,15 x 1,650 = m Tinggi conical section, Hn = 12 x D -Dn tan90- θ = m iii. Panjang LiquidCrystal Channel Panjang LiquidCrystal Channel, L = 0,7 x Hn = m iv. Tekanan Desain Tinggi level cairan, Hf = VfVt x H + Hc = 0,347 0,417 x 1,650 + 0,275 = m P hidrostatik = x g x Hf = 2.005,586 x 9,8 x 1,604 = Pa = kPa P O = Tekanan Operasi = 1 atm = 101,325 kPa Faktor Kelonggaran = 20 P desain = 1 + 1 x P hidrostatik + P O 1,650 1,650 0,275 64,94274 1,650 0,138 1,309 0,916 1,604 31.520,895 31,521 3 7 π Vt 24  3 7 0,417 x 24  