C. Normality and Homogeneity Test 1. Normality Test
a. Normality test of the students who are taught using Community Language Learning A
1
Based on the calculation result of scores of the students who are taught using Community Language Learning, the highest value of
Lo L obtained is 0.0607. From the table of critical value of Liliefors test with the students’ number N = 40 at the significance
level α
=0.05, the score of Lt is 0.140. Because Lo is lower than Lt or Lo 0.0607 Lt 0.140, it can be concluded that the data are in
normal distribution. b. Normality test of scores of the students who are taught using
Situational Language Teaching A
2
Based on the calculation result of scores of the students who are taught using Situational language teaching, the highest value of Lo
L obtained is 0.097. From the table of critical value of Liliefors test with the students’ number N = 40 at the significance level
α =0.05, the score of Lt is 0.140. Because Lo is lower than Lt or Lo
0.097 Lt 0.140, it can be concluded that the data are in normal distribution.
c. Normality test of scores of the students having high self confidence B
1
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Based on the calculation result of scores of the students who had high self confidence, the highest value of Lo L obtained is 0.097.
From the table of critical value of Liliefors test with the students’ number N = 40 at the significance level
α = 0.05 , the score of Lt
is 0.40. Because Lo is lower than Lt or Lo 0.097 Lt 0.140, it can be concluded that the data are in normal distribution.
d. Normality test of scores of the students having low self confidence B
2
Based on the calculation result of scores of the students who had low self confidence, the highest value of Lo L obtained is 0.067.
From the table of critical value of Liliefors test with the students’ number N = 40 at the significance level
α = 0.05, the score of Lt
is 0.140. Because Lo is lower than Lt or Lo 0.067 Lt 0.140, it can be concluded that the data are in normal distribution.
e. Normality test of score of the students having high self confidence who are taught using Community Language LearningA
1
B
1
Based on the calculation result of scores of the students who are taught using Community Language Learning, the highest value of
Lo L obtained is 0.118. From the table of critical value of Liliefors test with the students’ number N = 20 at the significance
level α
= 0.05, the score of Lt is 0.190. Because Lo is lower than Lt or Lo 0.118 Lt 0.190 , it can be concluded that the data are
in normal distribution. perpustakaan.uns.ac.id
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f. Normality test of scores of the students having low self confidence
who are taught using Community Language Learning A
1
B
2
Based on the calculation result of scores of the students who are taught using Community Language Learning, the highest value of
Lo L obtained is 0.094. From the table of critical value of Liliefors test with the students’ number N = 20 at the significance
level α
=0.05, the score of Lt is 0.190. Because Lo is lower than Lt or Lo 0.094 Lt 0.190, it can be concluded that the data are in
normal distribution. g. Normality test of scores of the students having high self confidence
who are taught using Situational Language Teaching A
2
B
1
Based on the calculation result of scores of the students who are taught using Situational Language Teaching, the highest value of
Lo L obtained is 0.121. From the table of critical value of Liliefors test with the students’ number N = 20 at the significance
level α
=0.05, the score of Lt is 0.190. Because Lo is lower than Lt or Lo 0.121 Lt 0.190, it can be concluded that the data are in
normal distribution. h. Normality test of scores of the students having low self confidence
who are taught using Situational Language Teaching A
2
B
2
Based on the calculation result of scores of the students who are taught using Situational Language Teaching, the highest value of
Lo L obtained is 0.079. From the table of critical value of perpustakaan.uns.ac.id
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Liliefors test with the students’ number N = 20 at the significance level
α = 0.05, the score of Lt is 0.190. Because Lo is lower than
Lt or Lo 0.079 Lt 0.190, it can be concluded that the data are in normal distribution.
Table 4.9. Summary of Normality test
No Data
No. of Sample
Lo Lt
α Status
1 A
1
40 0.0607
0.140 0.05
Normal 2
A
2
40 0.097
0.140 0.05
Normal 3
B
1
40 0.097
0.140 0.05
Normal 4
B
2
40 0.067
0.140 0.05
Normal 5
A
1
B
1
20 0.118
0.190 0.05
Normal 6
A
1
B
2
20 0.094
0.190 0.05
Normal 7
A
2
B
1
20 0.121
0.190 0.05
Normal 8
A
2
B
2
20 0.079
0.190 0.05
Normal
2. Homogeneity Test
Homogeneity test was conducted to know whether or not the data are homogenous. The data can be said as homogenous if
χ o
2
is lower than χ
t
2
0.05. Result of the data analysis can be seen in table 4.10.
Table 4.10. Summary of Homogeneity test
SAMPLE df
1df si²
log si² dflog si²
1 19
0,05 38,32632
1,5835 30,09
2 19
0,05 62,47105
1,7957 34,12
3 19
0,05 33,41842
1,5240 28,96
4 19
0,05 105,6289
2,0238 38,45
∑ 76
0,21 131,61
Based on the result of homogeneity test above, it can be seen that the score of
χ
o 2
is 6.24. From the table of Chi-Square distribution with the perpustakaan.uns.ac.id
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significance level α
= 0.05, the score of χ
t 2
0.95 3 is 7.815. Because χ
o 2
6.24 is lower than χ
t 2
0.95 7.815 or χ
o 2
χ
t 2
6.247.815, it can be concluded that the data are homogenous.
D. Testing Hypothesis