getdocdef8. 412KB Jun 04 2011 12:05:05 AM

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El e c t ro n ic

Jo ur

n a l o

f P

r o

b a b il i t y

Vol. 14 (2009), Paper no. 72, pages 2091–2129. Journal URL

http://www.math.washington.edu/~ejpecp/

Intermittency on catalysts:

three-dimensional simple symmetric exclusion

Jürgen Gärtner

Institut für Mathematik

Technische Universität Berlin

Straße des 17. Juni 136

D-10623 Berlin, Germany

[email protected]

Frank den Hollander

Mathematical Institute

Leiden University, P.O. Box 9512

2300 RA Leiden, The Netherlands

and EURANDOM, P.O. Box 513

5600 MB Eindhoven, The Netherlands

[email protected]

Grégory Maillard

CMI-LATP

Université de Provence

39 rue F. Joliot-Curie

F-13453 Marseille Cedex 13, France

[email protected]

Abstract

We continue our study of intermittency for the parabolic Anderson model∂u/∂t=κu+ξuin a space-time random mediumξ, whereκis a positive diffusion constant,∆is the lattice Laplacian onZd,d1, andξis a simple symmetric exclusion process onZdin Bernoulli equilibrium. This model describes the evolution of areactant uunder the influence of acatalystξ.

In[3]we investigated the behavior of the annealed Lyapunov exponents, i.e., the exponential growth rates as t → ∞ of the successive moments of the solution u. This led to an almostThe research of this paper was partially supported by the DFG Research Group 718 “Analysis and Stochastics in

Complex Physical Systems”, the DFG-NWO Bilateral Research Group “Mathematical Models from Physics and Biology”, and the ANR-project MEMEMO


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complete picture of intermittency as a function of d and κ. In the present paper we finish our study by focussing on the asymptotics of the Lyaponov exponents asκ→ ∞in thecritical dimensiond=3, which was left open in[3]and which is the most challenging. We show that, interestingly, this asymptotics is characterized not only by aGreenterm, as in d4, but also by apolaronterm. The presence of the latter implies intermittency ofallorders above a finite threshold forκ.

Key words: Parabolic Anderson model, catalytic random medium, exclusion process, graphical representation, Lyapunov exponents, intermittency, large deviation.

AMS 2000 Subject Classification:Primary 60H25, 82C44; Secondary: 60F10, 35B40. Submitted to EJP on December 17, 2008, final version accepted August 17, 2009.


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1

Introduction and main result

1.1

Model

In this paper we consider theparabolic Anderson model(PAM) onZd,d1,

  

∂u

∂t =κu+ξu onZ

d×[0,),

u(·, 0) =1 onZd,

(1.1)

whereκis a positive diffusion constant,∆is the lattice Laplacian acting onuas

u(x,t) = X

y∈Zd

kyxk=1

[u(y,t)u(x,t)] (1.2)

(k · kis the Euclidian norm), and

ξ= (ξt)t≥0, ξt={ξt(x): x∈Zd}, (1.3)

is a space-time random field that drives the evolution. If ξis given by an infinite particle system dynamics, then the solution uof the PAM may be interpreted as the concentration of a diffusing

reactantunder the influence of acatalystperforming such a dynamics.

In Gärtner, den Hollander and Maillard [3]we studied the PAM for ξSymmetric Exclusion (SE), and developed an almost complete qualitative picture. In the present paper we finish our study by focussing on the limiting behavior asκ→ ∞in thecriticaldimensiond=3, which was left open in

[3]and which is the most challenging. We restrict toSimple Symmetric Exclusion(SSE), i.e.,(ξt)t≥0 is the Markov dynamics on Ω = {0, 1}Z3

(0 = vacancy, 1 = particle) with generator L acting on cylinder functions f:ΩRas

(L f)(η) = 1

6 X

{a,b}

h

f ηa,bf(η)i, η∈Ω, (1.4)

where the sum is taken over all unoriented nearest-neighbor bonds{a,b} ofZ3, andηa,b denotes

the configuration obtained fromηby interchanging the states ataand b:

ηa,b(a) =η(b), ηa,b(b) =η(a), ηa,b(x) =η(x)forx∈ {/ a,b}. (1.5) (See Liggett[7], Chapter VIII.) LetPηandEη denote probability and expectation forξgivenξ0=

η∈Ω. Letξ0be drawn according to the Bernoulli product measureνρonΩwith densityρ∈(0, 1).

The probability measuresνρ,ρ∈(0, 1), are the only extremal equilibria of the SSE dynamics. (See

Liggett[7], Chapter VIII, Theorem 1.44.) We writePν

ρ= R

νρ()PηandEνρ= R

νρ()Eη.

1.2

Lyapunov exponents

ForpN, define thep-thannealed Lyapunov exponentof the PAM by

λp(κ,ρ) =tlim→∞

1

ptlogEνρ([u(0,t)]


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We are interested in the asymptotic behavior ofλp(κ,ρ)asκ→ ∞for fixedρand p. To this end,

letGdenote the value at 0 of theGreen functionof simple random walk onZ3with jump rate 1 (i.e., the Markov process with generator 16∆), and letP3be the value of thepolaron variational problem

P3= sup

fH1(R3)

kfk2=1

−∆R3

1/2

f2

2 2−

R3f

2

2

, (1.7)

whereR3 and∆R3are thecontinuousgradient and Laplacian,k · k2 is theL2(R3)-norm,H1(R3) =

{fL2(R3): R3fL2(R3)}, and

−∆R3

−1/2

f2

2 2=

Z

R3

d x f2(x)

Z

R3

d y f2(y) 1

4πkx yk. (1.8)

(See Donsker and Varadhan[1]for background on howP3 arises in the context of a self-attracting Brownian motion referred to as the polaron model. See also Gärtner and den Hollander[2], Section 1.5.)

We are now ready to formulate our main result (which was already announced in Gärtner, den Hollander and Maillard[4]).

Theorem 1.1. Let d=3∈(0, 1)and pN. Then

lim

κ→∞κ[λp(κ,ρ)−ρ] =

1

6ρ(1−ρ)G+ [6ρ(1−ρ)p] 2

P3. (1.9)

Note that the expression in the r.h.s. of (1.9) is the sum of aGreenterm and apolaronterm. The existence, continuity, monotonicity and convexity ofκ7→λp(κ,ρ)were proved in[3]for alld ≥1

for all exclusion processes with an irreducible and symmetric random walk transition kernel. It was further proved thatλp(κ,ρ) =1 when the random walk is recurrent and ρ < λp(κ,ρ)< 1 when

the random walk is transient. Moreover, it was shown that for simple random walk in d 4 the asymptotics as κ→ ∞ ofλp(κ,ρ) is similar to (1.9), but without the polaron term. In fact, the

subtlety ind =3 is caused by the appearance of this extra term which, as we will see in Section 5, is related to the large deviation behavior of the occupation time measure of a rescaled random walk that lies deeply hidden in the problem. For the heuristics behind Theorem 1.1 we refer the reader to[3], Section 1.5.

1.3

Intermittency

The presence of the polaron term in Theorem 1.1 implies that, for eachρ ∈(0, 1), there exists a κ0(ρ)>0 such that thestrictinequality

λp(κ,ρ)> λp−1(κ,ρ) ∀κ > κ0(ρ) (1.10)

holds for p = 2 and, consequently, for all p ≥ 2 by the convexity of p 7→ pλp(κ,ρ). This means

that all moments of the solution u are intermittent for κ > κ0(ρ), i.e., for large t the random field u(·,t) develops sparse high spatial peaks dominating the moments in such a way that each moment is dominated by its own collection of peaks (see Gärtner and König[5], Section 1.3, and den Hollander[6], Chapter 8, for more explanation).


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In[3]it was shown that for alld3 the PAM is intermittent forsmallκ. We conjecture that ind=3 it is in fact intermittent forallκ. Unfortunately, our analysis does not allow us to treat intermediate values ofκ(see the figure).

0 ρ 1

r r r p=3 p=2 p=1

?

κ λp(κ)

Qualitative picture ofκ7→λp(κ)forp=1, 2, 3.

The formulation of Theorem 1.1 coincides with the corresponding result in Gärtner and den Hollan-der[2], where the random potential ξis given by independent simple random walks in a Poisson equilibrium in the so-called weakly catalytic regime. However, as we already pointed out in[3], the approach in[2]cannot be adapted to the exclusion process, since it relies on an explicit Feynman-Kac representation for the moments that is available only in the case ofindependentparticle motion. We must therefore proceed in a totally different way. Only at the end of Section 5 will we be able to use some of the ideas in[2].

1.4

Outline

Each of Sections 2–5 is devoted to a major step in the proof of Theorem 1.1 forp=1. The extension top2 will be indicated in Section 6.

In Section 2 we start with the Feynman-Kac representation for the first moment of the solutionu, which involves a random walk sampling the exclusion process. After rescaling time, we transform the representation w.r.t. the old measure to a representation w.r.t. a new measure via an appropriate absolutely continuous transformation. This allows us to separate the parts responsible for, respec-tively, the Green term and the polaron term in the r.h.s. of (1.9). Since the Green term has already been handled in[3], we need only concentrate on the polaron term. In Section 3 we show that, in the limit asκ→ ∞, the new measure may be replaced by the old measure. The resulting represen-tation is used in Section 4 to prove thelower boundfor the polaron term. This is done analytically with the help of a Rayleigh-Ritz formula. In Section 5, which is technical and takes up almost half of the paper, we prove the correspondingupper bound. This is done by freezing and defreezing the exclusion process over long time intervals, allowing us to approximate the representation in terms of the occupation time measures of the random walk over these time intervals. After applying spectral estimates and using a large deviation principle for these occupation time measures, we arrive at the polaron variational formula.


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2

Separation of the Green term and the polaron term

In Section 2.1 we formulate the Feynman-Kac representation for the first moment of uand show how to split this into two parts after an appropriate change of measure. In Section 2.2 we formulate two propositions for the asymptotics of these two parts, which lead to, respectively, the Green term and the polaron term in (1.9). These two propositions will be proved in Sections 3–5. In Section 2.3 we state and prove three elementary lemmas that will be needed along the way.

2.1

Key objects

The solutionuof the PAM in (1.1) admits the Feynman-Kac representation

u(x,t) =EXx ‚

exp –Z t

0

dsξts Xκs

™Œ

, (2.1)

where X is simple random walk on Z3 with step rate 6 (i.e., with generator ) and PX

x and E

X x

denote probability and expectation with respect to X given X0 = x. Sinceξis reversible w.r.t.νρ,

we may reverse time in (2.1) to obtain

Eν

ρ u(0,t)

=Eν

ρ,0

exp Z t

0

dsξs Xκs

, (2.2)

whereEν

ρ,0is expectation w.r.t.Pνρ,0=Pνρ⊗P

X

0. As in[2]and[3], we rescale time and write

eρ(t/κ)Eν

ρ u(0,t/κ)

=Eν

ρ,0

exp 1

κ Z t

0

dsφ(Zs)

(2.3) with

φ(η,x) =η(x)ρ (2.4)

and

Zt= ξt/κ,Xt

. (2.5)

From (2.3) it is obvious that (1.9) in Theorem 1.1 (forp=1) reduces to lim

κ→∞κ

2λ(κ) = 1

6ρ(1−ρ)G+ [6ρ(1−ρ)] 2

P3, (2.6)

where

λ∗(κ) = lim

t→∞

1

t logEνρ,0 ‚

exp –

1 κ

Z t

0

dsφ(Zs)

™Œ

. (2.7)

Here and in the rest of the paper we suppress the dependence on ρ ∈(0, 1) from the notation. UnderPη,x =PηPX

x,(Zt)t≥0 is a Markov process with state spaceΩ×Z3and generator

A = 1


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(acting on the Banach space of bounded continuous functions onΩ×Z3, equipped with the

supre-mum norm). Let(St)t0denote the semigroup generated byA.

Our aim is to make an absolutely continuous transformation of the measurePη,x with the help of

an exponential martingale, in such a way that, under the new measurePnew

η,x , (Zt)t≥0 is a Markov process with generatorAnewof the form

Anewf =e−1κψA

e1κψf

e−1κψAe

1

κψ

f. (2.9)

This transformation leads to an interaction between the exclusion process part and the random walk part of(Zt)t≥0, controlled byψ:Ω×Z3→R. As explained in[3], Section 4.2, it will be expedient to chooseψas

ψ=

Z T

0

ds S

(2.10) withT a large constant (suppressed from the notation), implying that

− Aψ=φ− STφ. (2.11)

It was shown in[3], Lemma 4.3.1, that

Nt=exp

– 1 κ

ψ(Zt)−ψ(Z0)

Z t

0

ds

e−1κψAe

1

κψ

(Zs)

™

(2.12) is an exponentialPη,x-martingale for all(η,x)×Z3. Moreover, if we definePnew

η,x in such a way

that

Pnew

η,x(A) =Eη,x Nt11A

(2.13) for all eventsAin theσ-algebra generated by(Zs)s[0,t], then underPnew

η,x indeed(Zs)s≥0is a Markov process with generatorAnew. Using (2.11–2.13) andEnew

νρ,0= R

νρ()E

new

η,0, it then follows that the expectation in (2.7) can be written in the form

Eν

ρ,0 ‚

exp –

1 κ

Z t

0

dsφ(Zs)

™Œ

=Enew

νρ,0

exp 1

κ

ψ(Z0)−ψ(Zt)

+

Z t

0

ds

eκ1ψAe

1

κψ

− A

1

κψ

(Zs)

+ 1

κ Z t

0

ds STφ(Zs)

.

(2.14)

The first term in the exponent in the r.h.s. of (2.14) stays bounded ast → ∞and can therefore be discarded when computingλ∗(κ)via (2.7). We will see later that the second term and the third term lead to the Green term and the polaron term in (2.6), respectively. These terms may be separated from each other with the help of Hölder’s inequality, as stated in Proposition 2.1 below.

2.2

Key propositions

Proposition 2.1. For anyκ >0,

λ∗(κ) ≤

I

q

1(κ) +I

r


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with

I1q(κ) = 1

qtlim→∞

1

t logE

new

νρ,0

exp

q

Z t

0

dse−1κψAe

1

κψ

− A

1 κψ

(Zs)

,

I2r(κ) = 1

r tlim→∞

1

t logE

new

νρ,0

exp r

κ Z t

0

ds S

(Zs)

,

(2.16)

where 1/q+1/r = 1, with q >0, r > 1in the first inequality and q <0, 0< r < 1in the second inequality.

Proof. See[3], Proposition 4.4.1. The existence and finiteness of the limits in (2.16) follow from Lemma 3.1 below.

By choosingr arbitrarily close to 1, we see that the proof of our main statement in (2.6) reduces to the following two propositions, where we abbreviate

lim sup

t,κ,T→∞

=lim sup

T→∞

lim sup

κ→∞

lim sup

t→∞

and lim

t,κ,T→∞=Tlim→∞κlim→∞tlim→∞. (2.17)

In the next proposition we writeψT instead ofψto indicate the dependence on the parameterT.

Proposition 2.2. For anyα∈R,

lim sup

t,κ,T→∞

κ2

t logE

new

νρ,0 ‚

exp –

α Z t

0

dse−1κψTAe1κψT

− A1

κψT

(Zs)

™Œ

α

6ρ(1−ρ)G. (2.18) Proposition 2.3. For anyα >0,

lim

t,κ,T→∞

κ2

t logE

new

νρ,0

exp

α κ

Z t

0

ds S

(Zs)

= [6α2ρ(1−ρ)]2P3. (2.19)

These propositions will be proved in Sections 3–5.

2.3

Preparatory lemmas

This section contains three elementary lemmas that will be used frequently in Sections 3–5.

Let p(t1)(x,y) and pt(x,y) = p(t3)(x,y) be the transition kernels of simple random walk in d =1 andd=3, respectively, with step rate 1.

Lemma 2.4. There exists C>0such that, for all t 0and x,y,eZ3 withkek=1,

p(t1)(x,y) C (1+t)12

, pt(x,y)≤

C

(1+t)32

, pt(x+e,y)−pt(x,y)

C

(1+t)2. (2.20)

Proof. Standard.


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From the graphical representation for SSE (Liggett[7], Chapter VIII, Theorem 1.1) it is immediate that

Eη ξt(x)= X y∈Zd

pt(x,y)η(y). (2.21)

Recalling (2.4–2.5) and (2.10), we therefore have

S(η,x) =Eη,x

φ(Zs)=Eη‚ X

y∈Z3

p6s(x,y)ξs/κ(y)−ρ

Œ

= X

z∈Z3

p6s1[κ](x,z)

η(z)ρ

(2.22)

and

ψ(η,x) =

Z T

0

ds X

z∈Z3

p6s1[κ](x,z)

η(z)ρ, (2.23)

where we abbreviate

1[κ] =1+ 1

6κ. (2.24)

Lemma 2.5. For allκ,T>0∈Ω, a,bZ3 withkabk=1and xZ3,

|ψ(η,b)ψ(η,a)| ≤2CpT for T1, (2.25)

ψ ηa,b,xψ(η,x)

≤2G, (2.26)

X

{a,b}

ψ ηa,b,xψ(η,x)

2

≤ 16G, (2.27)

where C >0is the same constant as in Lemma 2.4, and G is the value at0of the Green function of simple random walk onZ3.

Proof. For a proof of (2.26–2.27), see[3], Lemma 4.5.1. To prove (2.25), we may without loss of generality consider b=a+e1 withe1= (1, 0, 0). Then, by (2.23), we have

|ψ(η,b)ψ(η,a)| ≤

Z T

0

ds X

z∈Z3

p6s1[κ](z+e1)−p6s1[κ](z)

=

Z T

0

ds X

z∈Z3

p6(1s1)[κ](z1+e1)−p

(1)

6s1[κ](z1)

p(61s)1[κ](z2)p

(1)

6s1[κ](z3)

=

Z T

0

ds X

z1∈Z

p(61s)1[κ](z1+e1)−p

(1)

6s1[κ](z1)

=2 Z T

0

ds p(61s)1[κ](0)2CpT.

(2.28)


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LetG be the Green operator acting on functionsV:Z3[0,)as

GV(x) = X y∈Z3

G(xy)V(y), xZ3, (2.29)

withG(z) =R0d t pt(z). Letk · kdenote the supremum norm. Lemma 2.6. For all V:Z3[0,)and x Z3,

EXx

exp Z∞

0

d t V(Xt)

1− kGVk

1

≤exp ‚

kGVk

1− kGVk∞

Œ

, (2.30)

provided that

kGVk∞<1. (2.31)

Proof. See[2], Lemma 8.1.

3

Reduction to the original measure

In this section we show that the expectations in Propositions 2.2–2.3 w.r.t. the new measurePnew

νρ,0 are asymptotically the same as the expectations w.r.t. the old measurePν

ρ,0. In Section 3.1 we state a Rayleigh-Ritz formula from which we draw the desired comparison. In Section 3.2 we state the analogues of Propositions 2.2–2.3 whose proof will be the subject of Sections 4–5.

3.1

Rayleigh-Ritz formula

Recall the definition ofψin (2.10). Letmdenote the counting measure onZ3. It is easily checked

that bothµρ=νρmandµnewρ given by

newρ =e2κψdµρ (3.1)

are reversible invariant measures of the Markov processes with generators A defined in (2.8), respectively,Anewdefined in (2.9). In particular,A andAneware self-adjoint operators in L2(µρ)

andL2(µnew

ρ ). LetD(A)andD(Anew)denote their domains.

Lemma 3.1. For all bounded measurable V:Ω×Z3R,

lim

t→∞

1

t logE

new

νρ,0

exp Z t

0

ds V(Zs)

= sup

F∈D(Anew)

kFkL2(µnew

ρ )=1

ZZ

Ω×Z3

newρ V F2+FAnewF

. (3.2)

The same is true whenEnew

νρ,0 new

ρ ,A

neware replaced byE

νρ,0,µρ,A, respectively.

Proof. The limit in the l.h.s. of (3.2) coincides with the upper boundary of the spectrum of the operatorAnew+V onL2(µnewρ ), which may be represented by the Rayleigh-Ritz formula. The latter coincides with the expression in the r.h.s. of (3.2). The details are similar to[3], Section 2.2.


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Lemma 3.1 can be used to express the limits ast→ ∞in Propositions 2.2–2.3 as variational expres-sions involving the new measure. Lemma 3.2 below says that, for largeκ, these variational expres-sions are close to the corresponding variational expresexpres-sions for the old measure. Using Lemma 3.1 for the original measure, we may therefore arrive at the corresponding limit for the old measure. For later use, in the statement of Lemma 3.2 we do not assume thatψis given by (2.10). Instead, we only suppose thatη7→ψ(η)is bounded and measurable and that there is a constantK>0 such that for allη∈Ω, a,b∈Z3withkabk=1 andx ∈Z3,

|ψ(η,b)ψ(η,a)| ≤K and

ψ ηa,b,xψ(η,x)

K, (3.3)

but retain thatAnewandµnewρ are given by (2.9) and (3.1), respectively. Lemma 3.2. Assume(3.3). Then, for all bounded measurable V:Ω×Z3R,

sup

F∈D(Anew)

kFkL2(µnew

ρ )

=1

ZZ

Ω×Z3 newρ

V F2+FAnewF

≤ ≥ e

Kκ sup

F∈D(A)

kFkL2(µρ)=1

ZZ

Ω×Z3 dµρ

e±KκV F2+FAF

,

(3.4)

where±means+in the first inequality andin the second inequality, andmeans the reverse. Proof. Combining (1.2), (1.4) and (2.8–2.9), we have for all(η,x)×Z3 and allF∈ D(Anew),

V F2+FAnewF(η,x) =V(η,x)F2(η,x) + 1

6κ X

{a,b}

F(η,x)1[ψ(η

a,b,x)ψ(η,x)]h

F(ηa,b,x)F(η,x)i

+ X

y:kyxk=1

F(η,x)e1κ[ψ(η,y)−ψ(η,x)]F(η,y)−F(η,x).

(3.5)

Therefore, taking into account (2.9), (3.1) and the exchangeability ofνρ, we find that

ZZ

Ω×Z3

newρ V F2+FAnewF=

ZZ

Ω×Z3

newρ (η,x)

‚

V(η,x)F2(η,x)

− 1

12κ X

{a,b} e1κ[ψ(η

a,b,x)ψ(η,x)]h

F(ηa,b,x)F(η,x)i2

−1

2 X

y:kyxk=1

e1κ[ψ(η,y)−ψ(η,x)]F(η,y)−F(η,x)2 Œ

. (3.6)


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LetFe=eψ/κF. Then, by (3.1) and (3.3),

(3.6) ≤

ZZ

Ω×Z3

newρ (η,x)

‚

V(η,x)F2(η,x)

e

K

κ 12κ

X

{a,b}

h

F(ηa,b,x)F(η,x)i2 eK

κ 2

X

y:kyxk=1

F(η,y)F(η,x)2

Œ

=

ZZ

Ω×Z3

dµρ(η,x)

‚

V(η,x)Fe2(η,x)

e

Kκ

12κ X

{a,b}

h e

F(ηa,b,x)Fe(η,x)i2 eKκ

2

X

y:kyxk=1 h

e

F(η,y)Fe(η,x)i2

Œ

= e ZZ

Ω×Z3 dµρ

e± VFe2+eFAFe

.

(3.7)

Taking further into account that eF2L2

ρ)=kFk 2

L2new

ρ )

, (3.8)

and that eF∈ D(A)if and only ifF ∈ D(Anew), we get the claim.

3.2

Reduced key propositions

At this point we may combine the assertions in Lemmas 3.1–3.2 for the potentials

V =αeκ1ψAe

1

κψ

− A

1

κψ

(3.9) and

V = α

κ S

(3.10) withψgiven by (2.10). Because of (2.25–2.26), the constant K in (3.3) may be chosen to be the maximum of 2G and 2CpT, resulting inK/κ→0 asκ→ ∞. Moreover, from (2.27) and a Taylor expansion of the r.h.s. of (3.9) we see that the potential in (3.9) is bounded for each κ and T, and the same is obviously true for the potential in (3.10) because of (2.4). In this way, using a moment inequality to replace the factor e±K/κα by a slightly larger, respectively, smaller factorα′ independent of T and κ, we see that the limits in Propositions 2.2–2.3 do not change when we replaceEnew

νρ,0by

Eν

ρ,0. Hence it will be enough to prove the following two propositions. Proposition 3.3. For allα∈R,

lim sup

t,κ,T→∞

κ2

t logEνρ,0 ‚

exp –

α Z t

0

ds

e−1κψAe

1

κψ

− A1

κψ

(Zs)

™Œ

α

6ρ(1−ρ)G. (3.11) Proposition 3.4. For allα >0,

lim

t,κ,T→∞

κ2

t logEνρ,0

exp

α κ

Z t

0

ds S

(Zs)

=6α2ρ(1−ρ)2P3. (3.12) Proposition 3.3 has already been proven in[3], Proposition 4.4.2. Sections 4–5 are dedicated to the proof of the lower, respectively, upper bound in Proposition 3.4.


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4

Proof of Proposition 3.4: lower bound

In this section we derive the lower bound in Proposition 3.4. We fixα,κ,T>0 and use Lemma 3.1, to obtain

lim

t→∞

1

t logEνρ,0

exp α

κ Z t

0

ds STφ(Zs)

= sup

F∈D(A)

kFkL2(µρ)=1

ZZ

Ω×Z3 dµρ

α κ S

F2+FAF. (4.1) In Section 4.1 we choose a test function. In Section 4.2 we compute and estimate the resulting expression. In Section 4.3 we take the limitκ,T → ∞and show that this gives the desired lower bound.

4.1

Choice of test function

To get the desired lower bound, we use test functionsF of the form

F(η,x) =F1(η)F2(x). (4.2)

Before specifyingF1 andF2, we introduce some further notation. In addition to the counting mea-sure m on Z3, consider the discrete Lebesgue measure mκ on Z3

κ = κ−1Z3 giving weightκ−3 to

each site inZ3

κ. Letl2(Z3)andl2(Z3κ)denote the correspondingl2-spaces. Let∆κdenote the lattice

Laplacian onZ3

κdefined by

κf(x) =κ2 X

y∈Z3κ

kyxk=κ−1

f(y)f(x). (4.3)

Choose f ∈ Cc∞(R 3)with

kfkL2(R3)=1 arbitrarily, whereCc∞(R3) is the set of infinitely

differen-tiable functions onR3 with compact support. Define

(x) =κ−3/2f κ−1x

, x ∈Z3, (4.4)

and note that

kkl2(Z3)=kfkl2(Z3

κ)→1 asκ→ ∞. (4.5)

ForF2choose

F2=kfκk−1

l2(Z3). (4.6)

To choose F1, introduce the function e

φ(η) = α

kk2l2(Z3)

X

x∈Z3

S

(η,x)fκ2(x). (4.7)

GivenK>0, abbreviate

S=6T1[κ] and U =621[κ] (4.8)

(recall (2.24)). Forκ >pT/K, defineψe:ΩRby

e

ψ=

Z US

0


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where(Tt)t0 is the semigroup generated by the operator Lin (1.4). Note that the construction of e

ψfromφein (4.9) is similar to the construction ofψfromφin (2.10). In particular,

e=φe− TUSφ.e (4.10)

Combining the probabilistic representations of the semigroups (St)t0 (generated byA in (2.8)) and(Tt)t0 (generated byLin (1.4)) with the graphical representation formulas (2.21–2.22), and using (4.4–4.5), we find that

e

φ(η) = α

kfk2

l2(Z3

κ) Z

Z3

κ

(d x)f2(x)

X

z∈Z3

pS(κx,z)[η(z)−ρ] (4.11)

and

e

ψ(η) = X z∈Z3

h(z)[η(z)ρ] (4.12)

with

h(z) = α

kfk2

l2(Z3

κ) Z

Z3

κ

mκ(d x)f2(x)

Z U S

ds ps(κx,z). (4.13)

Using the second inequality in (2.20), we have 0h(z) p

T, z

Z3. (4.14)

Now chooseF1 as

F1= e−L21

ρ)e

e

ψ. (4.15)

For the above choice of F1 and F2, we have kF1kL2

ρ) = kF2kl2(Z3) = 1 and, consequently,

kFkL2

ρ) = 1. With F1, F2 and φe as above, and A as in (2.8), after scaling space byκ we ar-rive at the following lemma.

Lemma 4.1. For F as in(4.2),(4.6)and(4.15), allα,T,K>0andκ >pT/K,

κ2 ZZ

Ω×Z3 dµρ

α κ S

F2+FAF

= 1

kfk2

l2(Z3

κ) Z

Z3

κ

d mκfκf +

κ

kek2

L2

ρ) Z

dνρ

e

φe2ψe+eLeψe,

(4.16)

whereφeandψeare as in(4.7)and(4.9).

4.2

Computation of the r.h.s. of (4.16)

Clearly, asκ→ ∞the first summand in the r.h.s. of (4.16) converges to Z

R3

d x f(x) ∆f(x) =R3f

2

L2(R3). (4.17)


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Lemma 4.2. For allα >0and0< ε <K,

lim inf

κ,T→∞

κ

kek2

L2

ρ) Z

dνρ

e

φe2ψe+eLeψe

≥6α2ρ(1ρ)

Z

R3

d x f2(x)

Z

R3

d y f2(y)

‚ Z 6K

6ε

d t p(tG)(x,y)

Z 12K

6K

d t p(tG)(x,y)

Œ ,

(4.18)

where

p(tG)(x,y) = (4πt)−3/2exp[−kxyk2/4t] (4.19)

denotes the Gaussian transition kernel associated with∆R3, the continuous Laplacian onR3. Proof. Using the probability measure

ρnew=e−L22

ρ)e 2ψedν

ρ (4.20)

in combination with (4.10), we may write the term under the lim inf in (4.18) in the form κ

Z

ρneweψeLeψee+TUSφe. (4.21)

This expression can be handled by making a Taylor expansion of the L-terms and showing that the

TUS-term is nonnegative. Indeed, by the definition of Lin (1.4), we have

eψeLeψe−e(η) = 1

6 X

{a,b}

e[ψ(ηe a,b)−ψ(η)]e −1−hψ ηe a,bψe(η)i. (4.22)

Recalling the expressions forψein (4.12–4.13) and using (4.14), we get fora,bZ3withkabk=

1,

eψ ηa,bψe(η)=|h(a)h(b)| |η(b)η(a)| ≤ p

T. (4.23)

Hence, a Taylor expansion of the exponent in the r.h.s. of (4.22) gives Z

ρneweψeLeψee≥ e

Cα/pT

12 Z

ρnewX

{a,b}

h e

ψ ηa,bψe(η)i2. (4.24) Using (4.12), we obtain

Z

νρnew()X {a,b}

h e

ψ ηa,bψe(η)i2= X {a,b}

h(a)h(b)2

Z

νρnew()η(b)η(a)2. (4.25) Using (4.20), we have (after cancellation of factors not depending onaor b)

Z

νρnew()η(b)η(a)2=

Z

νρ()e2χa,b(η)

η(b)η(a)2

Z

νρ()e2χa,b(η)


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with

χa,b(η) =h(a)η(a) +h(b)η(b). (4.27)

Using (4.14), we obtain that Z

νρnew()η(b)η(a)2e−4Cα/pT

Z

νρ()

η(b)η(a)2=e−4Cα/pT2ρ(1ρ). (4.28) On the other hand, by (4.13),

X

{a,b}

h(a)h(b)2= α

2

kfk4

l2(Z3

κ) Z U

S

d t

Z U S

ds

Z

Z3

κ

mκ(d x)f2(x)

Z

Z3

κ

mκ(d y)f2(y)

× X

{a,b}

pt(κx,a)−pt(κx,b)

ps(κy,a)−ps(κy,b)

(4.29)

with X

{a,b}

pt(κx,a)pt(κx,b)ps(κy,a)ps(κy,b)=X a∈Z3

pt(κx,a)∆ps(κx,a)

=6X

a∈Z3

pt(κx,a)

∂sps(κy,a)

,

(4.30)

where∆acts on the first spatial variable ofps(·,·)and∆ps=6(∂ps/∂s). Therefore,

(4.29) =6 Z U

S

d t

Z

Z3

κ

(d x)f2(x)

Z

Z3

κ

(d y)f2(y)

X

a∈Z3

pt(κx,a)pS(κy,a)pU(κy,a)

=6 Z

Z3

κ

(d x)f2(x)

Z

Z3

κ

(d y)f2(y)

‚ Z S+U

2S

d t pt(κx,κy)

Z 2U U+S

d t pt(κx,κy)

Œ . (4.31) Combining (4.24–4.25) and (4.28–4.29) and (4.31), we arrive at

Z

ρneweψeLeψe−e≥ e

−5Cα/pTα2

kfk4l2(Z3

κ)

ρ(1−ρ)

Z

Z3

κ

(d x)f2(x)

Z

Z3

κ

(d y)f2(y)

×

‚ Z S+U

2S

d t pt(κx,κy)

Z 2U U+S

d t pt(κx,κy)

Œ .

(4.32)

After replacing 2Sin the first integral by 6εκ21[κ], using a Gaussian approximation of the transition kernelpt(x,y)and recalling the definitions ofSandU in (4.8), we get that, for anyε >0,

lim inf

κ,T→∞κ

Z

ρnew

eψeLeψee

≥6α2ρ(1−ρ)

Z

R3

d x f2(x)

Z

R3

d y f2(y)

‚ Z 6K

6ε

d t p(tG)(x,y)

Z 12K

6K

d t p(tG)(x,y)

Œ .


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At this point it only remains to check that theTUS-term in (4.21) is nonnegative. By (4.11) and the probabilistic representation of the semigroup(Tt)t0, we have

Z

ρnewTUe=

α

kfk2

l2(Z3

κ) Z

Z3

κ

(d x)f2(x)

X

z∈Z3

pU(κx,z)

Z

νρnew()[η(z)ρ] (4.34) and, by (4.20),

Z

νρnew()[η(z)ρ] =ρ+ ρe

2h(z)

ρe2h(z)+1ρ =−ρ+

ρ

1(1ρ) 1e−2h(z)

≥ −ρ+ρh1+ (1−ρ)1−e−2h(z)

i

=ρ(1−ρ)1−e−2h(z)

,

(4.35)

which proves the claim.

4.3

Proof of the lower bound in Proposition 3.4

We finish by using Lemma 4.2 to prove the lower bound in Proposition 3.4.

Proof. Combining (4.16–4.18), we get lim inf

κ,T→∞κ

2 ZZ

Ω×Z3 dµρ

α κ S

F2FAF

≥6α2ρ(1ρ)

Z

R3

d x f2(x)

Z

R3

d y f2(y)

‚ Z 6K

6ε

d t p(tG)(x,y)

Z 12K

6K

d t p(tG)(x,y)

Œ

−∇R3f

2

L2(R3).

(4.36)

Lettingε ↓0, K → ∞, replacing f(x) byγ3/2f(γx)withγ= 2ρ(1ρ), taking the supremum over all f Cc∞(R3)such thatkfkL2(R3)=1 and recalling (4.1), we arrive at

lim inf

t,κ,T→∞

κ2

t logEνρ,0

exp

α κ

Z t

0

ds S

(Zs)

≥6α2ρ(1−ρ)2P3, (4.37) which is the desired inequality.

5

Proof of Proposition 3.4: upper bound

In this section we prove the upper bound in Proposition 3.4. The proof is long and technical. In Sections 5.1 we “freeze” and “defreeze” the exclusion dynamics on long time intervals. This allows us to approximate the relevant functionals of the random walk in terms of its occupation time measures on those intervals. In Section 5.2 we use a spectral bound to reduce the study of the long-time asymptotics for the resulting dependent potentials to the investigation of time-independent potentials. In Section 5.3 we make a cut-off for small times, showing that these times are negligible in the limit as κ → ∞, perform a space-time scaling and compactification of the underlying random walk, and apply a large deviation principle for the occupation time measures, culminating in the appearance of the variational expression for the polaron termP3.


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5.1

Freezing, defreezing and reduction to two key lemmas

5.1.1 Freezing

We begin by deriving a preliminary upper bound for the expectation in Proposition 3.4 given by

Eν

ρ,0

exp Z t

0

ds V(Zs)

(5.1) with

V(η,x) =α

κ S

(η,x) = α

κ X

y∈Z3

p6T1[κ](x,y)(η(y)−ρ), (5.2)

where, as before, T is a large constant. To this end, we divide the time interval[0,t]into⌊t/Rκ

intervals of length

Rκ=2 (5.3)

withR a large constant, and “freeze” the exclusion dynamics(ξt/κ)t≥0 on each of these intervals. As will become clear later on, this procedure allows us to express the dependence of (5.1) on the random walkX in terms of objects that are close to integrals over occupation time measures ofX on time intervals of length. We will see that the resulting expression can be estimated from above by

“defreezing” the exclusion dynamics. We will subsequently see that, after we have taken the limits

t → ∞, κ→ ∞and T → ∞, the resulting estimate can be handled by applying a large deviation principle for the space-time rescaled occupation time measures in the limit asR → ∞. The latter will lead us to the polaron term.

Ignoring the negligible final time interval[t/Rκ,t], using Hölder’s inequality withp,q>1 and

1/p+1/q=1, and inserting (5.2), we see that (5.1) may be estimated from above as

Eν

ρ,0

exp

Z⌊t/RκRκ

0

ds V(Zs)

=Eν

ρ,0 ‚

exp –

α κ

tX/Rκ

k=1 Z kRκ

(k−1)Rκ

ds X

y∈Z3

p6T1[κ](Xs,y) ξs/κ(y)−ρ

™Œ

≤ER(1,α)q(t)

1/q

ER(2,α)p(t)

1/p

(5.4)

with

ER(1,α)(t) =E (1)

R,α(κ,T;t) =Eνρ,0 ‚

exp –

α κ

tX/Rκk=1

Z kRκ (k−1)

ds X

y∈Z3

p6T1[κ](Xs,y)ξs

κ(y)

p6T1[κ]+s−(k−1) κ

(Xs,y)ξ(k−1) κ

(y)

™Œ (5.5)

and

ER(2,α)(t) =E (2)

R,α(κ,T;t) =Eν

ρ,0 ‚

exp –

α κ

tX/Rκk=1

Z kRκ (k−1)Rκ

ds X

y∈Z3

p6T1[κ]+s−(k−1)Rκ

κ

(Xs,y)

ξ(k−1)Rκ

κ


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Therefore, by choosing pclose to 1, the proof of the upper bound in Proposition 3.4 reduces to the proof of the following two lemmas.

Lemma 5.1. For all R,α >0,

lim sup

t,κ,T→∞

κ2

t logE (1)

R,α(κ,T;t)≤0. (5.7)

Lemma 5.2. For allα >0,

lim sup

R→∞

lim sup

t,κ,T→∞

κ2

t logE (2)

R,α(κ,T;t)≤

6α2ρ(1ρ)2P3. (5.8)

Lemma 5.1 will be proved in Section 5.1.2, Lemma 5.2 in Sections 5.1.3–5.3.3.

5.1.2 Proof of Lemma 5.1

Proof. Fix R,α > 0 arbitrarily. Given a pathX, an initial configurationη ∈Ω and k N, we first

derive an upper bound for

Eη

‚ exp

– α κ

Z 0

ds X

y∈Z3

p6T1[κ]

Xs(k,κ),y

ξs

κ(y)−p6T1[κ]+

s

κ

Xs(k,κ),y

η(y)

™Œ

, (5.9)

where

Xs(k,κ)=X(k−1)+s. (5.10)

To this end, we use the independent random walk approximationξeofξ(cf.[3], Proposition 1.2.1), to obtain

(5.9) Y yAη

EY0 ‚

exp –

α κ

Z 0

ds

p6T1[κ]

Xs(k,κ),y+Ys

κ

p6T1[κ]+s

κ

Xs(k,κ),y

™Œ

, (5.11)

whereY is simple random walk onZ3 with jump rate 1 (i.e., with generator 1

6∆), E

Y

0 is expectation w.r.t.Y starting from 0, and

={x∈Z3:η(x) =1}. (5.12)

Observe that the expectation w.r.t.Y of the expression in the exponent is zero. Therefore, a Taylor expansion of the exponential function yields the bound

EY0 ‚

exp –

α κ

Z 0

ds

p6T1[κ]

Xs(k,κ),y+Ys

κ

p6T1[κ]+κs

Xs(k,κ),y

™Œ

≤1+ ∞

X

n=2

n

Y

l=1 ‚

α κ

Z Rκ sl−1

dsl X

yl∈Z3 pslsl−1

κ

(yl1,yl)

×

p6T1[κ]Xs(k,κ) l ,y+yl

+p6T1[κ]+sl

κ

Xs(k,κ) l ,y

Œ ,


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wheres0 =0, y0 =0, and the product has to be understood in a noncommutative way. Using the Chapman-Kolmogorov equation and the inequalitypt(z)≤pt(0),z∈Z3, we find that

Z

sl−1

dsl X

yl∈Z3 pslsl−1

κ

(yl1,yl)

p6T1[κ]

Xs(k,κ) l ,y+ yl

+p6T1[κ]+sl

κ

Xs(k,κ) l ,y

Œ

≤2 Z ∞

0

ds pT+κs(0) =2κGT(0)

(5.14)

with

GT(0) =

Z

T

ds ps(0) (5.15)

the cut-off Green function of simple random walk at 0 at time T. Substituting this into the above bound for l = n,n−1,· · ·, 3, computing the resulting geometric series, and using the inequality 1+x ex, we obtain

(5.13)exp –

CTα2

κ2 2 Y

l=1 Z Rκ

sl−1

dsl X

yl∈Z3 pslsl−1

κ

(yl1,yl)

×

p6T1[κ]

Xs(k,κ) l ,y+yl

+p6T1[κ]+sl

κ

Xs(k,κ) l ,y

™ (5.16)

with

CT = 1

1−2αGT(0), (5.17)

provided that 2αGT(0) < 1, which is true for T large enough. Note that CT → 1 as T → ∞.

Substituting (5.16) into (5.11), we find that

(5.9)exp –

CTα2

κ2 X

y∈Z3

2 Y

l=1 Z

sl−1

dsl X

yl∈Z3 pslsl−1

κ

(yl1,yl)

×

p6T1[κ]

Xs(k,κ) l ,y+yl

+p6T1[κ]+sl

κ

Xs(k,κ) l ,y

™ .

(5.18)

Using once more the Chapman-Kolmogorov equation and pt(x,y) = pt(xy), we may compute

the sums in the exponent, to arrive at

(5.9)exp –

CTα2 κ2

Z Rκ

0

ds1 Z Rκ

s1 ds2

p12T1[κ]+s2s1

κ

Xs(k,κ) 2 −X

(k,κ) s1

+3p12T1[κ]+s2+s1

κ

Xs(k,κ) 2 −X

(k,κ) s1

™ .

(5.19)

Note that this bound does not depend on the initial configuration η and depends on the process

X only via its increments on the time interval [(k−1),kRκ]. By (5.10), the increments over

the time intervals labelled k=1, 2,· · ·,t/Rκ⌋ are independent and identically distributed. Using

Eν

ρ,0 = R


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(ξt/κ)t≥0 at times, 2, · · ·, (⌊t/Rκ⌋ −1) to the expectation in the r.h.s. of (5.5), insert the

bound (5.19) and afterwards use that(Xt)t≥0 has independent increments, to arrive at logER(1,α)(t) t

log EX0 ‚

exp –

CTα2

κ2 Z

0

ds1

Z

s1 ds2

p12T1[κ]+s2−s1

κ

Xs2Xs1

+3p12T1[κ]+s2+s1

κ

Xs 2−Xs1

™Œ

.

(5.20)

Hence, recalling the definition ofRκ in (5.3), we obtain lim sup

t→∞

κ2

t logE (1) R,α(t)

R1log EX0 ‚

exp –

CTα2R Rκ

Z 0

ds1

Z

s1 ds2

p12T1[κ]+s2s1

κ

Xs2Xs1

+3p12T1[κ]+s2+s1

κ

Xs2Xs1

™Œ .

(5.21)

Let

b

Xt=Xt+Yt, (5.22)

and let EX0b =EX0EY0 be the expectation w.r.t.Xbstarting at 0. Observe that

pt+s(z) =EY0pt z+Ys. (5.23)

We next apply Jensen’s inequality w.r.t. the first integral in the r.h.s. of (5.21), substitutes2=s1+s, take into account thatX has independent increments, and afterwards apply Jensen’s inequality w.r.t. EY0, to arrive at the following upper bound for the expectation in (5.21):

EX0 ‚

exp –

CTα2R

Z Rκ

0

ds1

Z Rκ s1

ds2

p12T1[κ]+s2−s1

κ

Xs2Xs1

+3p12T1[κ]+s2+s1

κ

Xs 2−Xs1

™

≤ 1

Z Rκ

0

ds1E0X ‚

exp –

CTα2R

Z ∞

0

dsEY0

p12T1[κ]Xs+Ys

κ

+3p12T1[κ]+2s1

κ

Xs+Ys

κ ™Œ

≤ 1

Z Rκ

0

ds1E0Xb ‚

exp –

CTα2R

Z ∞

0

dsp12T1[κ] Xbs+3p12T1[κ]+2s1

κ b

Xs

™Œ .

(5.24)

Applying Lemma 2.6, we can bound the last expression from above by exp

–

4CTα2RGb 2T(0)

14CTα2RGb 2T(0)

™

, (5.25)

where Gb2T(0) is the cut-off at time 2T of the Green function Gb at 0 for Xb (which has generator

1[κ]∆). Since Gb2T(0) 1

6G12T(0)asκ→ ∞, and since the latter converges to zero asT → ∞, a combination of the above estimates with (5.21) gives the claim.


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whereM1(Q)is the space of probability measures onQ, andHper1 (Q)denotes the space of functions inH1(Q)with periodic boundary conditions. By[2], Lemma 7.4, we have

lim sup Q↑R3

P3(Q)(θ;ε,K)≤ P3(θ;ε,K) (5.119)

with

P3(θ;ε,K)

= sup

fH1(R3)

kfk2=1

6θ2α2ρ(1ρ) Z

R3

d x f2(x) Z

R3

d y f2(y) Z K

ε

d r p(rG)(x,y)R3f 2

L2(R3)

≤ sup

fH1(R3)

kfk2=1

6θ2α2ρ(1ρ) Z

R3

d x f2(x) Z

R3

d y f2(y) Z ∞

0

d r p(rG)(x,y)R3f 2

L2(R3)

=6θ2α2ρ(1ρ)2P3.

(5.120)

Combining (5.116) and (5.120), and lettingθ↓1, we arrive at the claim of Lemma 5.13.

This, after a long struggle by the authors and considerable patience on the side of the reader, com-pletes the proof of the upper bound in Proposition 3.4.

Remark. The reader might be surprised that the expression in the l.h.s. of (5.98) does not only vanish in the limit asε↓0 but vanishes forallε >0 sufficiently small. This fact is closely related to the observation that

P3 π3

=0 whereas P3() =P3>0 (5.121) with

P3(ε) = sup

fH1(R3)

kfk2=1 – Z

R3

d x f2(x) Z

R3

d y f2(y) Z ε

0

d r p(rG)(xy)R3f 2

2

™

. (5.122)

Indeed, given a potential V 0 with kGR3Vk < 1/2, where GR3 denotes the Green operator associated with∆R3, the method used in the proof of Lemma 5.12 leads to

lim R→∞

1

Rlog E

β

0

‚ exp

– 1

R

Z R

0 ds

Z R

0

des V(βesβs) ™Œ

=0. (5.123)

On the other hand, the large deviation principle for the occupation time measures ofβ shows that this limit coincides with

sup

fH1(R3)

kfk2=1 – Z

R3

d x f2(x) Z

R3

d y f2(y)V(xy)R3f 2

2

™

. (5.124)

But, for 0< ε < π3the potential

(x) =

Z ε

0

d r p(rG)(x) (5.125)


(2)

6

Higher moments

In this last section we explain how to extend the proof of Theorem 1.1 to higher momentsp 2. Sections 6.1–6.3 parallel Sections 2.1, 3.2, 4 and 5.

6.1

Two key propositions

Our starting point is the Feynman-Kac representation for thep-th moment, Eν

ρ

u(0,t)p=E(p)

νρ;0

‚ exp

– Z t

0 ds

p X

j=1

ξs Xκjs

™Œ

, (6.1)

where X1,· · ·,Xp are independent simple random walks on Z3 starting at 0 and E(νp)

ρ;x denotes

expectation w.r.t.P(νp)

ρ;x =Pνρ⊗P

X1

x1⊗ · · · ⊗P Xp

xp, x = (x1,· · ·,xp)∈(

Z3)p.

The arguments in Sections 2 and 3 easily extend to this more general case by replacing Z, A, (St)t0, φ andψ by their p-dimensional analogues Z(p), A(p), (St(p))t0, φ(p) and ψ(p). To be precise, consider the Markov process

Zt(p)= ξt/κ,X1t,· · ·,X p t

onΩ×(Z3)p (6.2)

with generator

A(p)= 1

κL+

p X

j=1

j, (6.3)

where the lattice Laplacian∆j acts on the j-th spatial variable. Denote by(St(p))t0 the associated semigroup. We define

φ(p)(η;x1,· · ·,xp) = p X

j=1

φ(η,xj) = p X

j=1

(η(xj)ρ) (6.4) and

ψ(p)= Z T

0

dsSs(p)φ(p). (6.5)

Then

ψ(p)(η;x1,· · ·,xp) = p X

j=1

ψ(η,xj). (6.6)

In this way the proof of Theorem 1.1 for p2 reduces to the proof of the following extension of Propositions 3.3 and 3.4.

Proposition 6.1. For all pNandαR, lim sup

t,κ,T→∞

κ2

ptlogE (p)

νρ;0

‚ exp

–

α

Z t

0

dseκ1ψ

(p)

A(p)1ψ

(p)

− A(p)1

κψ

(p) Z(p)

s ™Œ ≤ α

6ρ(1−ρ)G.


(3)

Proposition 6.2. For all pNandα >0, lim

t,κ,T→∞

κ2 ptlogE

(p)

νρ;0

‚ exp

–

α κ

Z t

0

dsST(p)φ(p) Zs(p)

™Œ

=6α2ρ(1ρ)p2P3. (6.8)

Proposition 6.1 has already been proven for allpNin[3], Proposition 4.4.2 and Section 4.8.

6.2

Lower bound in Proposition 6.2

We use the following analogue of the variational representation (4.1) lim

t→∞ 1

t logE (p)

νρ;0

‚ exp

–

α κ

Z t

0 ds

ST(p)φ

(p) Z(p)

s ™Œ

= sup

F(p)∈D(A(p)) kF(p)k

L2(µρp)=1

ZZ

Ω×(Z3)p

ρp

α κ

ST(p)φ

(p) F(p)2

+F(p)A(p)F(p)

. (6.9)

To obtain the appropriate lower bound, we use test functionsF(p)of the form

F(p)(η;x1,· · ·,xp) =F1(η)F2(x1)· · ·F2(xp), (6.10) whereF1,F2 andF =F(1)are the same as in (4.15), (4.6) and (4.2), respectively. One easily checks

that

κ2

p

ZZ

Ω×(Z3)p

ρp

α

κ

ST(p)φ

(p) F(p)2

+F(p)A(p)F(p)

=()

2 p2

ZZ

Ω×Z3

dµρ

p

α

STφF2+F

1

pκL+ ∆

F

.

(6.11)

But this is 1/p2times the expression in Lemma 4.1 withαandκreplaced byand, respectively. Hence, we may use the lower bounds for this expression in Section 4 to arrive at the lower bound in Proposition 6.2.

6.3

Upper bound in Proposition 6.2

1. Freezing and defreezing can be done in the same way as in Section 5.1, but withV(η,x)in (5.2) replaced by

V(p)(η,x) =α

κ

X y∈Z3

‚Xp j=1

p6T1[κ] xj,y

Œ

η(y)ρ. (6.12)

This leads to the analogues of Lemmas 5.1 and 5.3 along the lines of Sections 5.1.2 and 5.1.4. 2. Considering

Vk(,pu)(η) = 1

Z (k+1)Rκ kRκ

ds X

y∈Z3 ‚Xp

j=1

p6T1[κ]+su

κ X

j s,y

Œ


(4)

and

ER(4,,αp)(t) =Eνρ;0

‚ exp

–

α κ

tX/Rκk=1

Z kRκ (k−1)Rκ

du Vk(,pu) ξu/κ

™Œ

(6.14) instead of (5.34–5.35), the proof reduces to the following analogue of Lemma 5.4.

Lemma 6.3. For eachα >0,

lim sup R→∞

lim sup t,κ,T→∞

κ2 ptlogE

(4,p)

R,α (t)≤

6α2ρ(1ρ)p2P3. (6.15) 3. The proof of Lemma 6.3 follows the lines of Sections 5.2–5.3. The spectral bound is essentially the same as in Section 5.2.1. In Lemma 5.6 we have to replaceVk,ubyVk(,pu)andλk,uby

λ(kp,u)= lim t→∞

1

t logEνρ

‚ exp – α κ Z t 0

ds Vk(,pu) ξs

™Œ

. (6.16)

Subsequently, we replaceVk,ubyVk(,pu)in (5.45), to obtain functionsφb(p),ψb(p)replacing (5.45–5.46), and

Ξ(rp)(x) = 1

Z (k+1)

kRκ ds

p X

j=1

p6T1[κ]+su+r

κ X

j s,x

(6.17) replacing (5.50). Then, in the analogue of Lemma 5.7, instead of (5.58) we get the bound

K(p)

k,u

1≤e

2Cα/T 2α

2

κ2R2

κ

Z (k+1)Rκ kRκ

ds

Z (k+1)Rκ kRκ

des

Z M

0 d r

p X i,j=1

p12T1[κ]+s+es−2u+2r

κ Xj

e

sX i s

(6.18) along the line of Section 5.2.3. Similarly, the proof of the analogue of Lemma 5.8 follows the argument in Section 5.2.4, leading to a reduction of Lemma 6.3 to the analogue of Lemma 5.11, as in Section 5.2.5.

4. To make the small-time cut-off, instead of (5.95) we consider ER(8,,αp)(κ)

=EX0 ‚

exp –

Θα,T,ρ

κ2R2

κ

Z Rκ

0 ds

Z Rκ s

des

Z 0

Rκ

du Z m 0 d r p X i,j=1

p12T1[κ]+s+es−2u+2r

κ Xj

e

sX i s

™Œ

. (6.19) Using the Chapman-Kolmogorov equation, we see that

Z Rκ

0 ds

Z Rκ

0 des

p X i,j=1

p12T1[κ]+s+es−2u+2r

κ

XesjXsi

= X

z∈Z3 ‚Xp

i=1

Z Rκ

0

ds p6T1[κ]+su+r

κ X

i s,z

Œ2

pX

z∈Z3 p X i=1

‚ Z 0

ds p6T1[κ]+su+r

κ X

i s,z

Œ2

=p

p X

i=1

Z 0

ds

Z 0

des p12T1[κ]+s+es−2u+2r

κ

XesiXsi.


(5)

Substituting this into the r.h.s. of (6.19) and applying Hölder’s inequality for the p exponential factors, we reduce the problem to the consideration of a single random walk and can proceed as in Section 5.3, leading to the analogues of Lemmas 5.12–5.13.

5. The proof of the analogue of Lemma 5.12 runs along the line of Section 5.3.2. To prove the analogue of Lemma 5.13, instead of (5.96) we consider

ER(9,,αp)(κ)

=EX0 ‚

exp –

Θα,T,ρ κ2R2

κ

Z 0

ds

Z

s

des

Z 0

Rκ

du

Z M m

d r

p X i,j=1

p12T1[κ]+s+es−2u+2r

κ

XesjXsi

™Œ

. (6.21) As in Section 5.3.3, this leads to

lim sup

κ,T,R→∞ 1

pRlogE (9,p)

R,α (κ)

≤ 1

p νi∈Msup1(Q) 1≤ip

–

6θ2α2ρ(1ρ) p X i,j=1

Z Q

νi(d x) Z

Q

νj(d y) Z K

ε

d r p(rG,Q)(x,y) p X i=1

SQ(νi)

™ (6.22)

instead of (5.116–5.117). Now we can proceed similarly as in[2], Lemma 7.3. Consider the Fourier transformsνbi of the measuresνi∈ M1(Q)defined by

b

νj(k) = Z

Q

ei(2π/l(Q))k·xνj(d x), k∈Z3,j=1,· · ·,p. (6.23) The transition kernel p(G,Q)admits the Fourier representation

p(rG,Q)(x) = 1

l(Q)3

X k∈Z3

e−(2π/l(Q))2|k|2rei(2π/l(Q))k·x, (x,t)Q×(0,). (6.24) Therefore we may write

Z Q

νi(d x) Z

Q

νj(d y)pr(G,Q)(x,y) = 1

l(Q)3

X k∈Z3

e−(2π/l(Q))2|k|2bi(k)νbj(k). (6.25) Using that

Re

b

νi(k)νbj(k)

≤12bνi(k) 2

+1 2 bνj(k)

2

, (6.26)

we obtain Z Q

νi(d x) Z

Q

νj(d y)p(rG,Q)(x,y) ≤ 1

2 Z

Q

νi(d x) Z

Q

νi(d y)pr(G,Q)(x,y) + 1 2 Z

Q

νj(d x) Z

Q

νj(d y)pr(G,Q)(x,y).

(6.27)

Therefore the term inside the square brackets in the r.h.s. of (6.22) does not exceed p

X i=1

–

6θ2α2ρ(1ρ)p

Z Q

νi(d x) Z

Q

νi(d y) Z K

ε

d r p(rG,Q)(x,y)SQ(νi) ™


(6)

and we arrive at

lim sup

κ,T,R→∞

p RlogE

(9,p)

R,α (κ)≤ P

(Q,p)

3 (θ;ε,K) (6.29)

with

P3(Q,p)(θ;ε,K) = sup

ν∈M1(Q) –

6θ2α2ρ(1ρ)p

Z Q

ν(d x) Z

Q

ν(d y) Z K

ε

d r p(rG,Q)(x,y)SQ(ν) ™

, (6.30) which is the analogue of (5.116–5.117) forp2. The rest of the proof can be easily obtained from the analogues of (5.119–5.120).

References

[1] M.D. Donsker and S.R.S. Varadhan, Asymptotics for the polaron, Comm. Pure Appl. Math. 36 (1983) 505–528.

[2] J. Gärtner and F. den Hollander, Intermittency in a catalytic random medium, Ann. Probab. 34 (2006) 2219–2287.

[3] J. Gärtner, F. den Hollander and G. Maillard, Intermittency on catalysts: symmetric exclusion, Electronic J. Probab. 12 (2007) 516–573.

[4] J. Gärtner, F. den Hollander and G. Maillard, Intermittency on catalysts, in: Trends in Stochastic Analysis (eds. J. Blath, P. Mörters and M. Scheutzow), London Mathematical Society Lecture Note Series 353, Cambridge University Press, Cambridge, 2009, pp. 235–248.

[5] J. Gärtner and W. König, The parabolic Anderson model, in: Interacting Stochastic Systems

(eds. J.-D. Deuschel and A. Greven), Springer, Berlin, 2005, pp. 153–179.

[6] F. den Hollander, Large Deviations, Fields Institute Monographs 14, American Mathematical Society, Providence, RI, 2000.

[7] T.M. Liggett, Interacting Particle Systems, Grundlehren der Mathematischen Wissenschaften 276, Springer, New York, 1985.


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